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If the answer key is out on the official website, then all the exam takers need to visit the official website to go through the answer key to evaluate their expected ICAR Scores. In case candidates want to raise an objection, they need to submit an objection fee of INR 200. 

$\frac{a+b}{7}=\frac{b+c}{8}=\frac{c+a}{9}=\frac{2\left(a+b+c\right)}{24}=\frac{c}{5}=\frac{a}{4}=\frac{b}{3}$

$r=\frac{\Delta }{S}=\frac{6k^2}{6k}=k$

$R=\frac{5k}{2}\Rightarrow \frac{R}{r}=\frac{5}{2}$

BC = CN = x = 75

$cot\theta =\frac{3h}{75}$            

$tan\theta =\frac{h}{75}$          

$\frac{3h^2}{75\times 75}=1\Rightarrow h=\frac{75}{\sqrt[]{3}}=25\sqrt[]{3}$

The authority mentions the SITEEE eligibility criteria along with the release of application forms. The basic eligiblity criteria to apply for SITEEE exam is passing the class 10+2 exam with Physics, Mathematics and Chemistry/ Computer Science/Electronics/ Information Technology/Biology/Informatics Practices/ Biotechnology/Technical Vocational subject/ Agriculture/ Engineering Graphics/Business Studies /Entrepreneurship. Candidates must have obtained at least 45% marks aggregate (40% for reserved category).

Aspirants can practice the JEE Advanced mock tests on the official website jeeadv.ac.in. Every year the conducting IIT releases the official JEE Advanced paper 1 and paper 2 mock tests. Candidates can practice these mock tests without any need of registration or payment of fee.

Apart from that, candidates can also practice the JEE Advanced mock exams provided by the coaching centres and experts on their respective websites.

There is total 13 Oberoi STEP test centres in India. These are:

• Agra

• Bhubaneswar 

• Chandigarh

• Chennai      

• Cochin

• Delhi/NCR

• Hyderabad 

• Jaipur 

• Kolkata

• Mumbai – North

• Mumbai – South 

• Shimla

• Udaipur

Candidates can check section-wise marking and question distribution.

Students will be given 4 marks for each correct response, and -1 mark will be deducted for incorrect answer.

$\underset{x\to 0}{lim}\frac{{\displaystyle \underset{0}{\overset{x^2}{\int }}\left(sin\sqrt[]{t}\right)dt}}{x^3}$ $\left(\frac{0}{0}\right)$   aplying L’ Hospital rule

$=\underset{x\to 0}{lim}\frac{sin\left(\sqrt[]{x^2}\right).2x}{3x^2}$

$=\frac{2}{3},forx>0$

Yes, VIT has introduced negative marking scheme in VITEEE 2026-27 admissions. Now, students will get -1 mark for every wrong attempt. However, for each correct answer, 4 marks will be awarded.

The age limit for Oberoi step is betwen 18 to 20 years. You should be above 18 years and below 20 years to apply for Oberoi Step entrance exam. 

ICAR AIEEA Answer key is released with the purpose of allowing exam takers to evaluate their expected scores and to challenge the answer key. However, the process to raise an objection is simple.

1. Candidates need to visit the official website of the ICAR Exam.
2. Candidates need to click on the objection link by using their login id and password.
3. Go through the Answer key and ICAR AIEEA Question paper.
4. Candidates need to submit the valid proof to support their objection along with the question number, and then they need to submit the answer key.

p + q = 2

p⁴ + q⁴ = 272

  ${\left(p^2+q^2\right)}^2-2p^2{q}^2=272$          

${\left[{\left(p+q\right)}^2-2pq\right]}^2-2p^2{q}^2=272$           

Let pq = t -> (4 – 2t)² – 2t² = 272

2t² – 16 t – 256 = 0

->t = pq = 16

Required equation x² – 2x + 16 = 0

1. Improving the accuracy and speed.
2. Understanding the previous year trends.
3. Knowing the exam pattern.
4. Identifying the important topics with high weightage.
5. Knowing the types of questions that come.

$l={\displaystyle \underset{0}{\overset{\pi }{\int }}\frac{e^{cosx}sinxdx}{\left(1+co{s}^{2}x\right)\left(e^{cosx}+e^{-cosx}\right)}}$

$2l={\displaystyle \underset{0}{\overset{\pi }{\int }}\frac{sindx}{1+co{s}^{2}x}=2{\displaystyle \underset{0}{\overset{\pi /2}{\int }}\frac{sinxdx}{1+co{s}^{2}x}}}$

$l={\displaystyle \underset{1}{\overset{0}{\int }}\frac{-dt}{1+t^2}={\displaystyle \underset{0}{\overset{1}{\int }}\frac{dt}{1+t^2}=\frac{\pi }{4}}}$

The SITEEE 2026 exam fee is Rs. 2250 per test. Students can apply for a single or both sessions of the exam. Applicants also have to pay Rs 1000 for each programme that they apply for.

A  (A -> B) -> B is a tautology