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Gandhi Engineering College is known for its excellent placement record. Check out the tabulated data given below to know more about Gandhi Engineering College placement in 2024:

NOTE: The above data is obtained from the NIRF report 2025.

Hall ticket for the UK 12th board exam is issued by the Uttarakhand Board to which you are enrolled via your school. So your school cannot deny you the admit card even if you have failed to pass in their pre-boards exam. If they still goes on to deny you the hall ticket you can straight away write it to board asking them to issue your UK 12th hall ticket in duplicate as your school has failed to give you.

This is a short answer type question as classified in NCERT Exemplar

Weight of the adult w= mg =600N

Height of each step = h = 0.25m

Total distance travelled = 6km =6000m

Total number of steps = 6000/1= 6000

Total energy utilised in jogging = n $\times$ mgh

= 6000 $\times$ 600 $\times$ 0.25J

= 9 $\times {10}^5$ J

Since 10% of intake energy is utilised in jogging

So total energy intake = 10

Yes, the Listening and Speaking sections are same for both Academic and General Training. Only Reading and Writing are different.

Yes, students from the Reserved Category in Maharashtra State can apply for the BA course at Faculty of Liberal Arts, MIT WPU with 45% marks in Class 12, provided they meet the subject requirements. For general category students, the minimum eligibility is 50% aggregate marks in Class 12 with English as a subject.

This is a short answer type question as classified in NCERT Exemplar

Mass of the system = 50000kg

Speed of the system v= 36km/h= 10m/s

Compression of the spring x= 1m

KE of the system = 1/2mv²

= ½ (50000) (10)²

= 25000 (100)J= 2.5 $\times {10}^{6}J$

Since 90 % of KE is lost due to the friction so energy transferred is

E= 1/2kx²= 10% of total KE of the system

= $\frac{10}{100}\times 2.5\times {10}^{6}J$ 0r K = $\frac{2\times 2.5\times {10}^6}{10}=5\times {10}^{5}N/m$

The IELTS exam has 4 section, Listening, Reading, Writing, and Speaking. Everyone gives all 4 sections. But Reading and Writing are a bit different in Academic and General Training test.

This is a short answer type question as classified in NCERT Exemplar

Mass of drop m = 3 $\times {10}^{-5}kg$

Terminal velocity = 9m/s

Height = 100cm=1m

Density of water  = 10³kg/m³

Area of the surface = 1m²

Volume of the water due to rain V = area $\times$ height

= 1 (1)= 1m³

Mas $\frac{1}{2}\times {10}^3\times 9^2=40.5\times {10}^{3}J$ s of water due to rain M= volume (density)

= V ( $\rho$ )= 10³kg

Energy transferred to the surface = 1/2mv²

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety=\frac{8^x}{x^8}\\ Takinglogonbothsides,weget,logy=log\frac{8^x}{x^8}\\ \Rightarrow logy=log{8}^x-log{x}^8\Rightarrow logy=xlog8-8logx\\ Differentiatingbothsidesw.r.t.x\\ \Rightarrow \frac{1}{y}.\frac{dy}{dx}=log8.1-\frac{8}{x}\\ \Rightarrow \frac{1}{y}.\frac{dy}{dx}=y\left[log8-\frac{8}{x}\right]\\ Hence,\frac{dy}{dx}=\frac{8^x}{x^8}\left[log8-\frac{8}{x}\right]\end{array}$

BA Political Science offers a variety of electives across semesters V and VI. These electives include African Studies, Central Asia Studies, and Indo-Pacific Studies. Students can also choose Defence and National Security Studies, International Security Studies, and International Law and Organisation. In addition, the programme offers Peace and Conflict Studies, Theory and Practice of Diplomacy, and Nuclear Deterrence. Other options include Public Policy Studies, International Political Economy, and Electoral Studies.

Dubai is a rapidly developing global educational spot with competitive courses, advanced facilities, and affordable tuition fees. It has a mid-range cost of living, high safety and increasing post-study work opportunities. Due to its connections with varied industries, global financial hub, and a quick growing economy, Dubai is becoming a famous education destination for Indian students. This also because Dubai has a culturally familiar environment closer to India.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety=2^{co{s}^{2}x}\\ Takinglogonbothsides,weget\\ logy=log{2}^{co{s}^{2}x}\\ Differentiatingbothsidesw.r.t.x\\ \Rightarrow \frac{1}{y}.\frac{dy}{dx}=log2.\frac{d}{dx}co{s}^{2}x\\ \Rightarrow \frac{1}{y}.\frac{dy}{dx}=log2.\left[2cosx.\frac{d}{dx}cosx\right]\\ \Rightarrow \frac{1}{y}.\frac{dy}{dx}=log2.\left[2cosx\left(-sinx\right)\right]\\ \Rightarrow \frac{1}{y}.\frac{dy}{dx}=log2\left(-sin2x\right)\\ \Rightarrow \frac{dy}{dx}=-y.log2sin2x\\ Hence,\frac{dy}{dx}=-2^{co{s}^{2}x}\left(log2sin2x\right)\end{array}$

This is a short answer type question as classified in NCERT Exemplar

mass of the rain drop = 1g=1 $\times {10}^{-3}kg$

Height of falling h= 1km = 10³m and g = 10m/s² and sped of drop =50m/s

(a) Loss of PE of the drop =mgh= 1 $\times {10}^{-3}\times 10\times {10}^3=10J$

(b) Gain in KE of the drop = 1/2mv²= ½ $\times 1\times {10}^{-3}\times {50}^2$ =1.250J

(c) No gain in KE is not equal to the loss in its Pe, because a part of PE is utilised in doing work against the viscous drag in air.

One of the toughest considerations for an international student is to 'where to live in Dubai as a student'. It is important to consider the location as this factor decides the monthly rent in relation to the connectivity, facilities, and cost of living.

Some of the top locations a student should go for include:

• Dubai International Academic City (DIAC)
• Dubai Knowledge Park
• Al Barsha
• Deira
• Mirdif
• Bur Dubai 

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhatf:R\to Rsatisfiestheequationf\left(x+y\right)=f\left(x\right).f\left(y\right)\forall x,y\in R,f\left(x\right)\ne 0.\\ Letustakeanypointx=0atwhichthefunctionf\left(x\right)isdifferentiable.\\ \therefore f\text{'}\left(0\right)=\underset{h\to 0}{lim}\frac{f\left(0+h\right)-f\left(0\right)}{h}\\ 2=\underset{h\to 0}{lim}\frac{f\left(0\right).f\left(h\right)-f\left(0\right)}{h}\left[?f\left(0\right)=f\left(h\right)\right]\dots \left(1\right)\\ 2=\underset{h\to 0}{lim}\frac{f\left(0\right).\left[f\left(h\right)-1\right]}{h}\\ Now,f\text{'}\left(x\right)=\underset{h\to 0}{lim}\frac{f\left(x+h\right)-f\left(x\right)}{h}\\ =\underset{h\to 0}{lim}\frac{f\left(x\right).f\left(h\right)-f\left(x\right)}{h}\left[?f\left(x+y\right)=f\left(x\right).f\left(y\right)\right]\\ =\underset{h\to 0}{lim}\frac{f\left(x\right).\left[f\left(h\right)-1\right]}{h}=2f\left(x\right)\left[Fromeq\left(1\right)\right]\\ Hence,f\text{'}\left(x\right)=2f\left(x\right)\end{array}$