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5 months ago

0 Follower 3 Views

P
Pallavi Pathak

Contributor-Level 10

In NEET entrance test, the weightage of Class 11 Physics Chapter 11 Thermodynamics is around 7%. Students should thoroughly understand the thermodynamic laws and internal energy. The medical entrance test includes theory and numerically-based questions. For JEE Main, the chapter has more significance, and it has nearly 15% weightage of the total Physics syllabus.

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5 months ago

0 Follower 24 Views

V
Vishal Baghel

Contributor-Level 10

2²? ¹ - 1 - 1 = 126
2²? ¹ = 2?
2n + 1 = 7
n = 3

New Question

5 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

W A B = n R T l n 2 V 1 V 1 = n R T l n 2 .

W B C = P 2 ( V 1 2 V 1 ) = P 2 V 1 = 1 2 n R T                         

[At B, 2P2 V1 = nRT]

W C A = 0   [CA is isochoric process].

W A B C A = W A B + W B C + W C A = n R T ( l n ( 2 ) 1 2 )            

New Question

5 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10


c = -5, a = 2, b = 1

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5 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Given, L = 2H

l = 2 sin (t2)

u = 0 2 L i d i = L 2 [ i 2 ] 0 2 = L 2 [ 4 0 ]

u = 2 2 × 4 = 4 J

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Let five terms in G.P. be a/r², a/r, a, ar, ar²
Then, a (r? ² + r? ¹ + 1 + r + r²) / (1/a) (r? ² + r? ¹ + 1 + r? ¹ + r? ²) = 49
⇒ a² = 49 ⇒ a = ±7
Also, a/r² + a = 35
Therefore, a = -7 is not possible
Now, fifth term = ar² = a (7/28) = p ⇒ 4p = 7

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

(12)                                                                                                                                                                                      &

...more

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5 months ago

0 Follower 47 Views

R
Raj Pandey

Contributor-Level 9

R e q = 2 . 5 Ω

l = v R e q = 5 2 . 5 = 2 A

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

All even + 2 odd 1 even
¹? C? + ¹? C? × ¹? C?
120 + 450
=570

New Question

5 months ago

0 Follower 2 Views

A
Aadit Singh Uppal

Contributor-Level 10

Power calculations can also differ based on the nature of forces, which are as follows:

  • Conservative Forces: Here, work done is path-independent. e.g., gravity, spring force
  • Non-Conservative Forces: Work depends on the path. e.g., friction

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5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

l 1 = 1 2 m r 2

l 2 = 1 2 m r 2 l 3 = 1 2 m r 2 l 4 = 2 5 m r 2

New Question

5 months ago

0 Follower 2 Views

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

C.O.V = σ/x? × 100

New Question

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

H = I 2 R t = 2 2 × R × 1 5

3 0 0 = 6 0 R

R = 5 Ω

Now for 3A, time = 10 sec

H ' = l 2 R t = 3 2 × 5 × 1 0 = 4 5 0 J

New Question

5 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

T? = cot? ¹ (2²? ¹ + 1/2? ) = cot? ¹ (1 + 2²? ¹)/2? ) = tan? ¹ (2? / (1 + 2²? ¹)
T? = tan? ¹ (2? ¹ - 2? ) / (1 + 2? ¹ . 2? ) = tan? ¹ (2? ¹) – tan? ¹ (2? )
S∞ = π/2 - tan? ¹ (2) = cot? ¹ (2) = tan? ¹ (1/2)

New Question

5 months ago

0 Follower 2 Views

S
Saumya Khandelwal

Contributor-Level 8

Sister Nivedita University, also known as SNU, is a renowned university in West Bengal that offers quality education to students in the fields of Humanities, Engineering, Social Sciences, Agricultural Sciences, etc. The popular programmes offered at Sister Nivedita University are BTech, BSc, and MBA. These courses are offered to students at the UG and PG levels for a duration of 4, 3, and 2 years, respectively. 

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5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

m ω 2 . 2 d 3 = G . m . 2 m d 2 ω = 3 G m d 3

T = 2 π ω = 2 π d 3 3 G m

 

New Question

5 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

3x² + 3x²y - 3xy² + dy³ = 0
3x² (x + y) – 3y² (x - dy/3) = 0
x - dy/3 = x + y for getting two perpendicular straight lines
d = -3

New Question

5 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

ceq = 2 4 × 8 3 2 = 6 μ F

 

 

New Question

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

cos 20° cos 40° cos 80°
= (2 sin 20° cos 20° cos 40° cos 80°) / (2 sin 20°)
= (2 sin 40° cos 40° cos 80°) / (2² sin 20°)
= (2 sin 80° cos 80°) / (2³ sin 20°)
= 1/8

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