Ask & Answer

Ask & Answer: India's Largest Education Community

1000+ExpertsQuick ResponsesReliable Answers

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post

All Questions

New Question

11 months ago

physics ncert solutions class 11th Work, Energy, and Power

6.8 Answer carefully, with reasons:

(a) In an elastic collision of two billiard balls, is the total kinetic energy conserved during the short time of collision of the balls (i.e. when they are in contact)?

(b) Is the total linear momentum conserved during the short time of an elastic collision of two balls?

(c) What are the answers to (a) and (b) for an inelastic collision?

(d) If the potential energy of two billiard balls depends only on the separation distance between their centers, is the collision elastic or inelastic?

(Note, we are talking here of potential energy corresponding to the force during colli

...more

0 Follower 3 Views

Payal Gupta

Contributor-Level 10

6.8 (a) In elastic collision, the initial and final kinetic energy is equal. When the two balls collide, there is no conservation of kinetic energy; it gets converted into potential energy.

(b) The total linear momentum is conserved in an elastic collision.

(c) In case of inelastic condition in case (a), there will be loss of kinetic energy but in case of (b), the total linear momentum will be conserved in inelastic collision also.

(d) It is an elastic collision as the forces involves are conservative forces.

0 0

New Question

11 months ago

Study Abroad

What is the percentage of 300 marks out of 600?

0 Follower 10 Views

Priya Garg

Contributor-Level 10

The percentage of marks can be calculated by applying the formula - (Obtained Marks/Total Marks) x 100

The percentage of marks of 300 marks obtained out of 600 marks is - (3.

0 0

New Question

11 months ago

Humanities & Social Sciences G H Raisoni University, Saikheda

Can I take admission in the BA course at G H Raisoni University, Saikheda with 45% in the Science steam?

0 Follower 2 Views

Anushka Bidhi

Contributor-Level 10

The students from any stream are eligible to apply for admission in the BA course at G H Raisoni University, Saikheda. According to the eligibility criteria the students are required pass class 12 exam. However for opting the Liberal Arts specialisation, the students need at least 50% minimum aggregate in their class 12 exams.

0 0

New Question

11 months ago

physics ncert solutions class 11th Work, Energy, and Power

6.7 State if each of the following statements is true or false. Give reasons for your answer.

(a) In an elastic collision of two bodies, the momentum and energy of each body is conserved.

(b) Total energy of a system is always conserved, no matter what internal and external forces on the body are present.

(c) Work done in the motion of a body over a closed loop is zero for every force in nature.

(d) In an inelastic collision, the final kinetic energy is always less than the initial kinetic energy of the system

0 Follower 11 Views

Payal Gupta

Contributor-Level 10

6.7 (a) False. The total momentum and energy is conserved, not the individual.

(b) False. External forces can change the energy of a body.

(c) False. Only work done by conservative force over a closed loop is zero.

(d) True. In an inelastic collision, the final velocity reduces, resulting in loss of the initial kinetic energy.

0 0

New Question

11 months ago

Management Development Institute of Singapore (MDIS) Study Abroad

How many alumni does MDIS Singapore have?

0 Follower 2 Views

Pallavi Sharma

Contributor-Level 10

Management Development Institute of Singapore is one of the best universities for higher education in Singapore. MDIS Singapore has a rich alumni network all over the world. Some notable alumni include Gibran Rakabuming Raka, Jayley Woo, Shawn Thia, Hayley Woo, Ivy Le, Ris Low, etc. MDIS Singapore alumni work in top companies such as HSBC, UOB, Singtel, DBS Bank, Singapore Airlines, Deriv, and more. Furthermore, the graduates work in top sectors such as:

Business Development
Operations
Sales
Marketing
Information Technology

0 0

New Question

11 months ago

physics ncert solutions class 11th Work, Energy, and Power

6.6 Underline the correct alternative:

(a) When a conservative force does positive work on a body, the potential energy of the body increases/decreases/remains unaltered.

(b) Work done by a body against friction always results in a loss of its kinetic/potential energy.

(c) The rate of change of total momentum of a many-particle system is proportional to the external force/sum of the internal forces on the system.

(d) In an inelastic collision of two bodies, the quantities which do not change after the collision are the total kinetic energy/total linear momentum/total energy of the system of two bodies.

0 Follower 125 Views

Payal Gupta

Contributor-Level 10

6.6 (a) When a conservative force does positive work on a body, the body gets displaced in the direction of the force, it moves towards the centre of the force, thus resulting in decrease of potential energy.

(b) When the work done by a body against friction, it reduces its velocity. Hence kinetic energy decreases.

(c) The momentum cannot be changed by the internal forces on the system; the change of momentum is proportional to the external force.

(d) The total linear momentum does not change in an elastic collision.

0 0

New Question

11 months ago

CII Institute of Hospitality - Taj Hotels, Kolkata Diploma

How can I get a seat for Diploma programme at CII Institute of Hospitality - Taj Hotels, Kolkata?

0 Follower 1 View

Pallavi Sharma

Contributor-Level 7

To get a seat to Diploma programmes at CII Institute of Hospitality - Taj Hotels, Kolkata, students must go through two levels of selection criteria. Find the details below:

Eligibility: Pass Class 12 with minimum 50% aggregate
Selection Criteria: Qualify CII Aptitude Test + Industry Panel Viva

0 0

New Question

11 months ago

MVN University Colleges in Faridabad

Can a student with 45% in Class 12 apply for MVN University BSc?

0 Follower 1 View

Himanshu Singh

Contributor-Level 10

No, students with 45% in Class 12 are not eligible to apply for the BSc programme at MVN University. To meet the eligibility criteria for admission, students must have passed Class 12 or an equivalent examination with at least 45% aggregate marks from a recognised board. This requirement is strictly enforced, ensuring that only students who meet the academic standards are considered for admission.

0 0

New Question

11 months ago

physics ncert solutions class 11th Work, Energy, and Power

6.5 Answer the following :

(a) The casing of a rocket in flight burns up due to friction. At whose expense is the heat

energy required for burning obtained? The rocket or the atmosphere?

(b) Comets move around the sun in highly elliptical orbits. The gravitational force on the comet due to the sun is not normal to the comet’s velocity in general. Yet the work done by the gravitational force over every complete orbit of the comet is zero. Why ?

(c) An artificial satellite orbiting the earth in very thin atmosphere loses its energy gradually due to dissipation against atmospheric resistance, however small. Why then do

...more

0 Follower 5 Views

Payal Gupta

Contributor-Level 10

6.5 (a) As per the law of conservation of energy,

Total energy = potential energy + kinetic energy

= mgh + $\frac{1}{2}$ mv2

When the casing burns, mass reduces, resulting in drop of energy. Hence the energy for burning of casing is drawn from the rocket.

(b) The force due to gravity is a conservative force. The work done on a closed path for a conservative force is zero. Hence, for every complete orbit of the comet, the work done by the gravitational force is zero.

(c) The potential energy of the satellite revolving the Earth decreases as it approaches the Earth and since the system's total energy should remain constant, the k

...more

6.5 (a) As per the law of conservation of energy,

Total energy = potential energy + kinetic energy

= mgh + $\frac{1}{2}$ mv2

When the casing burns, mass reduces, resulting in drop of energy. Hence the energy for burning of casing is drawn from the rocket.

(c) The potential energy of the satellite revolving the Earth decreases as it approaches the Earth and since the system's total energy should remain constant, the kinetic energy increases. Hence the satellite velocity increases when it approaches the Earth.

(d)

(i) Give, m = 15 kg, displacement, s = 4m

From the relation, work done, W = F $* s * \cos ? ?$ where $?$ is the angle between the force and displacement. Here F = mg, hence, W = mgs $\cos ? ?$ = 15 $* 9.8 * 4 * \cos ? 90 °$ = 0

(ii) Mass = 15 kg, s = 4 m, the applied force direction is same as the direction of the displacement, $? = 0$ . Hence W = 15 $* 9.8 * 4 * \cos ? 0 °$ = 588 J

less

0 0

New Question

11 months ago

Humanities & Social Sciences G H Raisoni University, Saikheda

Can I get direct admission in the BA course at G H Raisoni University, Saikheda?

0 Follower

Anushka Bidhi

Contributor-Level 10

No, there is no provision of direct admission as per the official website. The admission into the BA course atthe G H Raisoni University, Saikheda is subject to the fulfillment of the set eligibility criteria. Th students need to successfully pass the class 12 exams.

0 0

New Question

11 months ago

KIET University Colleges in Ghaziabad

What is the procedure and cutoff for direct admission through the 10+2 CBSE board at KIET Group of Institutions?

0 Follower 16 Views

New Question

11 months ago

B.A Mass Communication & Media

When can I download the admit card for Bachelor of Arts (Journalism & Mass Communication)?

0 Follower 9 Views

Ashmit Saini

Beginner-Level 5

Generally, you are able to access the admit card for Bachelor of Arts (Journalism & Mass Communication) about 1 to 2 weeks before the entrance exam, if the admission process is through CUET-UG or university-specific admission test.

Check the official CUET or university website frequently. The admit card will be uploaded to your dashboard as soon as it is available.

0 0

New Question

11 months ago

physics ncert solutions class 11th Work, Energy, and Power

6.4 The potential energy function for a particle executing linear simple harmonic motion is given by V(x) =kx²/2, where k is the force constant of the oscillator. For k = 0.5 N m^-1, the graph of V(x) versus x is shown in Fig. 6.12. Show that a particle of total energy 1 J moving under this potential must ‘turn back’ when it reaches x = ± 2 m.

0 Follower 4 Views

Payal Gupta

Contributor-Level 10

6.4 Given, particle energy, E = 1 J,

Force constant, k = 0.5 N/m

Kinetic energy, KE = $\frac{1}{2}$ mv2

From the equation, total energy, E = KE +PE, we get

1 = (1/2)mv2 + (1/2) kx2

when it turns back, v becomes 0

1 = (1/2) $* 0.5 * x^{2}$ , x = ± 2

0 0

New Question

11 months ago

MVN University Colleges in Faridabad

Are there any specialisations offered in the MVN University BSc programme?

0 Follower

Himanshu Singh

Contributor-Level 10

Yes, MVN University offers several specialisations in the BSc programme, including:

BSc in Medical Lab Technology
BSc in Biotechnology
BSc in Cardiovascular Technology (CVT)

0 0

New Question

11 months ago

physics ncert solutions class 11th NCERT Physics 11th

0 Follower 4 Views

New Question

11 months ago

Business Management Studies MBA/PGDM

What is the course fee for two years MBA in Sri Dev Suman Uttarakhand University?

0 Follower

Manori Karan

Contributor-Level 10

Sri Dev Suman Uttarakhand University offers MBA course via its affiliated institute Shivalik Institute of Professional Studies and others. The course fees for two-year MBA ranges from INR 70,000 to INR 3.3 lakh. The course might vary across the affiliated colleges and is inclusive of multiple other fee components. Candidates must pay the course fee to finalise their admission in the MBA course. The MBA course admission is subject to a valid score in the last qualifying exam.

NOTE: This information is sourced from the official website/ sanctioning body and is subject to change.

0 0

New Question

11 months ago

CII Institute of Hospitality - Taj Hotels, Kolkata

Are admissions open at CII Institute of Hospitality - Taj Hotels, Kolkata?

0 Follower

Manpreet Dixit

Contributor-Level 7

CII Institute of Hospitality - Taj Hotels, Kolkata admissions are currently open. Students can apply on the college's official website for their desired programme. The application window is open for current year's admissions.

0 0

New Question

11 months ago

physics ncert solutions class 11th Work, Energy, and Power

6.3 Given in Fig. 6.11 are examples of some potential energy functions in one dimension. The total energy of the particle is indicated by a cross on the ordinate axis. In each case, specify the regions, if any, in which the particle cannot be found for the given energy. Also, indicate the minimum total energy the particle must have in each case. Think of simple physical contexts for which these potential energy shapes are relevant.

0 Follower 216 Views

Payal Gupta

Contributor-Level 10

6.3 We know the total energy E is given by E = Kinetic energy (KE) + Potential energy (PE)

(a) In figure (a), we have at x=0, the potential energy is zero. So KE is positive. At x>a, the potential energy has a value greater than E, so the KE becomes 0. Thus the particle will not exist in the region x>a. Minimum total energy is zero.

(b) For the entire x-axis, PE >E, the KE of the object would be negative. Thus the particle will not exist in this region.

(c) In x=0 to x=a and x>b, PE is greater than E, so he KE has to be negative. The object cannot exist in this region.

(d) For x=-b/2 to x =-a/2 and x=a/2 to x=b/2, KE

...more

0 0

New Question

11 months ago

MVN University Colleges in Faridabad

What is the fee for BSc at MVN University?

0 Follower

Himanshu Singh

Contributor-Level 10

The tuition fee for the BSc at MVN University ranges from INR 1.5 Lacs to 2.2 Lakh. This fee may also include additional charges such as the application fee, refundable security deposit, hostel accommodation, and mess charges. Please note that the fee structure is subject to change and may vary based on university updates.

0 0

New Question

11 months ago

physics ncert solutions class 11th Work, Energy, and Power

6.2 A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1.

Compute the

(a) Work done by the applied force in 10 s

(b) Work done by friction in 10 s

(c) Work done by the net force on the body in 10 s

(d) Change in kinetic energy of the body in 10 s, and interpret your results

0 Follower 5 Views

Payal Gupta

Contributor-Level 10

6.2 Given, mass of the body, m = 2 kg

Horizontal force applied, F = 7 N

Coefficient of friction, $?$ = 0.1

Acceleration, a = F/m = 7/2 = 3.5 m/s2

Frictional force, f = $? R = ? m g =$ 0.1 $* 2 * 9.807 =$ 1.96 N

Retardation produced by the frictional force, $a_{r}$ = -f/m = -1.96 /2 = 0.98 m/s2

The net acceleration by which the body moves forward

$a_{n}$ = a - $a_{r}$ = 3.5 – 0.98 = 2.52 m/s2

Distance moved by the body in 10 s is given by

s = ut + (1/2) $a_{n} t^{2}$ = 0 $* 10 + (\frac{1}{2}) * 2.52 * 10^{2}$ = 126 m

(a) Work done in 10 s is given by

W = Force $* d i s p l a c e m e n t = 7 * 126 = 882 J$

(b) Work done by friction in 10 s is given by

W = -f $* s = - 1.96 * 126 =$ - 247J

(c) Work done by the net force

...more

6.2 Given, mass of the body, m = 2 kg

Horizontal force applied, F = 7 N

Coefficient of friction, $?$ = 0.1

Acceleration, a = F/m = 7/2 = 3.5 m/s2

Frictional force, f = $? R = ? m g =$ 0.1 $* 2 * 9.807 =$ 1.96 N

Retardation produced by the frictional force, $a_{r}$ = -f/m = -1.96 /2 = 0.98 m/s2

The net acceleration by which the body moves forward

$a_{n}$ = a - $a_{r}$ = 3.5 – 0.98 = 2.52 m/s2

Distance moved by the body in 10 s is given by

s = ut + (1/2) $a_{n} t^{2}$ = 0 $* 10 + (\frac{1}{2}) * 2.52 * 10^{2}$ = 126 m

(a) Work done in 10 s is given by

W = Force $* d i s p l a c e m e n t = 7 * 126 = 882 J$

(b) Work done by friction in 10 s is given by

W = -f $* s = - 1.96 * 126 =$ - 247J

(c) Work done by the net force,

W = (F-f) $* s$ = (7 – 1.96 ) $* 126$ = 635 J

(d) Kinetic energy is given by the equation

KE = (1/2)m $v^{2}$ where v is the final velocity

From the equation v = u + at we get after 10 s, v = 0 + 2.52 $*$ 10 = 25.2 m/s

Final kinetic energy = (1/2) $* 2 * {25.2}^{2}$ = 635 J

Initial kinetic energy = (1/2) $* 2 * 0^{2}$ = 0

Change in kinetic energy = 635 – 0 = 635 J

Hence the work done by the net force = change in kinetic energy

less

0 0

Ask & Answer
Panel of Experts

View Experts Panel

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Ask & Answer: India's Largest Education Community

Need guidance on career and education? Ask our experts

Your Question

All Questions

Share Your College Life Experience