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10 months ago

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10 months ago

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V
Vishal Baghel

Contributor-Level 10

1x(xn+1)=xn1xn1x(xn+1)=xn1xn(xn+1)

Putting xn = t Þ n xn- 1dx = dt

dxx(xn+1)=xn1dxxn(xn+1)=1ndtt(t+1)=1n(t+1t)t(t+1)dt=1n{t+1t(t+1)tt(t+1)}dt.=1n{dttdtt+1}=1n{logtlog(t+1)}+C.=1nlog?tt+1+ C=1nlog|xnxn+1|+C.

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10 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer – (c)

Explanation – R/S= (l1/100-l1)= 100 (2.9/100-2.9)= 100/97.1=2.98ohm

So he should change S to almost 3 ohm and repeat the experiment.

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10 months ago

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Vishal Baghel

Contributor-Level 10

Kindly go through the solution

⇒A=12Andfrom(1)weget,12dxy21=12dxy112dxy+1=12dxx2112dxx21{y=x2}=12×121log|x1x+1|12tan1x+ C=14log|x1x+1|12tan1x+ C

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10 months ago

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N
Nitesh Dhyani

Beginner-Level 5

Some of the most common Figures of Speech are as follows:

·       Simile

·       Metaphor

·       Personification

·       Hyperbole.

This is not the exact or absolute list, but are among the commonly used Figures of Speech. 

 

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10 months ago

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H
Himanshu Singh

Contributor-Level 10

Yes, candidates with a  45% aggregate marks in Class 12 from a recognised board are eligible to apply for the BCom programme at NCAS. Having 40% marks meets the eligibility requirement, allowing students to proceed with the application process.

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10 months ago

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Vishal Baghel

Contributor-Level 10

Kindly go through the solution

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

Consider the diagram

let n =number of molecules per unit volume

Vrms= rms speed of gas molecule

When block is moving with speed vo, relative speed of molecules w.r.t front face =v+vo

Coming head on, momentum transferred to block per collision =2m (v+vo)

Number of collisions in time ? t = 1 2 (v+vo)n ? t A  where A is the area of cross section.

So momentum transferred in time ? t =m (v+vo)2nA ? t   this is from front surface

Similarly momentum transferred in time ? t = m (v-vo)2nA ? t ) this is from back surface

Drag force = mnA (v+vo)2- (v-vo)2)

= mnA (4wo)=4mnAvvo

= 4 ρ A vvo

So ρ =mn/V=M/

...more

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10 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- (a)

Explanation- eeq= e2r1+e2r1r1+r2

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10 months ago

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Vishal Baghel

Contributor-Level 10

Kindly go through the solution

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10 months ago

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H
Himanshu Singh

Contributor-Level 10

Admission to the BCom programme at Nazareth College of Arts and Science is determined purely by merit. Selection is based on the students' Class 12 academic results, with no entrance examination needed. The college assesses applications by examining academic performance and releases merit lists to finalise the admission process.

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10 months ago

0 Follower 7 Views

P
Pooja Kalra

Beginner-Level 5

Figures of Speech are literary devices which add value to a sentence by providing an imagery, special effect and contrasts to create a vivid impact, drama element and improve the reader engagement. Figures of Speech is widely used in literature such as poems, drama or plays, novels, short stories, etc. Apart from that, Figures of Speech are also used in day to day lives and commercial purposes such as advertisement campaigns.

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10 months ago

1 Follower 16 Views

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10 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- (b)

Explanation- as we know that J=E, and current density is directly proportional to electric field, so electric field produced by charges accumulated on the surface of wire.

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10 months ago

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Vishal Baghel

Contributor-Level 10

Kindly go through the solution

New Question

10 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

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10 months ago

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P
Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

Given volume V = 1m3

area = 0.01mm2

= 8.01 × 10 - 6 m2= 10 - 8 m2

Temperature both inside and outside are equal

So initial pressure inside the box = 1.50atm

Final pressure inside the box= 0.1atm

Assuming Vx= speed of nitrogen molecule in x direction

ni = number of molecules per unit volume in a time interval of ? T

Let area of the wall, number of particles colliding in time

? t = 1 2 n i (vx ? t )A , here we use ½ because particle moves both in positive and negative direction.

Vx2+ Vy2+ Vz2= Vrms2

Vx2= Vrms2/3 if all three velocities are equal.

½ mvrms2= 3/2KBT/m

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10 months ago

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Vishal Baghel

Contributor-Level 10

Kindly go through the solution

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10 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- according to ohms law

I= VeffReff+R

If voltage and resistance increase

V'= nVeff, R'= nReff

I'= nVeffnReff+nR= VeffReff+R =

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10 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

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