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New Question

11 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

(a) In case of a non-polar (covalent) solvent, solvation enthalpy is small and hence, not sufficient to overcome lattice enthalpy of the salt. Consequently, the salt does not dissolve in non-polar solvent. As a general rule, for a salt to be able to dissolve in a particular solvent its solvation enthalpy must be greater than its lattice enthalpy so that the latter may be overcome by former. Each salt has its characteristic solubility which depends on temperature.

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11 months ago

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H
Himanshu Singh

Contributor-Level 10

To get a seat, candidates must hold a valid GATE or PERA CET score. Preference is given to those with experience in heritage travel visits or proficiency in local languages. Final selection is based on SOP, interview, and merit.

New Question

11 months ago

0 Follower 2 Views

A
Aayush Sharma

Contributor-Level 10

MMU Sadopur BSc admission start after Class 12 exams of recognised boards end. Candidates who want to apply for admission at the university can apply after they have given their Class 12 exams. There are no additional entrance exams necessary for admission into the programme, once Class 12 results are out candidates are provided with provisional admission at the university. Candidates have to pay some amount of the tuition fees to confirm their admission.

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11 months ago

0 Follower 248 Views

P
Piyush Shukla

Contributor-Level 7

The TS EAMCET counselling 2025 usually starts within 15 to 30 days after the announcement of the result. JNTUH had announced the TS EAMCET results on May 11 along with the rank card and topper's list. Hence, based on above-mentioned timeline, it is expected that the TG EAPCET counselling will begin in the first or second week of June 2025.

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11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

(d) Higher order ionization constants (Ka2, Ka3) are smaller than the lower order ionization constant (Ka1) of a polyprotic acid. The reason for this is that it is more difficult to remove a positively charged proton from a negative ion due to electrostatic forces. This can be seen in the case of removing a proton from the uncharged H2CO3 as compared from a negatively charged HCO3–.Similarly, it is more difficult to remove a proton from a doubly charged HPO42– anion as compared to H2PO4.

New Question

11 months ago

0 Follower 15 Views

T
Tasbiya Khan

Contributor-Level 10

There are about 100+ LLB colleges in Delhi NCR. Some of them are mentioned below along with their tuition fees:

LLB CollegesTuition Fee
Amity University Noida LLBINR 9 Lacs - INR 10 lakh
IMS Law College LLBINR 3 Lacs - INR 4 lakh
K.R. Mangalam University LLBINR 5 lakh
Jindal Global Law School, O.P. Jindal Global University LLBINR 19 lakh
Galgotias University LLBINR 2 lakh

Source: Official site and may vary.

New Question

11 months ago

0 Follower 6 Views

A
Abhay Dixit

Contributor-Level 7

The NTT  Diploma is a good alternative of NTT Course which is a good option for preschool teaching careers as ECCE focuses on early childhood education while NTT provides a foundation for teaching in Nursery class. 

New Question

11 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

(c) Ammonium hydroxide is a weak base (Kb = 1.77 * 10–5) and not a weak acid. Therefore, it remains almost unionised in solution. This results in increased of H+ ion concentration in solution making the solution acidic. Thus, the pH ofNH4Cl solution in water is less than 7.

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11 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

(a) The cations (e.g., Na+, K+, Ca2+, Ba2+, etc.) of strong bases and anions (e.g., Cl, Br, NO3–, ClO4– etc.) of strong acids simply get hydrated but do not hydrolyse, and therefore the solutions of salts formed from strong acids and bases are neutral i.e., their pH is 7. However, the other category of salts does undergo hydrolysis.

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11 months ago

0 Follower 3 Views

H
Himanshi Pandey

Contributor-Level 10

Navrachana University offers a full-time BSc (Hons) in various specialisations. The admission to the programme is subject to the fulfilment of the eligibility criteria specified by the university. The eligibility requirements slightly vary across the available specialisations. The following table presents the eligibility criteria for various BSc (Hons) specialisations at Navrachana University:

BSc (Hons) CoursesEligibility
ChemistryA minimum aggregate of 40% in Class 12 with PCM/ PCB subjects (Science Stream)
Data ScienceA minimum aggregate of 50% in Class 12/ equivalent exam in Science/ Arts/ Commerce stream

Botany & Plant Biotechnology, Microbiology, Zoology & Animal Biotechnology

A minimum aggregate of 45% in Class 12

New Question

11 months ago

0 Follower 4 Views

A
Akansha Gaurav

Contributor-Level 10

Guwahati University offers a variety of UG and PG courses across various streams such as Engineering, Managemnt, Commerce, ad others. The fee structure of the programme ranges between INR 12,000- INR 3.15 lakh. The fee strcture includes multiple components such as caution deposit, exam fee, tuition fee, and others. Additionally, students must pay an application fee while registering for admission at the institution. Students must take a note that this fee information is sourced from the official website/ sanctioning body and is subject to changes.

New Question

11 months ago

0 Follower 15 Views

New Question

11 months ago

0 Follower 5 Views

K
Kritika Tyagi

Contributor-Level 7

Yes, private institutes charge higher fees compared to Government Colleges that provide NTT Course which is between INR 30,000 – INR 50,000, depending on location and facilities

New Question

11 months ago

0 Follower 8 Views

S
SUMIT .

Contributor-Level 6

Yes, it is possible to pursue the rest of the course through online or correspondence mode even while living in kuwait.

Important consideration for foreign students:

Equivalence certificate 

Registration with INC

New Question

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

(b) Both are correct statements but R is not the reason for A. The acid-base pair that differs only by one proton is called a conjugate acid-base pair. Therefore, OH is called the conjugate base of an acid H2O and NH4+ is called conjugate acid of the base NH3. If Brönsted acid is a strong acid then its conjugate base is a weak base and vice-versa. It may be noted that conjugate acid has one extra proton and each conjugate base has one less proton.

New Question

11 months ago

0 Follower 6 Views

A
Aneena Abraham

Contributor-Level 10

Hi, Catering colleges in Coimbatore does offer Diploma courses and you can refer below for some of them:

College NameTuition Fee
Annamal Institute of Hotel Management-/-
Sankara College of Science and Commerce-/-
Kasturi Institute of Management KIM CoimbatoreINR 1.55 lakh

New Question

11 months ago

0 Follower 1 View

New Question

11 months ago

0 Follower 1 View

A
Aneena Abraham

Contributor-Level 10

Hi, listed below is the eligibility criteria for admission to best colleges for Catering in Coimbatore:

  • UG/UG Diploma: Class 12 from any stream with a minimum of 45% aggregate score from a recognised board.
  • PG/PGDM: A bachelor's degree from any discipline with a minimum of 45% aggregate score from a recognised university.
  • Doctorate: A master's degree from any discipline with a minimum of 45% aggregate score from a recognised university.
  • Certification/After Class 10: Class 10 score from a recognised board.

Disclaimer: This information is sourced from official website and may vary.

New Question

11 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

For precipitation to take place, it is required that the calculated ionic product exceeds the Ksp value. So, following data on Ksp values should have been provided to answer the question.

KspforFeS=6.3×1018,

MnS=2.5×1013,

ZnS=1.6×1024

CdS=8.0×1027

Before mixing:

[S2]=1.0×1019M and [M2+]=0.04M 

volume =10mL volume =5mL 

After mixing:

[S2]=? [M2+]=?  

volume = (10+5)=15mL volume =15mL 

[S2]= (1.0×1019×10)/ 15=6.67×1020M

[M2+]= (0.04×5) / 15=1.33×10−2M

Ionic prod

...more

New Question

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

5.8. Calculation of partial pressure of H2 in 1L vessel:

P1= 0.8 bar, P2=? V1= 0.5 L, V2 = 1.0 L
As temperature remains constant, P1V1 = P2V2
=> (0.8 bar) (0.5 L) = P2  (1.0 L)

=>P2 = 0.40 bar, i.e., PH2 = 0.40 bar
Calculation of partial pressure of O2 in 1 L vessel
P1V1 = P2V2
(0.7 bar) (2.0 L) = P2  (1L)

=>P2 = 1.4 bar

=>Po2= 1.4 bar
Total pressure =PH2 + PQ2 = 0.4 bar + 1.4 bar = 1.8 bar

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