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To secure a seat in the MBA programme at Neelkanth Group of Institutions, candidates must first meet the eligibility requirement of having at least 50% aggregate marks in their graduation. Additionally, they must present a valid scorecard from a recognised entrance exam such as CAT, MAT, GMAT, or UPSEE. Due to the limited intake of 60 seats, early application and a strong academic and entrance exam profile are important for improving admission chances.

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This is a long answer type question as classified in NCERT Exemplar

Total current i=i1+i2

Vmsinwt=Ri1

I1= $\frac{V_{m}sinwt}{R}$

If q2 is charge on the capacitor at any time t then for series combination of C and L

Applying KVL in below circuit

So q2=qmsin(wt $\frac{q_2}{C}+\frac{Ld{i}_2}{dt}-V_{m}sinwt=0$ )……….1

qm[ $+\varnothing$ sin(wt+ $\frac{q_2}{C}+\frac{L{d}_2{q}_2}{d{t}^2}=V_{m}sinwt$ )]= Vmsinwt

if $\frac{d{q}_2}{dt}=-q_m{w}^2\mathrm{s}\mathrm{i}\mathrm{n}?(wt+\varnothing )$

qm= $usethisvalueineqn1$

from above equation i2= $\frac{1}{C}+L(-w^2)$

i2= $\varnothing$ when $\varnothing =0$

so total current I = i1+i2

I= $\frac{V_m}{(\frac{1}{c}-L{w}^2)}$

I= i1+i2= Ccos $\frac{d{q}_2}{dt}=w{q}_m\cos ?\left(wt+\varnothing \right)$ +Csin $\frac{w{V}_m\mathrm{c}\mathrm{o}\mathrm{s}?(wt+\varnothing )}{\frac{1}{c}-L{w}^2}$

I= Csin(wt+ $\varnothing =0,i_2=\frac{V_{m}coswt}{\frac{1}{wC}-Lw}$ )

C= $\frac{V_{m}sinwt}{R}+\frac{V_{m}coswt}{\frac{1}{wC}-Lw}$

$\varnothing sinwt$ 1/2

$\varnothing coswt$ = tan-1 $\varnothing$

$\sqrt[]{A^2+B^2}$ 1/2

This is the expression for impedance.2

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This is a long answer type question as classified in NCERT Exemplar

For the 2025 academic session, Neelkanth Group of Institutions has a total of 60 seats available for the MBA programme. This limited intake creates a competitive admission process for prospective students.

This is a long answer type question as classified in NCERT Exemplar

Power drawn, p= 2KW= 2000W

tan $\varnothing$ =-3/4

P=V2/Z

Z=V2/P= $\frac{223\times 223}{2\times {10}^3}$ =25

Z = $\sqrt[]{R^2+({X_L-X_C)}^2}$

25= $\sqrt[]{R^2+({X_L-X_C)}^2}$

625 = $R^2+({X_L-X_C)}^2$ ………… (1)

tan $\varnothing$ = $\frac{X_L-X_C}{R}$ = ¾

XL-XC= 3R/4

Use this in eqn 1

625= R2+ (3R/4)2 = R2+9R2/16

625 = 25R2/16, R= 20ohm

XL-XC=15ohm

Im= $\sqrt[]{2}$ I= $\sqrt[]{2}V/Z$ = $\frac{223\times \sqrt[]{2}}{25}$ = 12.6A

If R, XL and Xc are all doubled, tan $\varnothing$ does not change . Z is doubled, current is halved. So power is also halved.

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This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation- F=GMm/r²

M=effective mass of hydrogen atom=mass of electron +mass of proton -B²/c

B.E of hydrogen atom = 13.6eV

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer (c)

Explanation- it is a process in which metal decays spontaneously . so during a span of 1 year it will decay almost half of its original value so it will come close to 5000.

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Madras University, through various schools of study, offers PG, PhD, diploma, certificate, and other courses to students. The below-mentioned are University of Madras Chennai schools of study:

As of now, the DYPIEMR is not accepting applications for the BTech programme for the academic year 2025. Interested candidates are advised to visit the official website frequently to stay updated with the upcoming events. Hence, it is essential for candidates to submit the application before the stipulated deadline.

Yes, Over the past few years, the University of Madras Rankings have been given for multiple streams, namely Management, and others. A few of the important University of Madras rankings are mentioned below:

HBSE 10th Supplementary exams 2025 were held between July 5 and 14, 2025. The Board released the HBSE Class 10 supplementary date sheet 2025 on the official website. Students can check on the link provided to download the datesheet.