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5 months agoContributor-Level 10
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5 months agoContributor-Level 10
Let five terms in G.P. be a/r², a/r, a, ar, ar²
Then, a (r? ² + r? ¹ + 1 + r + r²) / (1/a) (r? ² + r? ¹ + 1 + r? ¹ + r? ²) = 49
⇒ a² = 49 ⇒ a = ±7
Also, a/r² + a = 35
Therefore, a = -7 is not possible
Now, fifth term = ar² = a (7/28) = p ⇒ 4p = 7
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5 months agoContributor-Level 10
Power calculations can also differ based on the nature of forces, which are as follows:
- Conservative Forces: Here, work done is path-independent. e.g., gravity, spring force
- Non-Conservative Forces: Work depends on the path. e.g., friction
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5 months agoNew Question
5 months agoContributor-Level 10
T? = cot? ¹ (2²? ¹ + 1/2? ) = cot? ¹ (1 + 2²? ¹)/2? ) = tan? ¹ (2? / (1 + 2²? ¹)
T? = tan? ¹ (2? ¹ - 2? ) / (1 + 2? ¹ . 2? ) = tan? ¹ (2? ¹) – tan? ¹ (2? )
S∞ = π/2 - tan? ¹ (2) = cot? ¹ (2) = tan? ¹ (1/2)
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5 months agoContributor-Level 8
Sister Nivedita University, also known as SNU, is a renowned university in West Bengal that offers quality education to students in the fields of Humanities, Engineering, Social Sciences, Agricultural Sciences, etc. The popular programmes offered at Sister Nivedita University are BTech, BSc, and MBA. These courses are offered to students at the UG and PG levels for a duration of 4, 3, and 2 years, respectively.
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5 months agoContributor-Level 10
3x² + 3x²y - 3xy² + dy³ = 0
3x² (x + y) – 3y² (x - dy/3) = 0
x - dy/3 = x + y for getting two perpendicular straight lines
d = -3
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5 months agoContributor-Level 10
cos 20° cos 40° cos 80°
= (2 sin 20° cos 20° cos 40° cos 80°) / (2 sin 20°)
= (2 sin 40° cos 40° cos 80°) / (2² sin 20°)
= (2 sin 80° cos 80°) / (2³ sin 20°)
= 1/8
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