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If you are unable to log in to the Vidya Lakshmi portal, make sure that you are using the login and password correctly. If you forget, then reset it.

Second option is to make sure internet connection is stable or working. If problem persists, try reconnecting.

If both don't work, connect on toll free number of the portal. You will get customer support for technical assistance.

Yes, Definitely, B.Com is open to the students from all the streams whether it is arts, Science or other streams although you may need to put extra efforts initially to grasp accounting or finance concepts. Many students from engineering or arts successfully pursue B.Com and complement it with certifications like CA, CPA or CFA to build a strong career after the course.

The ICAR City Intimation slip was released on June 24, 2025, on the official website for both PG and PhD students who wish to appear for the ICAR Exam to pursue their preferred courses.  

$f\left(x\right)=\mathcal{l}n\left(x^2+1\right)-e^{-x}+1,g\left(x\right)=e^{-x}-2e^x$

for $f\left(g\left(a\right)\right)>f\left(g\left(b\right)\right)g\text{'}\left(x\right)=\overline{e^x}-2e^x<0\forall x\in R$

$f\text{'}\left(x\right)=\frac{2x}{x^2+1}+e^{-x}$

$\{\begin{array}{l}<1forn\ge 0,g\left(x\right)\downarrow \\ \ge 1forn<0\end{array}$

g(a) > g(b)

$\Rightarrow a<b\left(asg\downarrow \right)$

$\begin{array}{l}\Rightarrow {\alpha }^2-5\alpha +6<0\\ \left(\alpha -3\right)\left(\alpha -2\right)<0\end{array}$

Both terms refer to same online platform for applying for education loans in India. “Vidyalaxmi Portal” and “Vidyalakshmi Portal” are simply spelling variations of same thing.

Official portal introduced by the government is called “Vidya Lakshmi Portal, ” and it helps Indian students to apply for multiple education loan schemes offered by different banks through one application form.

No. The JEE Advanced 2026 admit card will not be sent via email or anyother mode of the candidates. Candidates have to doenload the admit card from their respective logins at jeeadv.ac.in.

The University of British Columbia has a total of 72,600+ students enrolled on its campus grounds, of which 18,600+ account for the international crowd. Moreover, 2,682 of the total student body accounts for Indian-origin students. Students can refer to the table given below for the enrollment trends of UBC over the years:

$\frac{x\left(cosx-sinx\right)}{e^x+1}+\frac{g\left(x\right)\left(e^x+1-x{e}^x\right)}{{\left(e^x+1\right)}^2}$

$=\sqrt[]{2}sin\left(x+\frac{\pi }{4}\right)+c,x>0$

$g\text{'}\left(x\right)=\sqrt[]{2}cos\left(x+\frac{\pi }{4}\right),x>0$

g + g’ = 2cos x + c, x > 0

 g – g’ = 2 sin x + c, x > 0

The last date to download the JEE Advanced 2026 admit card is May 17, the day of exam. Candidates can download the admit card before the exam starts from the respective logins at jeeadv.ac.in.

The JEE Advanced 2026 admit card will be released on May 11. Candidates can download the admit card by login to the website jeeadv.ac.in. 

According to the official website, NTA released the ICAR AIEEA Hall Ticket on June 27, 2025. The admit card is released a few days before the exam day for all the exam takers. 

$A=\left[\begin{array}{cc}\hfill 0\hfill & \hfill -2\hfill \\ \hfill 2\hfill & \hfill 0\hfill \end{array}\right]$

$A^2=\left[\begin{array}{cc}\hfill 0\hfill & \hfill -2\hfill \\ \hfill 2\hfill & \hfill 0\hfill \end{array}\right]\left[\begin{array}{cc}\hfill 0\hfill & \hfill -2\hfill \\ \hfill 2\hfill & \hfill 0\hfill \end{array}\right]$

$=\left[\begin{array}{cc}\hfill -4\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill -4\hfill \end{array}\right]=-4\left[\begin{array}{cc}\hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill \end{array}\right]=-4l$

$N^2=\frac{{\left(2^{20}-1\right)}^2}{25}l$

$M{N}^2=\frac{4}{125}{\left(2^{20}-1\right)}^{3}l$

$=\left[\begin{array}{ccc}\hfill \lambda \hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill \lambda \hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 0\hfill & \hfill \lambda \hfill \end{array}\right],\lambda \ne k$

No, there is no correction facility made available for JEE Advanced 026. Once a candidate has submitted the online JEE Advanced form by paying the application fee, there will be no option availale to edit the form and make corrections. Therefore candidates must submit the form after checking all the entries. Check for these errors:

• Spelling mistakes
• Document upload
• Exam centre perferences
• Reservation details filled

The last date to apply for JEE Advanced 2026 is May 2, 2026. Registered candidates can pay application fees is May 4. The official website to apply for IIT JEE Advanced is jeeadv.ac.in.

JEE Advanced application form 2026 will be released on April 23 for Indian candidates. Application form for foreign candidates can register beginning April 6, 2026. The application form will be available online only on the website jeeadv.ac.in.

$P\left(E_1/E_2\right)=\frac{1}{2},\Rightarrow \frac{P\left(E_1\cap E_2\right)}{P\left(E_2\right)}=\frac{1}{2}$

$P\left(E_2/E_1\right)=\frac{3}{4}$ $P\left(E_1\right)=\frac{1}{6}$

$P\left(E_1\cap E_2\right)=\frac{1}{8}$ $P\left(E_2\right)=\frac{1}{4}$

$P\left(E_1\cup E_2\right)=\frac{1}{6}+\frac{1}{4}-\frac{1}{8}=\frac{4+6-3}{24}=\frac{7}{24}$

There are two shift timings for the GATE exam. Candidates can find the details of the shift timing on the official website. The GATE shift timings are as follows -

• Forenoon  - 9:30 am to 12:30 pm
• Afternoon - 2:30 pm to 5:30 pm

Candidates can also find the exam timing details mentioned in the GATE admit card. Candidates are advised to appear for the GATE 2026 exam on the date prescribed in the hall ticket. 

The Seneca Polytechnic placement rate stands at 79.1%. The average graduate salary is CAD 53,092 (INR 33.90 L).  On the other hand Leeds graduate earn in the range CAD 45,000 - CAD 50,000 (INR 28.73 L - INR 31.92 L), per year. Check the table listed below for Leeds University ratings for placement:

CAD 1 - INR 63.86

$f\left(x\right)+f\text{'}\left(x\right)+f\text{'}\text{'}\left(x\right)=x^5+64$

$\underset{x\to 1}{lim}\frac{f\left(x\right)}{x-1}\left(\frac{f\left(1\right)}{0}\right)f\left(1\right)=0$

Let f(x) = x⁵ + ax⁴ + bx³ + cx² + dx + e

  f(1) = 0 Þ 1 + a + b + c + d + e = 0

$\Rightarrow x^5+\left(a+5\right)x^4+\left(b+4a+20\right)x^3+\left(c+3b+12a\right)x^2+\left(d+2c+6b\right)x+e+d+2c=x^5+64$  

 Þ e + d + 2c = 64

b + 4a + 20 = 0                 c – 1 – a – b = 64

c + 3b + 12a = 0

d + 2c + 6b = 0                 a + b – c = -65

1 + a + b + c + d + e = 0   13a + 4b = -65

b + 4c = -20 × 4

-3a = 15 a = -5

$\begin{array}{l}f\left(x\right)=x^5-5x^4+60x^2-120x+64\\ f\text{'}\left(x\right)=5x^4-20x^3+12x-120\\ f\text{'}\left(1\right)=5-20+120-120=-15\end{array}$

The JEE Advanced passing marks or the JEE Advanced cutoff is set every year and it differs. Last year the JEE Advanced qualifying cutoff was as follows:

JEE Advanced 2025 Criteria for Inclusion in a Rank List:

JEE Advanced 2025 Qualifying Marks: