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To be eligible for the BTech course at RNB Global University, candidates must pass Class 12 from a recognised board with Physics and Mathematics as compulsory subjects, along with one of Chemistry, Biotechnology, Computer Science, or Biology. RNB Global University requires a minimum of 50% aggregate marks (45% for SC/ST candidates) for admission.

The TS TET qualifying marks for SC and ST categories are 40 per cent. Candidates belonging to Scheduled Caste (SC) or Scheduled Tribe (ST) category need to obtain more than 60 marks out of total 150 to clear the exam and get eligible for the TS TET certificate. These qualifying marks or passing marks have been fixed by the Government of Telangana. 

RNB Global University offers BTech in various specialisations such as Computer Science Engineering (CSE), CSE with AI & Machine Learning, Cyber Security & Forensics, Data Science & Analytics, and Civil Engineering. These specialisations at RNB Global University provide students with the opportunity to align their technical education with modern industry trends and growing technology domains.

BTech course at RNB Global University is a full-time undergraduate programme with a duration of four years, divided into eight semesters. Students enrolled in RNB Global University BTech programme undergo a structured curriculum designed to build a strong foundation in engineering fundamentals along with exposure to their chosen specialisation throughout the course duration.

Yes, Brainware University admissions are currently open for BTech, and various other courses. Students can visit the official website to learn more and apply online. Brainware University Kolkata is ranked 1 by IIRF 2024 under the Technical Private University in West Bengal category.The university is also recognised as the 1st multidisciplinary university in West Bengal and among the top 100 universities in India by the Federation for World Academics (FWA).

There are about 40+ Graphic Design colleges in Mumbai (All) that offer certificate courses to their students. Some of them are mentioned below along with their tuition fees:

Disclaimer: This information is sourced from official website/ counselling body and may vary.

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}\left(i\right)Giventhatdirectrix=0andfocus\left(6,0\right)\\ \therefore Theequationoftheparabolais\\ {\left(x-6\right)}^2+y^2=x^2\\ \Rightarrow x^2+36-12x+y^2=x^2\\ \Rightarrow y^2-12x+36=0\\ Hence,therequiredequationis{y}^2-12x+36=0\\ \left(ii\right)Giventhatvertexat\left(0,4\right)andfocusat\left(0,2\right).\\ So,equationofdirectrixisy-6=0\\ Accordingtothedefinitionoftheparabola\\ PF=PM\\ \sqrt[]{{\left(x-0\right)}^2+{\left(y-2\right)}^2}=\left|y-6\right|\\ \Rightarrow \sqrt[]{x^2+y^2+4-4y}=\left|y-6\right|\\ Squaringbothsides,weget\\ x^2+y^2+4-4y=y^2+36-12y\\ \Rightarrow x^2+4-4y=36-12y\\ \Rightarrow x^2+8y-32=0\\ \Rightarrow x^2=32-8y\\ Hence,therequiredequationis{x}^2=32-8y\\ \left(iii\right)Giventhatfocusat\left(-1,-2\right)anddirectrixx-2y+3=0\\ Let\left(x,y\right)beanyontheparabola.\\ Accordingtothedefinitionoftheparabola\\ PF=PM\\ \sqrt[]{{\left(x+1\right)}^2+{\left(y+2\right)}^2}=\left|\frac{x-2y+3}{\sqrt[]{{\left(1\right)}^2+{\left(-2\right)}^2}}\right|\\ \Rightarrow \sqrt[]{x^2+1+2x+y^2+4+4y}=\left|\frac{x-2y+3}{\sqrt[]{5}}\right|\\ Squaringbothsides,weget\\ x^2+1+2x+y^2+4+4y=\frac{x^2+4y^2+9-4xy-12y+6x}{5}\\ \Rightarrow 5x^2+5+10x+5y^2+20+20y=x^2+4y^2+9-4xy-12y+6x\\ \Rightarrow 4x^2+y^2+4xy+4x+32y+16=0\\ Hence,therequiredequationis4x^2+y^2+4xy+4x+32y+16=0.\end{array}$

Academic writing is the driving force for success in PhD courses as it is key factor by which doctorate scholars can actually contribute something authentic to the established pool of academic knowledge through dissertations and scholarly publications. It is important to establish a strong publication record via excellent academic writing to get hold of academic positions at universities and research career advancement in general. 

The TS TET qualifying marks for BC category candidates are 50 per cent. Candidates belonging to Backward Classes (BC) category need to obtain more than 75 marks out of total 150 to clear the exam and get eligible for the TS TET certificate. These qualifying marks or passing marks have been fixed by the Government of Telangana. 

The selection criteria for the courses at Indian School of Business Management and Administration, Chennai are merit-based for the majority of the programmes. However the institute accepts Karnataka PGCET scores for admission to the MBA programme as well. Candidates are required to pay the course fee and secure their seat. 

Well, yes. When we talk about passion and grades, passion definitely wins the race because pursuing a PhD requires a long-term commitment that needs constant effort and dedication, which can only be driven by passion. While good academic grades are important for PhD admission, passion is what really leads to the culmination of the intense PhD research work and intellectual growth.

Yes, BTech cadets in International Maritime Institute are also sponsored by best shipping companies. Depending on the parameters, they are evaluated throughout their course and deserving candidates are recommended to specific selection processes of the company also. 

Cut-off: For General category, the CUET score cut-off is usually around 520–530 marks. For reserved categories, it can be a bit lower.

Placements: The course has decent placements mainly in hospitals and cancer treatment centers. Average starting salaries are around INR 2–4 Lacs per year, and higher packages are possible in private hospitals or with experience.

At International Maritime Institute students are given a pre-screening test followed by an interview after which details of their profiles are forwarded to the shipping companies. The companies would then shortlist a candidate who would have to pass through his own selection procedure, exams and medical check-up. The candidates who pass will get a sponsorship letter. This ensures that they are trained at sea and give formal access to IMI.

A PhD programme is no cakewalk and requires you to have a strong and resilient mindset coupled with curiosity and passion for the chosen field. Walking down the PhD academic lane necessitates a strong work ethic, positive attitude, setback embracement, and persistence. You should look at challenges as opportunities for growth and improvement and stay focused to achieve your goals.

Asian Law College Noida admissions 2025-26 are currently open for BA LLB, and other courses. Students interested in applying at the institute can visit the official website and apply online. Asian Law College is affiliated with the Bar Council of India (BCI), and offers various Diplomas/Certifications in Cyber Law, IPR, Media Law and Personality Development.

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lettheequationofthecirclebe\\ {\left(x-h\right)}^2+{\left(y-k\right)}^2=r^2\\ Ifitpassesthrough\left(7,3\right)then\\ {\left(7-h\right)}^2+{\left(3-k\right)}^2={\left(3\right)}^2\left[?r=3\right]\\ \Rightarrow 49+h^2-14h+9+k^2-6k=9\\ \Rightarrow h^2+k^2-14h-6k+49=0\dots \left(i\right)\\ Ifcentre\left(h,k\right)liesontheliney=x-1then\\ k=h-1\dots \left(ii\right)\\ Puttingthevalueofkineqn.\left(i\right)weget\\ h^2+{\left(h-1\right)}^2-14h-6\left(h-1\right)+49=0\\ \Rightarrow h^2+h^2+1-2h-14h-6h+6+49=0\\ \Rightarrow 2h^2-22h+56=0\\ \Rightarrow 2\left(h^2-11h+28\right)=0\\ \Rightarrow h^2-11h+28=0\\ \Rightarrow h^2-7h-4h+28=0\\ \Rightarrow h\left(h-7\right)-4\left(h-7\right)=0\\ \Rightarrow \left(h-7\right)\left(h-4\right)=0\Rightarrow h=7,4\\ Fromeqn.\left(ii\right)wegetk=4-1=3andk=7-1=6.\\ So,thecentresare\left(4,3\right)and\left(7,6\right).\\ Equationofthecircleis\\ Takingcentre\left(4,3\right)\\ {\left(x-4\right)}^2+{\left(y-3\right)}^2=9\\ \Rightarrow x^2+16-8x+y^2+9-6y=9\\ \Rightarrow x^2+y^2-8x-6y+16=0\\ Takingcentre\left(7,6\right)\\ {\left(x-7\right)}^2+{\left(y-6\right)}^2=9\\ \Rightarrow x^2+49-14x+y^2+36-12y=9\\ \Rightarrow x^2+y^2-14x-12y+76=0\\ Hence,therequiredequationsare\\ x^2+y^2-8x-6y+16=0\\ and{x}^2+y^2-14x-12y+76=0\end{array}$

The steps to fill out the application form for Indian School of Business Management and Administration, Chennai are as follows:

Step 1: Visit the official website of the institute. 

Step 2: Check the eligibility and selection criteria for the course. 

Step 3: Fill out the form with accurate details and upload required documents. 

The TS TET result 2026 will be released soon on the official website - tgtet.aptonline.in/tgtet/. Candidates will get the direct TS TET results  link here.