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New Question

10 months ago

0 Follower 2 Views

Shiksha Ask & Answer
Dr. Uma SinhaPrincipal

Scholar-Level 17

Hi. For B.E. / B.Tech admission at Sanaka Educational Trust's Group of Institutions:

Candidate seeking admission in the Institute through WBJEE or JEE MAIN examination with valid rank and required marks in '10+2' level or equivalent examination from any recognised Board / University are eligible to apply.

In all B.Tech courses, 90% students of approved intake capacity will be admitted on the basis of merit position secured by the candidate in the Joint Entrance Examination of the State (WBJEE).

Students on the basis of merit position in JEE MAIN may also be admitted up to 10% of total intake. 

Thanks 

New Question

10 months ago

0 Follower 3 Views

Shiksha Ask & Answer
Dr. Uma SinhaPrincipal

Scholar-Level 17

Hi.The required documents during the B.E. / B.Tech application process at Sanaka Educational Trust's Group of Institution for Admission are:

Original/Downloaded Admit and Rank Card (WBJEE / JEE MAIN / JEJET) with Photocopy (02 sets).

Provisional Seat Allotment Letter.

Original Admit Card & Mark Sheet of Class Xth&XIIth/Diploma/B.Sc. with Photocopy (02 sets).

06 Copies of Stamp Size Colour Photographs.

Original Medical, Eye & Blood Group Certificate.

Original Migration/School Leaving Certificate.

Original Certificate of SC / ST / OBC / PWD (if applicable) with Photocopy (02 sets).

Aadhar Card Photocopy (02 sets).

Signed copy of Online Undertakin

...more

New Question

10 months ago

0 Follower 14 Views

S
Sk Aryan

Beginner-Level 5

The Sanaka Educationql Trust Group of instituitions (SETGOI) generally uses a merit based admission process, often involving entrance exams like JEE Main or WBJEE, followed by counselling for some programs. The process typically includes online registration, application form filling, choice filling, entrance exam participation, document participation, document verification, and seat allocation.

New Question

10 months ago

0 Follower 7 Views

Shiksha Ask & Answer
Dr. Uma SinhaPrincipal

Scholar-Level 17

Hi.During the Sanaka Educational Trust's Group of Institutions BE/BTech WBJEE cutoff 2024, the last-round closing ranks ranged between 9781 and 1337992 for the General AI category students.

Bachelor of Architecture (B.Arch.) was the most sought-after BE/BTech specialisation with a closing rank of 9781 for the general AI quota.

On the contrary the least competitive specialisations for admission in 2024 were B.Tech. in Computer Science & Engineering (Artificial intelligence & Machine Learning) and B.Tech. in Computer Science and Engineering with closing cutoff ranks of 1337992 and 1262924, respectively.

Thanks 

New Question

10 months ago

0 Follower 8 Views

Shiksha Ask & Answer
Dr. Uma SinhaPrincipal

Scholar-Level 17

Hi.During the Sanaka Educational Trust's Group of Institutions BE/BTech cutoff 2024, the last-round closing ranks ranged between 9781 and 1337992 for the General AI category students.

For more detail cutoff mark  information for Sanaka Educational Trust's Group of Institutions you can see below link 

https://www.shiksha.com/college/sanaka-educational-trust-s-group-of-institutions-durgapur-47251/cutoff

Thanks 

New Question

10 months ago

0 Follower 13 Views

S
Sk Aryan

Beginner-Level 5

To join the Sanaka Educational Trust Group of Instituitions, candidates typically need to apply through a merit based process, depending on the program. For B.Tech and B.Pharm, entrance exams like WBJEE or JEE Main are often required, followed by counselling. Other programs like M.Tech, MBA, BBA, and MCA may have their own entrance exams or rely on scores from national level exams.

New Question

10 months ago

0 Follower 3 Views

Shiksha Ask & Answer
Dr. Uma SinhaPrincipal

Scholar-Level 17

Hi.Candidate seeking admission in the Institute through WBJEE or JEE MAIN examination with valid rank and required marks in ‘10+2’ level or equivalent examination from any recognised Board / University.

 In B.Tech and B. Pharm. courses, 90% students of approved intake capacity will be admitted on the basis of merit position secured by the candidate in the Joint Entrance Examination of the State. Students on the basis of merit position in JEE MAIN may also be admitted up to 10% of total intake.

 Candidate should satisfy the stipulated standard of physical fitness with good mental and physical health.

Thanks 

New Question

10 months ago

0 Follower 5 Views

Shiksha Ask & Answer
Dr. Uma SinhaPrincipal

Scholar-Level 17

Hi. No, you can't get direct admission to Sanaka Educational Trust's Group of Institutions.

Candidate seeking admission in the Institute through WBJEE or JEE MAIN examination with valid rank and required marks in ‘10+2’ level or equivalent examination from any recognised Board / University are eligible to apply. In all B.Tech courses, 90% students of approved intake capacity will be admitted on the basis of merit position secured by the candidate in the Joint Entrance Examination of the State (WBJEE). Students on the basis of merit position in JEE MAIN may also be admitted up to 10% of total intake.

Thanks 

New Question

10 months ago

0 Follower 6 Views

S
Sk Aryan

Beginner-Level 5

To gain admission to Sanaka Educational Trust Group of Instituitions (SETGOI), you will generally need to qualify in a relevant entrance exam, such as WBJEE or JEE Main for B.Tech programs. You will also need to meet the eligibility criteria for the specific course yoy are applying for the specific course you are applying for, which usually includes passing your 10+2 or equivalent exam with the required percentage.

New Question

10 months ago

0 Follower 8 Views

Shiksha Ask & Answer
Dr. Uma SinhaPrincipal

Scholar-Level 17

Yes, admission to Sanaka Educational Trust's Group of Institutions is currently open. The college offers only BTech, BArch, BPharma, and diploma courses. Admission to the BTech, BArch, and After 10th diploma courses is mainly based on the rank obtained in WBJEE/ JEE Main exam, NATA exam, and JEXPO counseling, respectively. To be eligible for the course, candidates need to have a minimum of 45% in previous qualifications in a relevant stream from any recognised institute. Although registrations for these exams are closed now, the applications for admission under the management quota are currently open. Admission to the BPharma course is

...more

New Question

10 months ago

0 Follower 3 Views

Shiksha Ask & Answer
Dr. Uma SinhaPrincipal

Scholar-Level 17

Hi.Sanaka Educational Trust's Group of Institutions gsupports the eligible candidates for availing the Scholarships: .

OASIS Scholarship

Aikyashree Scholarship

Swami Vivekananda Scholarship

NSP National Scholarship Portal (For all State students)

E-Kalyan Scholarship (For Jharkhand State students)

MAKAUT Students Welfare Scholarship

Education Loan:

Bank Loan assistance for the students.

West Bengal Student Credit Card Scheme

Thanks 

New Question

10 months ago

0 Follower 3 Views

P
Pallavi Pathak

Contributor-Level 10

NCERT Exemplar problems are designed by the subject matter experts. It helps in deepening conceptual understanding and improving the application skills of the students. Preparing the NCERT exemplar Chapter 2 helps students in mastering complex topics like capacitors, electric potential, and energy storage which are important for the board exam preparations and entrance tests like JEE and NEET.

New Question

10 months ago

0 Follower 3 Views

J
Jaya Madavi

Contributor-Level 10

Yes, the Shri Vishwakarma Skill University is accepting applications for the BBA programmes for the academic year 2025. Interested candidates can check the official website to apply offline or online for the course specialisation of their choice. Further, it is also necessary for candidates to submit the application on or before the stipulated application deadline.

New Question

10 months ago

0 Follower 6 Views

E
Esha Tiwari

Contributor-Level 9

Along with the global reputation for innovation and research, Simon Fraser University is renowned for its academic courses. Some of the popular courses include Accounting and Finance, Arts and Design, Biological Sciences, Communication and Media Studies, Global MBA, Mathematics, Medicine, and more. The Simon Fraser University popular courses, along with the QS Ranking 2025 are listed below:

Ranked by

2025

World University

319

Accounting and Finance

301

Art and Design

– / –

Biological Sciences

401

Communication and Media Studies

151

Engineering and Technology

501

Global MBA

201

Law and Legal Studies

301

Mathematics

301

Medicine

451

Physics and Astronomy

501

Politics

251

Sociology

301

New Question

10 months ago

0 Follower 1 View

S
Shailja Rawat

Contributor-Level 10

BSc in Physics is one of the top specialisations offered by Takshashila University under its BSc program. Completing this course opens the door to various career prospects in the healthcare sector. The below table shows various job titles that students can pursue after graduating with a BSc in Physics and their respective salaries:

Job Profile

Average Salary

Software Developer

INR 3 LPA - INR 5 LPA

Data Scientist

INR 6 LPA - INR 7 LPA

Cybersecurity Analyst

INR 5 LPA - INR 6 LPA

Web Developer

INR 3.5 LPA - INR 4 LPA

Data Engineer

INR 4.5 LPA

New Question

10 months ago

0 Follower 3 Views

R
Rachit Singh

Contributor-Level 6

Conjunctions are used to connect words, phrases, or clauses, allowing us to express more complex and meaningful thoughts in a simpler and smooth way.

New Question

10 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

As ivory ball is more elastic than wet clay ball. So ivory ball tries to regain its original shape quickly, hence more energy and momentum transferred to ivory than clay ball. So ivory ball rises high

New Question

10 months ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Length of steel cable l=9.1m

Radius r= 5mm= 5 × 10 - 3

Tension in the cable F =800N

Young’s modulus of steel Y= 2 × 10 11 N m 2

So ? l = F π r 2 × l Y = 800 3.14 × ( 5 × 10 - 3 ) - 2 × 9.1 2 × 10 11 = 4.64 × 10 - 4 m

New Question

10 months ago

0 Follower 4 Views

New Question

10 months ago

0 Follower 2 Views

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