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Cheran College of Physiotherapy offers BPT and MPT courses. The selection criteria is based on students merit. The application process at Cheran College of Physiotherapy conducted online. To secure a seat, students can check the following steps presented below:

1. Visit the official website and complete the online application process. 
2. Ensure eligibility and selection criteria for the UG and PG programme.
3. The selection criteria is based on merit.
4. Upon selected, pay the specified fee to confirm and secure your seat.

You'll need both original and clear scanned copies of:

• AP EAMCET 2025 Hall Ticket & Rank Card
• Class 10 (SSC) Certificate (DOB proof)
• Class 12 (Inter) Marks Memo & Study Certificates from Class 6–12
• Transfer Certificate (TC)
• Caste Certificate (BC/SC/ST/EWS if applicable)
• Income Certificate / White Ration Card (for fee reimbursement)
• Local Status Certificate (for migrants from Telangana, if applicable)
• Category-specific certificates (PH, NCC, CAP, Sports, etc.) 

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Let\left(x,y\right)bean\mathrm{ypoint}\\ Accordingtothequestion,wehave\\ \sqrt[]{{\left(x-4\right)}^2+{\left(y-0\right)}^2}-\sqrt[]{{\left(x+4\right)}^2+{\left(y-0\right)}^2}=2\\ \Rightarrow \sqrt[]{x^2+16-8x+y^2}-\sqrt[]{x^2+16+8x+y^2}=2\\ Putting{x}^2+y^2+16=z\dots \left(i\right)\\ \Rightarrow \sqrt[]{z-8x}-\sqrt[]{z+8x}=2\\ Squaringbothsides,wehave\\ \Rightarrow z-8x+z+8x-2\sqrt[]{\left(z-8x\right)\left(z+8x\right)}=4\\ \Rightarrow 2z-2\sqrt[]{z^2-64x^2}=4\\ \Rightarrow z-\sqrt[]{z^2-64x^2}=2\\ \Rightarrow \left(z-2\right)=\sqrt[]{z^2-64x^2}\\ Againsquaringbothsides,weget\\ \Rightarrow z^2+4-4z=z^2-64x^2\\ \Rightarrow 4-4z+64x^2=0\\ Puttingthevalueofz,wehave\\ \Rightarrow 4-4\left(x^2+y^2+16\right)+64x^2=0\\ \Rightarrow 4-4x^2-4y^2-64+64x^2=0\\ \Rightarrow 60x^2-4y^2-60=0\\ \Rightarrow 60x^2-4y^2=60\\ \Rightarrow \frac{60x^2}{60}-\frac{4y^2}{60}=1\\ \Rightarrow \frac{x^2}{1}-\frac{y^2}{15}=1\\ Whichrepresentahperbola.Henceproved.\end{array}$

There are about 80+ MBBS colleges in Maharashtra offer an UG courses. Candidates can see below for the best colleges with tuition fees -

Source: Official site and may vary.

Following are the steps involved in Andhra Pradesh EAMCET counselling:

• Online Registration & Fee Payment
• Document Upload / Online or at Help Centres
• Web Options (Choice Filling)
• Seat Allotment
• Self Reporting Online + Physical Reporting at College
• Start of Academic Term 

Cheran College of Physiotherapy admissions are currently open for all courses. Candidates are selected for courses based on merit for BPT and MPT courses. Aspirants can apply online. Interested candidates meeting the eligibility criteria can fill out the form. 

CMJ University applications are currently open. Candidates can download the application form from the university's website. The admissions are held twice in a year. The spring session commences in January and fall session in July. Aspirants have to fill out the application form in their own writing in English for the preferred course.

Yes, the CUET UG 2025 results were declared on July 4, 2025. Candidates seeking BTech admission at RNB Global University and who appeared for CUET UG can now check their scores. RNB Global University will consider valid CUET UG results along with other eligibility criteria for offering seats in the BTech programme.

Yes, BTech admissions at RNB Global University for the 2025 academic session are currently open. Interested candidates can apply through the university's official website. RNB Global University invites applications based on eligibility and performance in entrance exams like JEE Main and CUET UG, followed by further steps outlined in the admission process.

Cheran College of Physiotherapy admissions 2026 are open online. The last date is not available on the website. Since the admission is open, candidates can apply for BPT and MPT course. To get admission to the Cheran College of Physiotherapy, candidates must meet the eligibility set by the college. The application process at Cheran College of Physiotherapy is conducted online.

RAJUVAS applications begins with the opening of NEET registration. Candidates are required to pass NEET for admission in the BVSc programme. The applications for NEET are released in February every year and continues till March. The exam is usually held in May every year. 

The course duration for the Indian School of Business Management and Administration, Chennai Certificate specialisations are as follows: 

• Chartered Certified Accountant: Two years
• Chartered Financial Manager: Two years
• English Edge: Three months
• Advanced Certificate in Management: Six months

Candidates can visit the official website to learn more about the programmes. 
 

The important key dates for Andhra Pradesh EAMCET 2025 counselling are as follows:

• Registration & Fee Payment: July 2026
• Certificate Upload & Verification: July 2026
• Web Options Entry: July 2026
• Option Editing: July 2026
• Seat Allotment Result: July 2026
• Self-Reporting & College Reporting: July 2026
• Commencement of Classes: August 2026

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Let\left(x,y\right)beany\\ Accordingtothequestion,wehave\\ \sqrt[]{{\left(x-0\right)}^2+{\left(y-4\right)}^2}=\frac{2}{3}\left|\frac{y-9}{1}\right|\\ Squaringbothsides,wehave\\ \Rightarrow x^2+{\left(y-4\right)}^2=\frac{4}{9}\left(y^2+81-18y\right)\\ \Rightarrow 9x^2+9{\left(y-4\right)}^2=4y^2+324-72y\\ \Rightarrow 9x^2+9y^2+144-72y=4y^2+324-72y\\ \Rightarrow 9x^2+5y^2+144-324=0\\ \Rightarrow 9x^2+5y^2-180=0\\ Hence,therequiredequationis9x^2+5y^2-180=0.\end{array}$

To make sure your Ph.D. research is authentic, you should, first of all, choose a clear research topic along with an identified research gap on which you would like to work. Then you should start with literature reviews where you read a plethora of books, articles, and journals related to the chosen research topic, select your target audience, and collect data through online surveys and group discussions. Regularly assess your work and take feedback from your peers and supervisor to make sure you successfully complete your PhD thesis while ensuring sheer originality.

The certificate specialisations offered by Indian School of Business Management and Administration, Chennai are as follows: 

Yes, pursuing a PhD degree can often turn out to be a journey of solitude owing to a culture of long, silent, and independent research, which often makes mutual conversations difficult. You often find yourself sitting in libraries for hours and sipping coffee while reading various books, articles, and journals to come up with a strong thesis work. There is less social interaction, and time management may seem difficult, but with your persistent efforts and passion for the field, you can overcome this feeling of loneliness and reach your final goal of PhD completion.

The tuition fee for the BTech programme at RNB Global University ranges between INR 2.3 Lacs and INR 2.5 Lacs for the complete course. In addition to tuition, RNB Global University's fee structure may include other charges such as refundable security deposits. Candidates should verify the latest updates on the official website before applying.

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Let\left(x,y\right)beany\\ Givenare\left(3,0\right)and\left(9,0\right)\\ Accordingtothequestion,wehave\\ \sqrt[]{{\left(x-3\right)}^2+{\left(y-0\right)}^2}+\sqrt[]{{\left(x-9\right)}^2+{\left(y-0\right)}^2}=12\\ \Rightarrow \sqrt[]{x^2+9-6x+y^2}+\sqrt[]{x^2+81-18x+y^2}=12\\ Putting{x}^2+9-6x+y^2=k\\ \Rightarrow \sqrt[]{k}+\sqrt[]{72-12x+k}=12\\ \Rightarrow \sqrt[]{72-12x+k}=12-\sqrt[]{k}\\ Squaringbothsides,wehave\\ \Rightarrow 72-12x+k=144+k-24\sqrt[]{k}\\ \Rightarrow 24\sqrt[]{k}=144-72+12x\\ \Rightarrow 24\sqrt[]{k}=72+12x\\ \Rightarrow 2\sqrt[]{k}=6+x\\ Againsquaringbothsides,weget\\ \Rightarrow 4k=36+x^2+12x\\ Puttingthevalueofk,wehave\\ 4\left(x^2+9-6x+y^2\right)=36+x^2+12x\\ \Rightarrow 4x^2+36-24x+4y^2=36+x^2+12x\\ \Rightarrow 3x^2+4y^2-36x=0\\ Hence,therequiredequationis3x^2+4y^2-36x=0.\end{array}$