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This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans:

K_sp=3.2 × 10^-8

PbCl₂? Pb₂⁺ +2Cl^-

K_sp= (S) (2S)²

K_sp=4S³

s³=43.2 × 10^-8

s³=8 × 10^-9

s=2 × 10^-3

Molar   mass   of   PbCl₂=278g/mol   

By using Molarity formula,      

2 × 10^-3= 278 ×  x0.1

x= $\frac{0.1}{278\mathrm{ }\times \mathrm{ }2\mathrm{ }\times \mathrm{ }{10}^{-3}}$

= $\frac{100}{278\mathrm{ }\times \mathrm{ }2\mathrm{ }}$

x=0.18L   

This is a short answer type question as classified in NCERT Exemplar

NaH belongs to Saline hydrides and B₂H₆ and H₂O belong to molecular hydrides.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: pH of HOCL = 2.85

But, - pH = log [H⁺]

 -2.85=log [H⁺]

= -3.15 = log [H⁺]

  [H⁺]=anti log3.15

  [H⁺]= 1.413* 10^-3 

or weak mono basic acid

[H⁺]= $\sqrt[]{K_a*}$  C

= $K_a$  = $\frac{{\left. [{\mathrm{H}}^{+}\right]}^2}{\mathrm{C}}$  = $\frac{{\left(\mathrm{}1.43*{10}^{-3}\right)}^2\mathrm{ }\mathrm{ }}{0.08}$

=24.957 $*\mathrm{}$ 10^-6

=2.4957 $*\mathrm{}$ 10^-5

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This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: Given with the pH = 5 as, pH= - log  [ H⁺ ] 

  [ H⁺ ] =10^-5M

On 100 times dilution-

  [ H⁺ ] =10^-7M.

This is a short answer type question as classified in NCERT Exemplar

These are formed by many d-block and/block elements. However, the metals of group 7, 8 and 9 do not form hydride. Unlike saline hydrides, they are almost always non- stoichiometric, being deficient in hydrogen. For example, LaH 2.87, YbH 2.55, TiH 1.5-1.8, ZrH 1.3-1.75. Dihydrogen forms molecular compounds with most of the jp-block elements.

Most familiar examples are CH₄, NH₃, H₂O and HF.

This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: Here concentration of water cannot be neglected since the solution is very dilute. pH will be less than 7.0. Hence, the total concentration is given as -

  [ H₃O⁺ ] =10^-8+10^-7M.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: At a given time the reaction quotient Q for the reaction will be given by the expression:

Q= $\frac{\left[\mathbf{H}2\right]\left[\mathbf{I}2\right]}{\left[\mathbf{H}\mathbf{I}\right]\mathrm{}}$  = $\frac{[1\times 10??\times 1\times 10??]}{{\left(2\times \mathrm{}10^{-5}\right)}^2}$  = $\frac{1}{2}\mathrm{}$ = 0.25

 = 2.5×10⁻¹

As the value of the reaction quotient is greater than the value of K_c i.e. 1×10⁻⁴ the reaction will proceed in the reverse direction.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: Correct order of pH is -

NH₄Cl  C₆H₅COONH₄  KNO₃  CH₃COONa

Salts of strong acid and strong base do not hydrolyse and form neutral solution thus, pH will be nearly 7 of KNO₃?  

In sodium acetate, acetic acid remains unionised this results in increase in OH- concentration and pH will be more than 7. 

NH₄Cl formed from weak base,  NH₄OH and strong acid,  HCl, in water dissociates completely, aq. ammonium ions undergo hydrolysis with water to form NH₄OHand H₊ ions resulting in less pH value.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: Conjugate acid of a weak base is always stronger and conjugate base of weak acid is always strong.

The weak acids are:

⇒H₂O, ROH, CH₃COOH, HCl

⇒HCl > CH₃COOH > ROH > H₂O

⇒ Conjugate base order ⇒ OH⁻>RO⁻>CH₃COO⁻>Cl⁻

This is a short answer type question as classified in NCERT Exemplar

Water-gas shift reaction: The water-gas shift reaction is a chemical reaction in which carbon monoxide reacts with steam in the presence of a catalyst to form carbon dioxide and hydrogen.

CO+H₂+H₂O → CO₂+2H₂

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: Higher the value of Kb stronger will be the base. 

K_b-  5.4 * 10^-4 >1.77 * 10^-5 > 1.77 * 10^-9> 1.3 * 10^-14

Decreasing order of basic strength. 

Dimethylamine > Ammonia > Pyridine > Urea

Hence among the given bases, the strongest base is Dimethylamine. 

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: BF₃ does not have a proton but still it acts as a Lewis acid as it is an electron pair acceptor and reacts with NH₃by accepting its lone pair of electrons. The reaction can be represented by Coordinate bond is formed between BF₃ and NH₃. It can be represented as-

  [ BF₃ ← :NH₃]

Nitrogen acts as lone pair donator in this combination