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Sure! Here is an overview of theGame top BCA colleges in West Bengal:

Disclaimer: This information is sourced from the official website and may vary.

There are around 145+ BCA colleges in West Bengal. Students can get into these top colleges through entrance exams like CUET and MAKAUT. However, most colleges accept Class 12 scores as well.

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Yes, admissions at Deviprasad Goenka Management College of Media Studies are easy for hardworking students. Candidates must know their DGMC eligibility criteria and apply accordingly. Follow the DGMC application process mentioned below:

Step 1: Visit the official website of DGMC.

Step 2: Select the course.

Step 3: Pay the application fee.

Step 4: Fill out and submit the application form with the required information, such as the Registration no. of the University of Mumbai Pre-enrollment form and others.

DGMC offers BSc and MA as popular programmes. With the BSc course, students learn Statistics, Computing, and Data Analysis with various real-world applications. The BSc course focuses on the prediction, modeling, and Data Ethics while staying aligned with the various industry trends. Students get a chance to get equipped for various in-demand roles in the data-driven world.

Pursuing a BSc at Chennais Amirta International Institute of Hotel Management (CAIIHM) offers promising career prospects in the rapidly growing hospitality and tourism sectors. They are typically hired at entry-level positions in Hotels, Resorts, Cruise Lines, Airlines, Event Management Firms, etc. Some job role that CAIIHM Chennai BSc graduates can take up are listed below:

• Hotel Operations Manager
• Food and Beverage Manager
• Hospitality Consultant
• Sales & Marketing Executive in Hospitality
• Event Coordinator

Deviprasad Goenka Management College of Media Studies has a big campus with multiple facilities available for students. Deviprasad Goenka Management College of Media Studies has dynamic & fully air-conditioned classrooms, Wifi connection, up-to-date technical equipment, canteen facility, and others.

This is a multiple choice answer as classified in NCERT Exemplar

(a), (d) for steel wire Y_steel= stress/strain= $\frac{f/A}{starin}$

When F and A are same for both the wires . hence stress will be same for both the wire

(Strain)_steel= stress/Y_steel  and strain_copper=stress/Y_copper

Y_{steel $\ne$} Y_copper

hence they both have different starin

This is a multiple choice answer as classified in NCERT Exemplar

(a), (d) An ideal liquid is not compressible

Hence $?$ V=0

Bulk modulus B= strss /volumetric strain= $\frac{\frac{F}{A}}{\frac{?V}{V}}=\infty$

Compressibility K= 1/B=1/ $\infty =0$

As there is no tangential force exists. So shear strain =0

This is a multiple choice answer as classified in NCERT Exemplar

(b), (d) Let mass m is placed at x from the end B respectively.

T_A and T_B be the tensions in wire A and wire B respectively.

For the rotational equilibrium of the system,

$\sum \tau =0$

T_Bx-T_A(l-x)=0

$\frac{T_B}{T_A}$ = $\frac{l-x}{x}$

Stress in wire A = S_A= $\frac{T_A}{a_A}$

Stress in wire B = S_B= $\frac{T_B}{a_B}$  where a are the area of wire

We know that a_B=2a_A

Now for equal stress

S_A=S_B

$\frac{T_A}{a_A}=\frac{T_B}{a_B}$

So

$\frac{T_B}{T_A}=2$

$\frac{l-x}{x}=2$

So x =l/3 and l-x= 2l/3

Hence mass m should placed to B.

For equal strain

Strain_A= Strain_B

$\frac{Y_A}{S_A}=\frac{Y_B}{S_B}$

$\frac{Y_{steel}}{Y_{Al}}=\frac{T_A}{T_B}\times \frac{a_B}{a_A}=\frac{x}{l-x}\left(\frac{2a_A}{a_A}\right)$

$\frac{200\times {10}^9}{70\times {10}^9}=\frac{x}{l-x}$

After  solving we get x= x= 10l/17

l-x=l=10l/17=7l/17

This is a multiple choice answer as classified in NCERT Exemplar

(a), (d) Forces at cross section is F.

Now applying formula . stress = tension/area=F/A

Tension = applied force =F

This is a multiple choice answer as classified in NCERT Exemplar

(c), (d) The ultimate tensile strength for material ii is greater hence material ii is elastic over larger region as compared to material (i) for material (ii) fracture point is nearer, hence it is more brittle.

This is a multiple choice answer as classified in NCERT Exemplar

(d) a mass M is attached at the centre. As the mass is attached to both the rods, both rod will be elongated, but due to different elastic properties of material rubber changes shape also.

Some common alternate courses to the Bachelor of Mass Media are Bachelor of Journalism and Mass Communication (BJMC), Bachelor of Mass Communication (BMC), Bachelor of Journalism (B.J.), BA Mass Communication (BAMC), and BA Hons in Journalism. The curriculum and future prospects of all these courses are similar; however, the foundational knowledge may vary.

This is a multiple choice answer as classified in NCERT Exemplar

(c) 2Tsin $\theta$ -mg=0

2Tsin $\theta$ =mg

Total horizontal forces = Tcos $\theta -Tcos\theta =0$

T=mg/2sin $\theta$

As mg is constant T $\propto \frac{1}{sin\theta }$

T_max= mg/sin $\theta$ _min

Sin $\theta$ _min=0, $\theta$ _min= 0

T_min=mg/2sin $\theta$ _max

_{$sin\theta$ max}= 1, $\theta$ =90⁰