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In Education domain, Vocabulary are the words in English Language that students must know to understand the texts. Knowing vocabulary is important and one of the major contributors when it comes to answering the questions on Reading Comprehension or Unseen Passage. It not only helps the students at school level but also helps the aspirants or candidates who take competitive exams such as SSC exams, UPSC exams, RRB exams, IBPS exams, etc.

Yes, after completing the BBA course offered by Sewa Community College, students can seek out various government jobs. One way is to directly apply to government organisations for vacancies in relevant areas. Tabulated below are some of the popular government job titles for BBA students to pursue:

Note: The above-mentioned average salaries are industry-based average payouts. The actual pay may differ.

$\begin{array}{l}=\frac{cos2x}{co{s}^{2}x+si{n}^{2}x+2sinxcosx}\\ =\frac{cos2x}{1+sin2x}\end{array}$

$\begin{array}{l}={\displaystyle \int \frac{cos2x}{{(cosx+sinx)}^2}}dx\\ ={\displaystyle \int \frac{cos2x}{1+sin2x}}dx\\ \begin{array}{l}Put 1 + sin 2x=t\hfill \end{array}\end{array}$

$\begin{array}{l}\begin{array}{l}2 cos 2x dx=dt\hfill \end{array}\\ ={\displaystyle \int \frac{cos2x}{{(cosx+sinx)}^2}}dx\\ =\frac{1}{2}{\displaystyle \int \frac{1}{t}}dt=\frac{1}{2}log\left|t\right|+\; C\\ =\frac{1}{2}log\left|1+sin2x\right|+\; C\\ -\frac{1}{2}log\left|{(cosx+sinx)}^2\right|+\; C\\ =log\left|cosx+sinx\right|+C\end{array}$

This is a multiple choice answer as classified in NCERT Exemplar

(b), (c), (d) When the hot milk in the table is transferred to the surroundings by conduction, convection and radiation.

According to newton's law of cooling temperature of the milk falls of exponentially. Heat also will be transferred from surroundings to the milk but will be lesser than that of transferred from milk to surroundings. So option b, c, d satisfy.

Bharati Vidyapeeth College of Engineering offers courses at the UG and PG level. The duration of the respective courses varies from 2 years to 4 years with admission offered on the basis of merit and accepted entrance exams. BVCOE offers BTech and M.Tech as the prime course in full-time mode with various specialisations. The Institute offers the respective course at a total tuition fee ranging from INR 1.8 Lacs to INR 5.2 Lakh. 

Vocabulary is the set or words known and used by an individual. For example: My teacher has an amazing vocabulary. On the other hand, Vocabulary also refers to all the words in a language such as English. For example: Every year, new words are added into English Vocabulary.

Some of the common English Vocabulary words used in daily life are: come, go, eat, sit, hi, hello, good, bad, sit, up, down, give, have, get, stand, this, that, poor, rich, die, live, life, silence, noise, etc.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer. (c)

Explanation- As the space is increasing towards right means electric field is decreasing so as force is also decreasing . so force on -p is more than the force on +p 

$\begin{array}{l}\frac{si{n}^{2}x+co{s}^{2}x}{sinxco{s}^{3}x}=\frac{sinx}{co{s}^{3}x}+\frac{1}{sinxcosx}\\ =tanxse{c}^{2}x+\frac{co{s}^{2}x}{\left(\frac{sinxcosx}{co{s}^{2}x}\right)}\\ =tanxse{c}^{2}x+\frac{se{c}^{2}x}{tanx}\\ I={\displaystyle \int \frac{1}{sinxco{s}^{3}x}}dx={\displaystyle \int tan}xse{c}^{2}xdx+{\displaystyle \int \frac{se{c}^{2}x}{tanx}}dx\\ \begin{array}{l}Put tanx=t\hfill \end{array}\end{array}$

$\begin{array}{l}\begin{array}{l}Se{c}^{2}x dx=dt\hfill \end{array}\\ ={\displaystyle \int \frac{1}{sinxco{s}^{3}x}}dx={\displaystyle \int tanxse{c}^{2}xdx+{\displaystyle \int \frac{se{c}^{2}x}{tanx}}dx}\\ ={\displaystyle \int t}dt+{\displaystyle \int \frac{1dt}{t}}\\ =\frac{t^2}{2}+log\left|t\right|+\; C\\ =\frac{1}{2}ta{n}^{2}x+log\left|tanx\right|+\; C\end{array}$

BFTech is a great course option for students who want to gain both Design and technical exposure. However, some may feel challenges like:

• High competition in the Design industry.
• High expectations from employers.
• Constantly evolving trends can be overwhelming to keep up with.
• Cost of BFTech education can be financial burden for some students.

This is a multiple choice answer as classified in NCERT Exemplar

(a), (d) During the process AB temperature of the system is 0⁰C . hence it represents phase change that is transformation of ice into water while temperature remains 0⁰C.

BC represents rise in temperature of water from 0⁰C to 100⁰C. now water starts converting into steam which is represented by CD.

Which is only represents by a, d options

$\begin{array}{l}=\frac{cos2x+(1-cos2x)}{co{s}^{2}x}\\ =\frac{1}{co{s}^{2}x}=se{c}^{2}x\\ ={\displaystyle \int \frac{cos2x+2si{n}^{2}x}{co{s}^{2}x}}dx\\ \begin{array}{l}={\displaystyle \int se{c}^2}xd x\hfill \end{array}\end{array}$

$\begin{array}{l}\begin{array}{l}= tanx+ C\hfill \end{array}\end{array}$

Students enrolled in the Sewa Community College BBA programme gain knowledge of various domains, including HR, Finance, Operations, and more. In general, students who hold a BBA degree showcase a better understanding of business as compared to other students. Thus, pursuing a BBA offers an array of professional possibilities. Listed below are a few of the job profiles students can pursue after completing a BBA:

• Consultant
• Product Manager
• Financial analyst
• Digital marketer
• Junior Accountant
• Business Administrator
• Financial Analyst

Aspirants of BBA at SBBSU can explore other options as well. There are over 40 BBA colleges in Ludhiana. However, the parameters considered for comparison shall give out fair results. Mentioned below are a few parameters that can be taken into consideration:

• Fees
• Placement package
• Faculty
• Location, etc.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer. (b)

Explanation-The charges may be located anywhere inside the surface, if the surface      is so chosen that there are some charges inside and some outside, the electric field on the left side of equation is due to all charges, both inside and outside S.

$\begin{array}{l}\frac{si{n}^{3}x+co{s}^{3}x}{si{n}^{2}x\cdot co{s}^{2}x}=\frac{si{n}^{3}x}{si{n}^{2}x\cdot co{s}^{2}x}+\frac{co{s}^{3}x}{si{n}^{2}x.co{s}^{2}x}\\ =\frac{sinx}{co{s}^{2}x}+\frac{cosx}{si{n}^{2}x}\\ =tanxsecx+cotxcosecx.\\ ={\displaystyle \int \frac{si{n}^{3}x+co{s}^{3}x}{si{n}^{2}x\cdot co{s}^{2}x}}dx\\ \begin{array}{l}={\displaystyle \int \left(tanxsecx+cotxcosecx\right)dx}\hfill \end{array}\end{array}$

$\begin{array}{l}\begin{array}{l}= secx-cosecx+ C\hfill \end{array}\end{array}$

This is a multiple choice answer as classified in NCERT Exemplar

(b), (c) Smaller gulab jamun having least surface area hence they will be heated first. As in case of smaller gulab jamun heat radiates will be less.

Similarly smaller pizzas are heated before bigger ones because of smaller surface area.

The important admission dates related to NINS Kolkata are: 

• JENPAS UG conducted on 25 May 2025
• NEET result to be tentatively announced on 14 June 2025

Candidates are required to take note of these dates in order to make sure they don't miss any important updates .

Candidates seeking course admission at Ishan Institute of Pharmacy cannot enrol for direct admission. The college admits students based on scores from entrance exam score as per course requirement. To enrol for course admission, students must apply through the official website. Aspirants can apply for course admission on the official website.

$ta{n}^{4}x=ta{n}^{2}xta{n}^{2}x$

$=(se{c}^{2}x-1)ta{n}^{2}x$

$=se{c}^{2}x.ta{n}^{2}x-ta{n}^{2}x$

$=se{c}^{2}x.ta{n}^{2}x-(se{c}^{2}x-1)$

I $\begin{array}{l}\begin{array}{}\end{array}=se{c}^{2}x.ta{n}^{2}x-se{c}^{2}x+1\end{array}$

$\begin{array}{l} I={\displaystyle \int ta{n}^4}xdx={\displaystyle \int se{c}^2}x.ta{n}^{2}xdx-{\displaystyle \int se{c}^2}xdx+{\displaystyle \int 1}.dx\end{array}$

$\begin{array}{l}={\displaystyle \int se{c}^2}x.ta{n}^{2}xdx-tan\pi +x+C-----\left(i\right)\end{array}$

$\begin{array}{l}LetI={\displaystyle \int se{c}^2}x.ta{n}^{2}xdx\end{array}$

$\begin{array}{l}Puttanx=t\end{array}$

$\begin{array}{l}se{c}^{2}xdx=dt\end{array}$

$\begin{array}{l}{I}_1={\displaystyle \int se{c}^2}x.ta{n}^{2}xdx\end{array}$

$\begin{array}{l}={\displaystyle \int t^2}dt\end{array}$

$=\frac{t^3}{3}=\frac{ta{n}^{3}x}{}$

$\frac{3}{}I={\displaystyle \int ta{n}^4}xdx$

$=\frac{1}{3}ta{n}^{3}x-tanx+x+\; C$

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer. (d) 

Explanation- Total flux inside a conducting sphere is depend upon the algeabric sum of total charge inside that surface, which is same for all fig. As it does not depend upon shape of a body