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The precise writing helps in providing text briefly and as clear as possible. The important ideas are provided and the irrelevant information are cut down. Precise text provides the central ideas and saves time from reading long texts. 

The following scholarships are available to candidates in the Nehru College of Management: 

Merit Scholarship,
PG Scholarship for NGI Alumnus
Sibling Scholarship
Vigyan Scholarship
Single Parent Scholarship
Frontline Warriors Scholarship
MHRD Scholarship
Ex-service man Scholarship
Candidates may apply to any of the above mentioned scholarships based on their eligibility. 

$\begin{array}{l}\frac{se{c}^{2}x}{{(1-tanx)}^2}\\ Put\left(1-tanx\right)=t\\ \Rightarrow se{c}^{2}xdx=dt\\ I=\int \frac{se{c}^{2}x}{{(1-tanx)}^2}dx=\int \frac{-dt}{t^2}\\ =-\int t^{-2}dt\\ =\frac{1}{t}+C\\ =\frac{1}{1-tanx}+C\end{array}$

Precis writing is summarizing the text in brief by keeping the key details intact without any personal ideas or jargons. While writing precisely, certain rules must be followed to cover only important aspect in the text.

$\begin{array}{l}\frac{2cosx-3sinx}{2(3cosx+2sinx)}\\ Put3cosx+2sinx=t\\ \Rightarrow \left(-3sinx+2cosx\right)dx=dt\\ =\int \frac{2cosx-3sinx}{6cosx+4sinx}dx\\ =\int \frac{dt}{2t}=\frac{1}{2}{\displaystyle \int \frac{1}{t}}dt\\ =\frac{1}{2}log\left|t\right|+C\\ =\frac{1}{2}log|3cosx+2sinx|+C.\end{array}$

Hall ticket for the Andhra Pradesh 12th board exam is issued by the  Board of Intermediate Education, Andhra Pradesh (BIEAP) to which you are enrolled via your school. So your school cannot deny you the admit card even if you have failed to pass in their pre-boards exam. If they still goes on to deny you the hall ticket you can straight away write it to BIEAP asking them to issue your Andhra Pradesh Inter hall ticket in duplicate as your school has failed to give you.

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Scholarships are available from Nehru College of Management to students enrolled in two-year PGDM programs, including various specialisations. Nehru College of Management offers various kinds of scholarships, including the Tuition Fee Waiver Scheme. A scholarship programme to help meritorious candidates access higher education. 
Candidates must apply for the scholarships through the scholarship portal. 

$\begin{array}{l}Put7-4x=t\\ -4dx=dt\\ I=\int se{c}^2(7-4x)dx\\ =\frac{-1}{4}\int se{c}^{2}tdt=\frac{-1}{4}(tant)+C\end{array}$

The placement rate recorded during NSoJ placements 2023 was 100%.

To be eligible for the BSc programme in Computer Science and Visual Communication at Nazareth College of Arts and Science, students must have completed their Class 12 examination from a recognised board with a minimum aggregate of 40% marks. Meeting this criterion is essential to apply for admission to the course.

$\begin{array}{l}Put2x-3=t\\ 2dx=dt\\ I=\int ta{n}^2(2x-3)dx={\displaystyle \int \left[se{c}^2(2x-3)-1\right]dx}\\ =\frac{1}{2}\int \left(se{c}^{2}t\right)dt-{\displaystyle \int 1}dx\\ =\frac{1}{2}tant-x+C=\frac{1}{2}tan(2x-3)-x+C\end{array}$

The highest and average package offered during NSoJ placements 2023 are presented below:

$\begin{array}{l}Put{e}^{2x}+e^{-2x}=t\\ \begin{array}{l}\Rightarrow (2e^{2x}-2{e^{-}}^{2x})dx=dt\hfill \end{array}\end{array}$

$\begin{array}{l}\begin{array}{ll}\Rightarrow 2(e^{2x}-{e^{-}}^{2x})dx=dt\hfill & \hfill \end{array}\\ I=\int \frac{e^{2x}-e^{-2x}}{e^{2x}+e^{-2x}}dx=\int \frac{dt}{2t}=\frac{1}{2}\int \frac{1}{t}dt\\ =\frac{1}{2}log\left|t\right|+=\frac{1}{2}log\left|e^{2x}+e^{-2x}\right|+C\end{array}$

Yes, students enrolled in the BSc course of Chennais Amirta International Institute of Hotel Management, (CAIIHM) Chennai, are eligible for various scholarships. These scholarships include Merit-based Scholarships, Community-based Scholarships, and College-specific Scholarships. Listed below are some of the scholarships that BSc students of CAIIHM Chennai can avail of:

• 10% Scholarship on the term fees: Offered to ST/ SC Students
• 10% Merit Scholarship on the term fees: Offered to students scoring over 90% in Class 12
• Sports Quota Scholarship: Offered to students with records of excellence in sports at the National/ State/ District level

Profcyma Career Solutions (Dr. D. Y. Patil Vidyapeeth- Center for Online Learning) enquiry forms are also available online. Candidates meeting the eligibility criteria can apply for the preferred course. Below are the steps to fill out the from

Step 1: Visit the official Profcyma Career Solutions (Dr. D. Y. Patil Vidyapeeth- Center for Online Learning) .

Step 2: Fill out the form.

Step 3: Complete and submit it. 

Dividing both numerator and denominator by e^x, we get

$\begin{array}{l}\frac{\frac{e^{2x}-1}{e^x}}{\frac{e^{2x}+1}{e^x}}=\frac{e^x-e^{-x}}{e^x+e^{-x}}\\ Put{e}^x+e^{-x}=t\\ \Rightarrow \left(e^x-e^{-x}\right)dx=dt\\ I=\int \frac{e^{2x}-1}{e^{2x}+1}dx=\int \frac{e^x-e^{-x}}{e^x+e^{-x}}dx\\ I=\int \frac{dt}{t}=log\left|t\right|+c\\ =log\left|e^x+e^{-x}\right|+c\end{array}$