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B₂ have bond order equal to 1 and also paramagnetic.

$H{e}_2^{2+}{O}_2^{2-}N{e}_2^{2+}{F}_2{H}_2$ have bond order equal to 1 but are diamagnetic.

$O_2^{2+}$ have bond order equal to 3.

Fehling solution test can be given by aldehyde except aromatic aldehyde

can't give Fehling solution test,

other all three given can give Fehling solution test.

(E_a)_net = $E_{a_1}$ + $E_{a_2}$ – $E_{a_3}$  

= 40 + 50 – 60

= 90 – 60

= 30kJ/mol

Please find the solution below:

Assume mass of solution

= 100g

Mass of solute = 36gm

Moles of solute = 1

Molarity=  $\frac{1*1000}{\left(\frac{100}{1.5}\right)}=\frac{1000}{100}*1.5=15$

₃₇Rb = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 5s¹

Last electron enters in 5s subshell

Value of quantum numbers

n = 5, l = 0, m = 0, s =  $\pm \frac{1}{2}$

Please find the solution below:

After balancing change in oxidation state,

2Cl₂ $\stackrel{}{\to }$ 2Cl^– + 2ClO^–

Next, balance 'O' atoms,

2Cl₂ +4OH^– $\stackrel{}{\to }$  2Cl^– + 2ClO^–+ 2H₂O

Simplifying to get the simplest ratios,

Cl₂ +2OH^– $\stackrel{}{\to }$ Cl^–+ClO^–+ H₂O

x = 1, y = 2, z = 1, p = 1

K₂Cr₂O₇ + H₂O₂ + H₂SO₄->  + K₂SO₄ + H₂O compound 'X' is ->CrO₅

Oxidation state of chromium = +6.

A. Vitamin B₁₂– Co

B.  Wilkinson catalyst –Rh ( [Rh (PPh₃)₃Cl])

C.  Ziegler-Natta catalyst –Ti (TiCl₄ +Al (C₂H₅)₃)

D.  Haemoglobin – Fe

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Ionisation enthalpy increases in a period. Z dominates over screening effect (s) in a period as Z_eff. increases.

Angular momentum is an axial vector along axis of rotation.

Proteins on hydrolysis gives α-amino acid because α-amino acids are building block of proteins. It is also fact that amino acids contain both –NH₂ and –COOH group.

Electronegativity generally decreases as we move down the group but Pb has higher electronegativity than Sn.

C non-metal

Si and Ge->metalloids

Sn and Pb->metals

E.N. of Sn 1.8, Pb = 1.9