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$tan\theta =\frac{3x}{18}=\frac{x}{6}........\left(i\right)$ and

$tan2\theta =\frac{10x}{8}=\frac{5x}{9}..........\left(ii\right)$

Solving (i) and (ii)  $\frac{2tan\theta }{1-ta{n}^2\theta }=\frac{5x}{9}wegetx=\sqrt[]{\frac{72}{5}}$  

Height of pole = 10x =  $12\sqrt[]{10}$

United Institute of Technology, Allahabad offers the flagship Bachelor of Technology (BTech) programme in a variety of specializations. The course is a popular programme for students seeking to build a career in Engineering. The total tuition fees for United Institute of Technology, Allahabad BTech is INR 2.4 L - 5.1 L. Students can also check out the various scholarship schemes offered by United Institute of Technology, Allahabad.

To apply for BSc at Ajeenkya DY Patil University Seamedu, visit the official portal at seamedu.com/apply-now. Register with your details, verify your email, and log in to complete the application form. After entering all required information, pay the application fee online and submit the form. This is the first step toward securing admission to the BSc programme.

In given circuit inductor behave as a simple wire so resultant circuit will be

R_ef = 2 + 1 = 3 $\Omega$  

V = IR

$l=\frac{30}{3}=10A$  

Yes, you can get admission in the BBA course offered at SCMC Pune with 75% in Class 12. Since the minimum aggregate required to apply for the course is 50%, (45% for those belonging to the SC/ ST categories), anyone with marks above that is eligible. However, fulfilling the basic eligibility requirements doesn't guarantee a seat at the institute. Students also need to clear the selection rounds as per the institute's guidelines. 

For the General AI category students, the NIFT Bhopal B.Des cutoff 2025 ranged between 1026 and 2690 during Round 3 admission. The cutoff ranks vary for different specialisations, rounds, and categories. So, if you are seeking admission based on the third cutoff list, yes, there is a chance of you getting a seat for B.Des at NIFT Bhopal with a cutoff rank of 2000. However, there is a chance that you might not get your desired specialisation. Refer to the table below to view what specialisations you can get with a cutoff rank of 2000. The cutoff data below is for the students belonging to the General AI quota. 

q = 18° Þ 2q + 3q = 90° Þ sin 3q = 1 – sin 2q Þ cos q Þ cosq (4 sin² q + 2sinq - 1) = 0

$?cos\theta \ne 0\therefore 4si{n}^2\theta +2sin\theta -1=0\Rightarrow cose{c}^{2}18°-2cosec18°-4=0$

? x² – 2x – 4 = 0

No, it's not possible to join Symbiosis Institute of Health Sciences without SNAP (Symbiosis National Aptitude Test) for the MBA programme. Symbiosis requires a valid SNAP score for admission to all its MBA programs, including those at SIHS. For other programmes SNAP score is not mandatory; students must meet the eligibility criteria set by the institute for the desired course. 

$l=\frac{V_{0}B\mathcal{l}}{R}=\frac{V_0\times 5\times 20\times 10^{-2}}{4+1}$         

  $2\times 10^{-3}=V_0\times 20\times 10^{-2}$

$V_0=\frac{2\times 10^{-3}}{20\times 10^{-2}}=\frac{2}{2}\times 10^{-2}=1\times 10^{-2}m/s$

V₀ = 1 cm/s

IIT Bombay offers BTech course, which is popular among students seeking to build career in Engineering. The course is offered in several specializations. BTech tuition fees is between Rs 8 L to Rs 10 L. Students can check about the scholarship schemes offered by IIT Bombay.

${\left|2\overrightarrow{a}+3\overrightarrow{b}\right|}^2={\left|3\overrightarrow{a}+\overrightarrow{b}\right|}^2\Rightarrow 4{\left|\overrightarrow{a}\right|}^2+9{\left|\overrightarrow{b}\right|}^2+12\overrightarrow{a}.\overrightarrow{b}=9{\left|\overrightarrow{a}\right|}^2+{\left|\overrightarrow{b}\right|}^2+6\overrightarrow{a}.\overrightarrow{b}$

$\Rightarrow -5{\left|\overrightarrow{a}\right|}^2+8{\left|\overrightarrow{b}\right|}^2+6\overrightarrow{a}.\overrightarrow{b}=0.........\left(i\right)$

$cos60°=\frac{\overrightarrow{a}.\overrightarrow{b}}{\left|\overrightarrow{a}\right|\left|\overrightarrow{b}\right|}=\frac{1}{2}\therefore \overrightarrow{a}.\overrightarrow{b}=4\left|\overrightarrow{b}\right|and\left|\overrightarrow{a}\right|=8$

from (i) we get $\left|\overrightarrow{b}\right|=5$

IIIT Hyderabad offers the flagship Bachelor of Technology (BTech) programme in a variety of specializations. The course is a popular programme for students seeking to build a career in Engineering. The total tuition fees for International Institute of Information Technology, Hyderabad BTech is INR 10 L - 18 L. Students can also check out the various scholarship schemes offered by IIIT Hyderabad.

IIT Jammu total tuition fee for the BTech course is INR 8 lakh. The total tuition fee for the M.Tech course is INR 80,000. The fee for the MSc course is INR 26,000. Expensive or not, depends on person to person. Those students who find the fee expensive must apply for the scholarships.

Following is the structure of the stops on this route:

Case I:

The official last date for BSc admission at Ajeenkya DY Patil University Seamedu has not been released by the institute. However, the official website mentions that applications are closing soon. This means students who are interested and haven't applied yet should do so as soon as possible to avoid missing out.

Yes, admissions for the BSc programme at Ajeenkya DY Patil University Seamedu are currently open. The admission process generally starts soon after the Class 12 results are declared, as these marks play a key role in meeting the eligibility requirements. Students are advised to keep an eye on the Institute's official website for the latest updates and important deadlines.

Following is the structure of the stops on this route:

Case I: