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Leaching involves the given reaction,

$4Au\left(s\right)+8C{N}^{-}\left(aq\right)+2H_{2}O\left(aq\right)+O_2\left(g\right)\to 4{\left[Au{\left(CN\right)}_2\right]}^{-}\left(aq\right)+4O{H}^{-}\left(aq\right)$              

Here, O₂ is required for formation of Au (l) cyanide complex but no complex in absence of O₂.

$2{\left[Au{\left(CN\right)}_2\right]}^{-}\left(aq\right)+Zn\left(s\right)\to {\left[Zn{\left(CN\right)}_4\right]}^{2-}\left(aq\right)+2Au\left(s\right)$                

In above displacement reaction, Zn is oxidized.

For high wavelength, size of antenna should be high.

No, isolated Mathematics students are not eligible for MHT CET or engineering admissions in Maharashtra. For B.E./B.Tech, candidates must have studied Physics and Mathematics along with a third science/vocational subject in Class 12. You need a complete Science background to apply for engineering through MHT CET.

For Transistor

to act as a switch → Saturation & cut – off state

to act as an amplifier → Active Region

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Note: The abovementioned information is as per official sources. However, it is subject to change. Hence, it is indicative.

Both Patanjali University and Jaipur National University are good options to pursue a BSc. However, in terms of affordability, Patanjali University is more affordable since the tuition fees to pursue a BSc at Patanjali University is INR 82,500, and the tuition fees to pursue a BSc at Jaipur National University is INR 4.96 lakh.

Note: The fee mentioned above is as per the official sources. However, it is indicative and subject to change.

$E_2>E_1$

For statement 1

              hf = E₁  - E₂

Since, E₂ > E₁

So, it should be

hf = E₂ – E₁

Therefore statement 1 is wrong

For statement 2

For the jumping of electron from higher energy orbit

(E₂) to lower energy orbit (E₁)

hf = E₂ – E₁

  $f=\frac{E_2-E_1}{h}$              

Statement (2) is correct

  ${\mu }_2>{\mu }_1$

$\frac{{\mu }_2}{{\mu }_1}>1$               

${\mu }_2=\frac{c}{v_2},{\mu }_1=\frac{c}{v_1}$               

$\frac{{\mu }_2}{{\mu }_1}=\frac{v_1}{v_2}>1\Rightarrow v_1>v_2$               

Frequency remains constant while refraction since energy is constant

$\upsilon =\frac{v}{\lambda }$               

$\lambda \alpha v$               

${\lambda }_1>{\lambda }_2$               

$\lambda \to$ decreases

wavelength and speed decreases but frequency remains constant

In order to make a choice between BA courses offered by Patanjali University and Dev Sanskriti Vishwavidyalaya, students can compare the options based on significant factors such as fees and Shiksha rating. To help, presented below is a comparison between the BA courses at Patanjali University and Dev Sanskriti Vishwavidyalaya based on fees and ratings:

Note: The abovementioned information is as per official sources. However, it is subject to change. Hence, it is indicative.

Both Patanjali University and Jaipur National University are good options to pursue a BA. However, in terms of affordability, Patanjali University is more affordable since the tuition fees to pursue a BA at Patanjali University range from INR 66,000 to INR 72,000, and the tuition fee to pursue a BA at Jaipur National University is INR 2.44 lakh.

Note: The fee mentioned above is as per the official sources. However, it is indicative and subject to change.

$R_1=R$  

$R_2=-R$       

$P=\frac{1}{f}=\left(\mu -1\right)\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$               

$P=\frac{1}{f}=\left(\mu -1\right)\left(\frac{1}{R}-\left(\frac{-1}{R}\right)\right)$

$P=\frac{\left(\mu -1\right)2}{R}$              

L₂

R₁ = R

$R_2=\infty$               

$R_1=\infty$               

R₂ = ­­-R

Power of  $L_1=\frac{1}{f\text{'}\text{'}}=\left(\mu -1\right)\left(\frac{1}{R_1}-\frac{1}{R_2}\right)$

Power of $L_1=\frac{\left(\mu -1\right)\times 2}{R}=P$