Ask & Answer: India's Largest Education Community

1000+ExpertsQuick ResponsesReliable Answers

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post




Ok

All Questions

New Question

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Kb= 5.4×104

c= 0.02M

Then, α= (Kb /c)1/2

α= (5.4×104 / 2 x 10-2)1/2 =0.1643

(CH3)2NH+H2O ↔ (CH3)2NH+2+OH-

[ (CH3)2NH] = 0.02 – x ≈ 0.02

[ (CH3)2NH+2] = x

[OH-] = 0.1 + x

≈ 0.1

Now, Kb= [ (CH3)2NH+2] [OH−]/ [ (CH3)2NH] = (x × 0.1) / (0.025).

x = 1.08 x 10-4

% of dimethylamine ionised = (1.08 x 10-4) x (100 / 0.02) = 0.54%

New Question

11 months ago

0 Follower 5 Views

U
Upasana Kumari

Contributor-Level 10

Guwahati University accepts a variety of national entrance exams such as JEE Main, GATE, CAT, MAT, XAT, CMAT, and others. Additionally, students with scores of 75 percentile or higher in these national exams may be exempted from the university's written test and proceed directly to the Group Discussion and Personal Interview rounds. 

New Question

11 months ago

0 Follower 7 Views

S
Shailja Rawat

Contributor-Level 10

Students willing to enroll into M.Tech courses at SRM University can appear for the SRMJEE PG exam. As per the official website of the university, the SRMJEE PG phase 2 dates are out. As per the schedule, the SRMJEEE PG exam phase 2 was conducted tentatively from Jun 12 to Jun 17, 2025. Registered students must appear on the scheduled exam date.

New Question

11 months ago

0 Follower 2 Views

A
Aayush Sharma

Contributor-Level 10

The total tuition fee of BSc at MMU Sadopur is INR 1.6 Lakh. The BSc programme at MMU Sadopur is four years long and candidates have to pay the tuition fee over that period. Therefore, candidates have to pay an annual fees of INR 40,000 as part of the BSc tuition fees at MMU Sadopur. 

New Question

11 months ago

0 Follower 52 Views

V
Vishal Baghel

Contributor-Level 10

pKa? =? logKa= 4.74

Ka? = 10? pKa =10?4.74 = 1.8*10?5
Let x be the degree of dissociation. The concentration of acetic acid solution, C = 0.05 M
The degree of dissociation,  

x= (Ka / C)1/2? = (1.8*10?5 / 0.05)1/2 ? = 0.019

(a) The solution is also 0.01 M in HCl.
Let x M be the hydrogen ion concentration from ionization of acetic acid. The hydrogen ion concentration from ionization of HCl is 0.01 M. The total hydrogen ion concentration

[H+] = 0.01 + x
The acetate ion concentration is equal to the hydrogen ion concentration from ionization of acetic acid. This is also equal to the concentration of acetic acid that has dissociated.
[CH3?

...more

New Question

11 months ago

0 Follower 4 Views

N
Nishtha Sharma

Contributor-Level 10

The highest stipend offered during IIM Rohtak MBA summer placements for the batch of 2024-26 is presented below:

Particulars

PGP Summer Placement Statistics (2024-26 Batch)

the highest stipend

INR 3.6 lakh

New Question

11 months ago

0 Follower 1 View

M
Manori Sahni

Contributor-Level 9

Cluster University Srinagar BCA graduates can find various career opportunities in the government and private sectors. The degree holders can work as a web developer, software developer, data analyst, cybersecurity specialist, or network administrator. Often, the UG degree holders opt for higher studies and pursue MCA or MBA to boost their career prospects.

Some other popular job roles for BCA degree holders are as follows: 

  • Mobile app development
  • Cloud computing
  • IT consulting

New Question

11 months ago

0 Follower 1 View

M
Mani Malhotra

Contributor-Level 6

Simple Present Tense is the kind of verb tense which is used in our everyday life. The scenarios where Simple Present Tense can be used are:

  • To describe daily routine 
  • To describe facts or universal truths
  • To describe scheduled events
  • To describe feelings and state of being
  • To describe directions and instructions
  • To describe habits

New Question

11 months ago

0 Follower 7 Views

S
Shailja Rawat

Contributor-Level 10

SRM University has commenced the M.Tech admission process for the academic year 2025. Students who wish to enroll into the courses can visit the university's official website and apply. However, the university has not announced any deadline to fill out the application form. Students are advised to register timely to avoid missing out on the application process.

New Question

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Let c be the initial concentration of C6H5NH3+ and x be the degree of ionisation.

C6H5NH2 + H2O?  C6H5NH3+ + OH-

c (1-x)                      cx              cx

Kb = [C6H5NH3+] [ OH-] / [C6H5NH2]

= [cx] [cx] / [c (1 – x)]

Since x is very small and negligible 1 – x≈ 1

 ∴Kb= [cx] [cx] / [c] = cx2

=> x = K b c

=

= 6.56 x 10-4

∴ [OH-] = cx = 0.001 x 6.56 x 10-4 = 6.56 x 10-7 M

  [H+]= Kw / [OH-] = 10-14 / 6.56 x 10-7 = 1.52 x 10-8

pH= &ndash

...more

New Question

11 months ago

0 Follower 4 Views

Shiksha Ask & Answer
Bhumika Khandelwal

Contributor-Level 10

IPFC Academy offers certification courses such as CMA USA, CIA USA, CPA USA and ACCA UK.The college prepares students through its Online Live Classes. Students with work experience can enroll to these programmes.

New Question

11 months ago

0 Follower 13 Views

V
Vishal Baghel

Contributor-Level 10

pH = 9.95,  

pOH = 14 – pH = 14 − 9.95 = 4.05
[OH] = 10−pOH = 10−4.05 = 8.913 × 10−5

Codeine + H2? O? CodeineH+ + OH

The ionization constant,  Kb? = [CodeineH+] [OH] / [codeine]?

= [ (8.913×10−5)× (8.913×10−5)] / 5×10−3

= 1.588×10−6.

pKb? = −log (1.588×10−6)

= 5.8

New Question

11 months ago

0 Follower 3 Views

S
Shailja Rawat

Contributor-Level 10

Once the M.Tech selection process is completed at SRMU AP, students with admission offers are required to pay a part of the tuition fees to secure their seat. As per official sources, the total tuition fees for M.Tech courses amount to INR 3 lakh.

Note: The above-mentioned fee is as per the official sources. However, it is indicative and subject to change.

New Question

11 months ago

0 Follower 4 Views

P
Pooja Divya

Contributor-Level 10

The domain-wise average package received during IIM Rohtak placements 2025 is presented below:

Domain

PGP Average Package (2025)

Sales & Marketing

INR 17.73 LPA

Product Management, IT and Operations

INR 19.62 LPA

Consulting

INR 16.05 LPA

Finance

INR 17.01 LPA

General Management and HR

INR 16.16 LPA

New Question

11 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

H+] = cα = 0.1 × 0.132 = 0.0132M

pH = −log [H+] = −log0.0132

= 1.88

The acid dissociation constant is 

 Ka? = cα2? / (1−α) = 0.1 × (0.132)2 / (1−0.132)

= 2.01×10−3.

pKa? = −logKa? = −log (2.01×10−3) ≈ 2.7

New Question

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

(a) For 2g of TlOH dissolved in water to give 2 L of solution:

[TlOH] = [OH] = (2×1)? / (2×221) = (1 / 221)? M

pOH = −log [OH] = −log (1/221)?

= 2.35

pH = 14 – pOH = 14 − 2.35 = 11.65


(b) For 0.3 g of Ca (OH)2?  dissolved in water to give 500 mL of solution:

[OH] = 2 [Ca (OH)2? ] = 2 (0.3×1000/500? ) = 1.2M
pOH = −log [OH] = −log1.2 = 1.79

pH= 14−pOH=14−1.79

=12.21

(c) For 0.3 g of NaOH dissolved in water to give 200 mL of solution:

[OH]= [NaOH] = 0.3×1000/200? = 1.5M
pOH= −log [OH] = &mi

...more

New Question

11 months ago

0 Follower 7 Views

N
Nishtha Karan

Contributor-Level 10

The highest package offered during IIM Rohtak placements over the past three years is presented below:

Particulars

PGP Placement Statistics (2023)

PGP Placement Statistics (2024)

PGP Placement Statistics (2025)

the highest package

INR 36 LPA

INR 48.25 LPA

INR 36 LPA

New Question

11 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

(a) 0.003 M HCl
[H3? O+] = [HCl] = 0.003M

 pH = −log [H+] = −log (3.0×10−3) = 2.523


(b) 0.005 M NaOH
[OH] = [NaOH] = 0.005M
[H+] = Kw? / [OH]? = 10−14/ 0.005? =2×10−12

pH= −log [H+]=−log (2×10−12)=11.699


(c) 0.002M HBr
[H+]= [HBr]=0.002

pH= −log [H+]=−log0.002=2.699


(d) 0.002M KOH
[OH]= [KOH]=0.002M
[H+]= Kw / [OH]? =10−14 / 0.002? =5×10−12

pH= −log [H+]=−log (5×10−12)=11.301

New Question

11 months ago

0 Follower 1 View

S
Shailja Rawat

Contributor-Level 10

SRM University offers an array of specialisations under its M.Tech programme. At the time of application, students must indicate the choice of specialisation. The following is a list of all the courses offered by the university for students to choose from:

New Question

11 months ago

0 Follower 3 Views

S
Shiksha Shukla

Contributor-Level 6

There are three kinds of simple present tense in the English language. The structure for each is as follows:

Affirmative: Subject + base verb (add -s/-es for third-person singular)

Negative: Subject + do/does + not + base verb

Interrogative: Do/Does + subject + base verb +?

Register to get relevant
Questions & Discussions on your feed

Login or Register

Ask & Answer
Panel of Experts

View Experts Panel

Share Your College Life Experience

×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.