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Which of the following pair of molecules contain odd electron molecule and an expanded octet molecule?

The circle passing through the intersection of the circles, $x^2+y^2-6x=0$ and $x^2+y^2-4y$ $=0$ , having its centre on the line, $2x-3y+12=0$ , also passes through the point:

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The locus of a point for which $y=0,z=0$  is

(a) Equation of $x$ -axis

(b) Equation of $y$ -axis

(c) Equation of $z$ -axis

(d) None of these

Let $\lambda \ne 0$ be in R. If $\alpha$ and $\beta$ are the roots of the equation, $x^2-x+2\lambda =0$ and $\alpha$ and $\gamma$ are the roots of the equation, $3x^2-10x+27\lambda =0$ , then $\frac{\beta \gamma }{\lambda }$ is equal to:

A plane is parallel to yz-plane so it is perpendicular to:

(a) x -axis

(b) y-axis

(c) z-axis

(d) None of these

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Let $\lambda \ne 0$ be in R. If $\alpha$ and $\beta$ are the roots of the equation, $x^2-x+2\lambda =0$ and $\alpha$ and $\gamma$ are the roots of the equation, $3x^2-10x+27\lambda =0$ , then $\frac{\beta \gamma }{\lambda }$ is equal to:

A plane is parallel to yz-plane so it is perpendicular to:

(a) x  -axis

(b) y -axis

(c) z -axis

(d) None of these

Let $\lambda \ne 0$ be in R. If $\alpha$ and $\beta$ are the roots of the equation, $x^2-x+2\lambda =0$ and $\alpha$ and $\gamma$ are the roots of the equation, $3x^2-10x+27\lambda =0$ , then $\frac{\beta \gamma }{\lambda }$ is equal to: