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The top private MBA colleges in Navi Mumbai include ITM Business Schoo, DY Patil University School of Management, etc., known for their quality education, experienced faculty with high tuition fees. Listed below are some of the top private colleges -

Source: Official site and may vary.

This is a long answer type question as classified in NCERT Exemplar

Suppose the charge is slightly shifted to left so net potential energy will be

U= $\frac{1}{4\mathit{\pi }{\mathit{\epsilon }}_0}\{\frac{-{\mathit{q}}^2}{\left(\mathit{d}-\mathit{x}\right)}+\frac{-{\mathit{q}}^2}{(\mathit{d}+\mathit{x})}\}$

U= $\frac{-{\mathit{q}}^2}{4\mathit{\pi }{\mathit{\epsilon }}_{\mathit{o}}}\frac{2\mathit{d}}{({\mathit{d}}^2-{\mathit{x}}^2)}$

$\frac{\mathit{d}\mathit{U}}{\mathit{d}\mathit{x}}$ = $\frac{-{\mathit{q}}^{2}2\mathit{d}}{4\mathit{\pi }{\mathit{\epsilon }}_{\mathit{o}}}\frac{2\mathit{x}}{{({\mathit{d}}^2-{\mathit{x}}^2)}^2}$

System will be in equilibrium if this energy is zero

But when we double differentiate it

But when x<0 this value is negative so less than 0

This shows an unstable equilibrium

It follows the parabolic graph

Here are some details about the entrance exams that are accepted at the top MBA colleges in Navi Mumbai:

Disclaimer: This information is sourced from the official website and may vary.

As per the popularity basis by shiksha.com, listed below are some of the best MBA colleges in Navi Mumbai with their tuition fees -

Source: Official site and may vary.

The key highlights of CUSAT placements for the Class of 2024 are tabulated below:

Note: The above-mentioned placement stats are sourced from the media reports. These may vary once the final placement report 2024 is out.

Students can go for the following books to study personification:

This is a long answer type question as classified in NCERT Exemplar

Let any three point x,y,z  seprated by a distance 2d

Then potential due to two charges

$\frac{q1}{(\sqrt[]{x^2+{\left(y\right)}^2+{(z-d)}^2}}+\frac{q2}{(\sqrt[]{x^2+{\left(y\right)}^2+{(z+d)}^2}}$ =0

$\frac{q1}{(\sqrt[]{x^2+{\left(y\right)}^2+{(z-d)}^2}}$ = $\frac{q2}{(\sqrt[]{x^2+{\left(y\right)}^2+{(z+d)}^2}}$

X²+Y²+z²+ $\frac{\left(\frac{q1}{q2}\right)+1}{\left(\frac{q1}{q2}\right)-1}$ (2zd)+d²-0

this is equation of sphere .

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There are about 20+ MBA colleges in Navi Mumbai and of these, 17 colleges are privately owned. CAT, MAT, MAH CET, XAT, etc. are some of the poplar entrance exams accepted in the best colleges.

Navi Mumbai MBA colleges include ITM Business School, DY Patil University School of Management, SIES School of Business Studies, NMIMS Deemed to be University, Vijay Patil School of Management, Pillai Institute of Management Studies and Research, etc.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- dW=F.dl=0

As dl = vdt

dW= Fvdt

dW= f.v=0

This is a long answer type question as classified in NCERT Exemplar

$\sigma$ =charge/Area

Q= $\sigma$ (2 $\pi rdr$ )

V=KdQ/ $\surd (r$ ²+x²)=K $\sigma$ (2 $\pi rdr$ )/ $\surd (r$ ²+x²)

After integration we got

V= $k\frac{Q}{2\pi a}$ ₂ ( $\sqrt[]{x^2+a^2}$ )-x

Reverse Personification flips the concept of Personification that assigns animal, inanimate, or other non-human traits to human beings. Reverse personification can be used to explore themes, critique societal norms, or create thought-provoking narratives. For example:

·       She is as tall as a tree.

·       He has a heart of stone.

This is a long answer type question as classified in NCERT Exemplar

When initially K₁ is closed and K₂ is open, the capacitors C₁ and C₂ connected in series with battery

Q=CV=C (C₁C₂/C₁+C₂) = 6 $\times$ 3/6+3=18 $\mu$ C

Now K₁ was opened and K₂ was closed, the battery and capacitor C, are disconnected from the circuit .

Here charge being shared by both capacitor so a common potential will develop.

V=C₁V₁+C₂V₂/C₁+C₂ = 18/3+3=3V

Q₂=3CV=3 $\times$ 3=9μC

Q₃=3CV=3 $\times$ 3=9μC

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Personification is always figurative it's not intended to be taken literally. Personification uses human qualities or behaviors that would be appropriate for the object or concept being personified. Personification in language should enhancing imagery, making a concept more relatable, or creating a specific mood.

This is a long answer type question as classified in NCERT Exemplar

As we know that,   $\sigma$ =charge/Area

Q₁= $\sigma$ (4 $\pi r$ ²)

Q₂= $\sigma$ (4 $\pi \left(2r\right)$ ²)= 4Q₁

when they come in contact with each other potential being same and charge will be conserved.

So net charge is 5Q₁= 5 ( $\sigma$ (4 $\pi r$ ²)

Also V₁=V₂

KQ₁/R=KQ₂/2R  so Q₁=Q₂/2

Q₁= $\frac{5}{3}(\sigma$ (4 $\pi r$ ²) and Q₂= $\frac{10}{3}(\sigma$ (4 $\pi r$ ²)

$\sigma$ =5 $\sigma$ /3  and $\sigma$  =5 $\sigma$ /6

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- i_G (G) = (I₁-I_G) (S₁+S₂+S₃) for I₁= 10mA

i_G (G+S₁) = (I₂-I_G) (S₂+S₃) for I₂= 100mA

i_G (G+S₁+S₂) = (I₃-I_G) (S₃) for I₃= 1A

S₁= 1W, S₂= 0,1W and S₃= 0.01W