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This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- angular resolution of the eye? = 5.8 x 10^-4

linear distance between two dots is l= 2.54/300=0.84 $\times$ 10^-2cm

? = l/z

z=l/? = $\frac{0.84\times {10}^{-2}}{5.8\times {10}^{-4}}$ = 14.5cm

Tritya Institute of Event Management course admissions are based on entrance exam, as per the course requirement. Tritya Institute of Event Management admission process is aptitude based for all courses.  Students can check course-wise selection criteria below:

Students are advised to start the revision as early as possible to reduce the stress during MBSE HSSLC exam preparation. Check the points below to reduce board exam stress.

• Start early revision and plan 
• Make a proper time table
• Understand the syllabus and exam pattern
• Solve and learn with previous years' question papers
• Focus on time management
• Revise thoroughly
• Maintain a healthy lifestyle
• Stay positive and avoid comparisons

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- As we know that the frequencies of sound waves lie between 20 Hz to 20 kHz so that their wavelength ranges between 15 m to 15 mm. The diffraction occur if the wavelength of waves is nearly equal to slit width.

As the wavelength of light waves is 7000 *10^-10 m to 4000 $*$ 10^-10m. The slit width is very near to the wavelength of sound waves as compared to light waves. Thus, the diffraction of sound waves is more evident in daily life than that of light waves.

Clini Launch Research Institute offers admission to various PG Diploma, Advanced Diploma, MBA and Certificate courses on the basis of merit. Candidates must secure a minimum aggregate in Class 12 for admission to UG level courses and 50% aggregate in graduation for PG level courses. Furthermore, for courses such as MBA, candidates must qualify group discussion and personal interview for the final admission. 

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- We know that the sun is at very large distance from the earth. Assuming sun as spherical, it can be considered as point source situated at infinity. Due to the large distance the radius of wavefront can be considered as large (infinity) and hence, wavefront is almost plane.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- (c, d)

Explanation- in given figure the slope of curve A is greater than slope B. so decay in A is faster than B . also wavelength of A is grater than B.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- The point image I₁, due to L₁ is at the focal point. Now, due to the converging lens L₂, let final image formed is I which is point image, hence the wavefront for this image will be of spherical symmetry.

Students should not only depend only on the previous year question paper to clear the MBSE 12th examinations. They must also learn the text books prescribed by the board. Solving the previous question papers helps them to know pattern, type of questions and important questions. 

This is a short answer type question as classified in NCERT Exemplar

E=E₀sinwt

And current I=I₀sin (wt $\frac{+}{-}\varnothing$ )

Power, P= EI = E₀sinwt = E₀I₀sinwtsin (wt+ $\varnothing$ )

= $\frac{E_0{I}_0}{2}$  [cos $\varnothing -cos(2wt+\varnothing )$ ]………… (1)

Pav= $\frac{V_0}{\sqrt[]{2}}\frac{{\mathrm{I}}_0}{\sqrt[]{2}}$ cos $\varnothing$ =V_rmsI_rmscos $\varnothing$ ………. (2)

From eqn 1 ……But when cos $\varnothing$ < cos (2wt+$\mathrm{\varnothing )}$

P<0 power can be nagative of an AC source

From eqn 2……… P_av>0

cos $\varnothing$ =R/Z>0 average power can not be negative

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- When we are considering a point source of sound wave. The disturbance due to the source propagates in spherical symmetry that is in all directions. The formation of

wavefront is in accordance with Huygen's principle.

So, Huygen's principle is valid for longitudinal sound waves also.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- (b, d)

Explanation- this is only possible when rate of decay of 1 is almost double the rate of decay of other.so in this case initial decay of A must be twice of B. also  Initial rate of decay of B is same as the rate of decay of A at t = 2h and  λ_A < λ_B

Candidates who have passed their 10+2 in Science stream, preferably with subjects - Physics, Chemistry and Biology can opt for BSc Food Science and Nutrition. Although many universities/ colleges offer BSc food Science and Nutrition & related courses to PCM students as well.

No, the Consortium of Medical, Engineering, and Dental Colleges of Karnataka will release the COMEDK UGET result rankcard on June 7 on its official website. Candidates can find the direct link to access the COMEDK result 2025 here on our page.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- (a, b)

Explanation- fusion process are almost impossible at ordinary temperature because nuclei are positive charge and forces between them is of short range.

The college offers Certificate, PG Diploma, MBA and BBA course. Candidates must pass graduation with a 50% aggregate for all course admission excluding BBA. For BBA admission, candidates must pass Class 12 with a 50% aggregate. Students can check the table below to know course-wise eligibility:

This is a short answer type question as classified in NCERT Exemplar

(I_rms)a= $\frac{V_{rms}}{R}$ = $\frac{V}{R}$

(I_rms)b= $\frac{V_{rms}}{Z}$ = $\frac{V}{\sqrt[]{R^2+(X_L-X_C)2}}$

When $\left(Irms\right)a$ = (I_rms)b

Then R= $\sqrt[]{R^2+(X_L-X_C)2}$

XL=Xc resonance condition

As Z>R $\frac{\left(\mathrm{I}\mathrm{r}\mathrm{m}\mathrm{s}\right)\mathrm{a}}{\left(\mathrm{I}\mathrm{r}\mathrm{m}\mathrm{s}\right)\mathrm{b}}$ = $\frac{\sqrt[]{R^2+(X_L-X_C)2}}{R}$ = $\frac{Z}{R}$ >1

(I_rms)a > (I_rms)b

Clini Launch Research Institute offers Advanced Diploma in Clinical SAS as a 6 month programme. The Institute offers admission to the respective programme on the basis of merit. To apply for the admission process, candidates must meet the eligibility criteria and access the official website of the Institute to fill out the form. Furthermore, the Institute offers the respective course with a total tuition fee worth INR 80K.