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Nazareth College of Arts and Science has a diverse range of recruiters participating in its placement drives. Some key names include Larsen & Toubro Infotech, TCS BPS, Infosys BPO, Sundaram Finance, Tech Mahindra, Sutherland Global Services, Star Health Insurance, Mphasis, CAMS Outsourcing, and Qspiders. These recruiters highlight the college's strong industry connections and career support for BBA students.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- c

Explanation– as the given track y=x² is a frictionless track thus total energy will be same throughout the journey.

Hence total energy at A = total energy at P . at B the particle is having only Ke but at P some KE is converted to P

Hence (KE)_B = (KE)_P

Total energy at A = PE= total energy at B = KE= total energy at P

= PE+KE

Potential energy at A is converted to KE and PE at P hence

(PE)P< (PE)A

Hence (height)P= (height)A

As height of p < height of A

Hence path length AB > path length BP

This is a long answer type question as classified in NCERT Exemplar

To lift the disc ther must be some electrostatic force is reqired.

F=qE……. (1), E=V/d………. (2)

But the charge required during the process is - $\in$ _{0 $\frac{v}{d}\pi$} r², using this relation in 1 and 2

F=- $\in$ _{0 $\frac{v}{d}\pi$} r²V/d…… (3)

Also to balance something F=mg……. (4)

From equation 3 and 4

Mg= - $\in$ _{0 $\frac{v}{d}\pi$} r²V/d, so V = $\surd \frac{mgd}{\in 0\mathrm{\pi }\mathrm{r}}$ ₂ this the requird solution.

Yes, you are eligible. The minimum requirement to apply for the BBA course at NCAS is 40% aggregate marks in Class 12 from a recognised board. With 45%, you satisfy the eligibility condition and can proceed with the application.

NCERT Exemplar goes beyond the NCERT textbook as it contains questions based on the textbook concepts. While practicing the short answer type questions, long answer type questions, and multiple choice questions, students learn how to use these concepts for solving problems. It will help students improve their analytical thinking and problem-solving skills and develop a deeper understanding of concepts. It prepares students for CBSE Board exams and competitive exams like NEET and JEE.

Some of the top colleges that accept TS EAMCET scores for admission along with the opening and closing rank -

GITAM University Vishakhapatnam Campus offers scholarships to students as financial assistance. The top-performing students are provided Merit-Based Scholarships. There are Special Scholarships for Distinguished Groups. Under this type of scholarship scheme, there are CRPF Scholarships, Indian Navy Scholarships, and others. The below-mentioned are the scholarships awarded to the GITAM University Vishakhapatnam Campus students:

Yes, having prior work experience or a bachelor's degree in Fashion Design is not mandatory to join the MFTech course. However, coming from a different field, you will need to have some basic sketching and Design principles skills and a passion for learning a different avenue. 

While applying Kirchhoff's Current Law (KCL) at junctions, the total current leaving is equal to the total current entering. For Kirchhoff's Voltage Law (KVL) in loops, the total of the voltage gains and drops around any closed loop is zero. To avoid mistakes, students must assign a direction to currents which can be positive for gains and negative for drops, and be consistent with the signs while solving the equations.

The PTE score rechecking, which can only be requested via phone, is a payable service; which means that this service is not free. The PTE score rechecking costs  $160 USD; however, this amount is refunded if your overall or communicative skills score changes upon rechecking.   

Master's degree in Zoology or Microbiology is offered at GITAM University, Vizag.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- a,b,c

Explanation – H= $\frac{u^2{sin}^2\theta }{2g}$

H₁=V_o²sin^{2 $\theta$} ₁/2g  , H₂=V_o²sin^{2 $\theta$} ₂/2g

H₁>H₂

V_o²sin^{2 $\theta$} ₁/2g= V_o²sin^{2 $\theta$} ₂/2g

Sin^{2 $\theta$} ₁>sin^{2 $\theta$} ₂

Sin^{2 $\theta$} ₁ – sin² $\theta$ ₂>0

(Sin $\theta$ ₁ – sin $\theta$ ₂)( Sin $\theta$ ₁ + sin $\theta$ ₂)>0

Sin $\theta$ ₁>sin $\theta$ ₂ or ₁ >₂

T= $\frac{2usin\theta }{g}=\frac{2v_{o}sin\theta }{g}$

T₁= $\frac{2v_{o}sin{\vartheta }_1}{g}$   , T₂= $\frac{2v_{o}sin{\vartheta }_2}{g}$

T₁> T₂

R= $\frac{u^{2}sin2\theta }{g}=\frac{v_o^{2}sin2\theta }{g}$

Sin $\theta$ ₁>sin $\theta$ ₂

Sin2 $\theta$ ₁> sin2 $\theta$ ₂

$\frac{R_1}{R_2}=\frac{\mathrm{S}\mathrm{i}\mathrm{n}2{\theta }_1}{sin2{\theta }_2}1$

R₁>R₂

Total energy for the first particle

U₁=K.E+P.E=1/2m_{1 $v_o^2$}

U₂= K.E+P.E= 1/2m_{2 $v_o^2$}

Total energy for the second particle

So m₁= m₂ then U₁=U₂

So m₁>m₂ then U₁>U₂

So m₁2 then U1

This is a long answer type question as classified in NCERT Exemplar

$\frac{1}{4\pi ??}\frac{q}{(\sqrt[]{x^2+{(d/2)}^2+h^2}}$ - $\frac{1}{4\pi ??}\frac{q}{(\sqrt[]{x^2-{(d/2)}^2+h^2}}$

If net potential is zero then,

$\frac{1}{(\sqrt[]{{\mathit{x}}^2+{(\mathit{d}/2)}^2+{\mathit{h}}^2}\mathit{}}$ = $\frac{1}{(\sqrt[]{{\mathit{x}}^2+{(\mathit{d}/2)}^2+{\mathit{h}}^2}\mathit{}}$

$x^2+{(d/2)}^2+h^2$ = $x^2-{(d/2)}^2+h^2$

2dx= 0 , x=0

X=0 , y-z plane.

In the first semester, BBA students at NCAS study introductory subjects that form the base for advanced business learning. These include Principles of Management, Business Communication, Financial Accounting, Business Mathematics, and Business Environment. These subjects help students understand the fundamentals of business operations and management, which are essential for future coursework.

GITAM University Vishakhapatnam Campus, through various schools of study, offers UG, PhD, and PG courses to students. The below-mentioned are schools of study under the GITAM University Visakhapatnam Andhra Pradesh:

Nazareth College of Arts and Science offers various scholarship schemes with benefits that vary based on the type of scholarship. While certain schemes provide full tuition fee coverage, others, like the Single Parent Scholarship, grant a 50% waiver on tuition fees for the first semester. Eligible BBA students are encouraged to review the criteria for each scheme and apply accordingly to take advantage of the financial support offered.

This is a long answer type question as classified in NCERT Exemplar

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- a, b

Explanation - |A+B|= |A|or |A+B|²=|A|²

|A|² +|B|²+2|A|B|cos $\theta$ = |A|²

|B| (|B|+2|A|cos $\theta$ )= 0

|B|=0 or |B|+2|A|cos $\theta$ =0

Cos $\theta$ = $\frac{-\left|B\right|}{2\left|A\right|}$

If A and B are antiparallel then $\theta$ =180

-1= $\frac{\left|B\right|}{2\left|A\right|}=\left|B\right|=2\left|A\right|$