Ask & Answer: India's Largest Education Community

The important documents to be submitted during DSIPST application process are as follows:

• Class 10 & 12 marksheet
• Aadhar card or any photo identity
• Admit card of PET (Pharmacy Entrance Test)
• Passport-size photo

This is a  Short Answer Type Questions as classified in NCERT Exemplar

Explanation-air molecules in the atmosphere are attracted vertically downward by the gravitational force of the earth just like an apple falling from the tree. Air molecules move randomly due to their thermal velocity and hence resultant motion of air molecules move randomly in vertical downward direction. But in case of apple it is heavier than air so it fall downwards only.

Anil Neerukonda Institute of Technology and Sciences has not released its overall placement rate. However it has released the placement highlights for its 2025 placement season. Check out the table below to know more:

Yes, the BSc course at Nazareth College of Arts and Science incorporates several practical components such as project work, summer internships, and industrial training. These hands-on experiences complement the theoretical curriculum, allowing students to apply their knowledge in real-world settings. This approach helps prepare NCAS students for professional challenges and enhances their employability after graduation.

Yes, top-performing students receive medals, certificates, trophies, and even cash prizes. National-level toppers can win scholarships and recognition. Some schools also reward their best-performing students. These awards motivate students to do better in academics. Participation certificates are also given to all students.

Yes. Both domestic and international debit/credit cards are accepted for payment. One should make sure that their payment card is enabled for international transactions and has sufficient balance for the registration fee of INR 16,900.

To apply for admission to Dr. Sudhir Chandra Sur Institute of Pharmaceutical Science and Technology, students need to meet the basic eligibility requirements and apply online on the college's official website. Check below the basic steps of application:

1. Visit the official website at (dsipst.ac.in/).
2. Fill the appeared form with basic information around personal and academic details.
3. Complete and submit the form by paying an application fee.

Some of the basic documentation for Humboldt Uni is stated below:

• Transcript of secondary education stating the academic record 
• Transcript of records/degree certificate/diploma incase one has priorly studied at another university
• English translated official documents
• Proof of Germa language proficiency- Level C1
• CV
• Copy of passport or identity card
• Certificate from the Academic Evaluation Centre (APS)

The Indian Olympiad exams are conducted online & offline and consist of objective type questions. The total duration of the exams is 45 minutes to 1 hour. 

A total of 50 recruiters took part during Anil Neerukonda Institute of Technology and Sciences placements some of them are:

This is a Long Type Questions as classified in NCERT Exemplar

Explanation- r_p= radius of perihelion =2R

R_a = radius of aphelion =6R

So r_a=a(1+e)=6R

And r_p= a(1-e)=2R

Solving above eqns

 We get e = ½

By conservation of angular momentum angular momentum at perigee= angular momentum at apogee

So mv_pr_p=mv_ar_a

V_a/v_p=1/3

Where m is mass of satellite .

By conservation of energy , energy at perigee =energy at apogee

$\frac{1}{2}m{v}_p^2$ - $\frac{GMm}{r_p}=\frac{1}{2}m{v}_a^2-\frac{GMm}{r_a}$

So $v_p^2\left(1-\frac{1}{9}\right)=-2GM\left(\frac{1}{r_a}-\frac{1}{r_p}\right)=2GM\left(\frac{1}{r_p}-\frac{1}{r_a}\right)$

V_p= $\frac{{\left[\frac{2GM}{R}\right(\frac{1}{2}-\frac{1}{6}\left)\right]}^{1/2}}{[{{[1-\frac{v_a}{v_p}]}^2]}^{1/2}}$ = $\sqrt[]{\frac{3}{4}\frac{GM}{R}}=6.85km/s$

V_p=6.85km/s , v_a=2.28km/s

So orbital velocity v_c= $\sqrt[]{\frac{GM}{r}}$

R=6R ,v_c= 3.23km/s

Hence to transfer to a circular orbit at apogee , we have to boost the velocity by 3.23-2.28=0.95km/s.

Candidates should first check the availability of test centres in their location. If test centres are not operational or you are more comfortable testing from home, you may opt for the TOEFL iBT Home Edition. Candidates juts have to make sure they have the system that meets ETS TOEFL requirements and your environment is secure for test monitoring.

Students can decide if the BSc programme at Nazareth College of Arts and Science aligns with their goals by evaluating key aspects like available specialisations, course curriculum, faculty expertise, internship and placement opportunities, fee structure, and feedback from current or past students. Comparing these factors with other colleges will help in making an informed choice.

The Indian Talent Olympiad exams are held the following subjects.

• Science
• Mathematics
• English
• General Knowledge
• Drawing
• Essay
• Computer

The students will require to choose one or more subjects as per their interest. Each ITO paper has a different pattern. 

The highest packages recorded during Anil Neerukonda Institute of Technology and Sciences placements was INR 12 LPA. CCheck out the table below to know more:

Yes, students who attained an age of 17 years on or before Dec 31 of the year of admission to the course can apply for admission to a two year long DPharm programme at the college.

The placement rate for  Anil Neerukonda Institute of Technology and Sciences is not released yet. However, students can refer to the placement highlights provided in the table below:

The primary eligibility requirement for admission to the BBA course at Shikshapeeth College of Management and Technology is that candidates must complete their Class 12 from any stream with decent scores. Moreover, for the selection process, the college releases the merit list of selected candidates on the basis of applicants' scores in Class 12/ higher senior secondary, followed by group discussion/ personal interview. The college also accepts entrance-based admission. 

Explanation- mass of earth M = 6 $\times {10}^{24}kg$

Radius of the earth , R = 6400km= 6.4 $\times {10}^{6}m$

T=24h= 24 $\times 60\times 60=86400s$

G = 6.67 $\times$ 10^-11Nm²/kg²

(a) Time period T = $2\pi \sqrt[]{\frac{{\left(R+h\right)}^3}{GM}}$

$T^2$ = $4\pi$ ^{2 $\frac{{(R+h)}^3}{GM}$}

$R+h$ = ( $\frac{T^{2}GM}{4{\pi }^2}$ )^1/3

$h=$  ( $\frac{T^{2}GM}{4{\pi }^2}$ )^1/3-R

So after solving we get h = 3.59 $\times {10}^{7}m$

(b) If satellite is at height h from the earth’s surface

Cos $\theta$ = $\frac{R}{R+h}=\frac{1}{\left(1+\frac{h}{R}\right)}=\frac{1}{1+5.61}=\frac{1}{6.61}=0.1513$ = cos81⁰18’

$\theta$ = 81⁰18’

$2\theta$ =2(81⁰18’)= 162⁰36’

If n number of satellite needed to cover entire the earth then

So n = 360⁰/2 $\theta$ = 2.31

So minimum 3 satellite are required to cover entire earth.