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Candidates who secured placements during Amrita School of Dentistry placements 2023 had an average package of INR 17 LPA. The official data regarding MDS placements at Amrita School of Dentistry is unavailable. There is no data available for ascertaining the placement statistics for the year 2024 or 2025 at Amrita School of Dentistry. Candidates are advised to regularly check the official website of Amrita School of Dentistry for any updates regarding placement data.

One-cycle higher educational programs are the integrated programs where both UG and PG programs are combined to form one. These programs are available in English language along with few others. The cost to pursue these are as follows:

Yes, candidates who wish to apply for an MDS course at Amrita School of Dentistry must possess a BDS degree from a recognised institute. There is no mention of a minimum pasing aggregate needed in MDS at Amrita School of Dentistry. Candidates are advised to visit the official website to confirm the eligibility criteria for MDS admissions at Amrita School of Dentistry.

Equation of normal is 4x – 3y + 1 = 0

Equation of tangent is 3x + 4y – 43 = 0

Area of triangle = $\frac{1}{2}\left(\frac{43}{3}+\frac{1}{4}\right)\times 7$  

$=\frac{1}{2}\times \left(\frac{172+3}{12}\right)\times 7=\frac{1225}{24}$          

  $\therefore 24A=1225$        

${\sigma }^2=\frac{\sum x^2}{n}-{\left(\frac{\sum x}{n}\right)}^2=\frac{9+k^2}{10}-{\left(\frac{9+k}{10}\right)}^2<10$

$\Rightarrow k<\frac{10\sqrt[]{10}}{3}+1\Rightarrow k\le 11$        

$\therefore$ maximum value of k is 11

$af\left(x\right)+\alpha f\left(\frac{1}{x}\right)=bx+\frac{\beta }{x}............\left(i\right)$  

Replace x by   $\frac{1}{x}$

$af\left(\frac{1}{x}\right)+\alpha f\left(x\right)=\frac{b}{x}+\beta x..............\left(ii\right)$  

$a\left(f\left(x\right)+f\left(\frac{1}{x}\right)\right)+\alpha \left(f\left(x\right)+f\left(\frac{1}{x}\right)\right)=b\left(x+\frac{1}{x}\right)+\beta \left(x+\frac{1}{x}\right)$           

$\therefore \frac{f\left(x\right)+f\left(\frac{1}{x}\right)}{x+\frac{1}{x}}=\frac{b+\beta }{a+\alpha }=\frac{2}{1}=2$           

Pursuing a BTech from Kurukshetra University is a good choice if considering the placement opportunities.  Check out the key highlights KUK BTech placements for the Class of 2024 in the table below:

Note: The above-mentioned data has been taken from the KUK Engineering NIRF report 2025.

There are nine different MDS specailisation courses available at MDS at Amrita School of Dentistry in addition to the standard MDS course. These specialisations include the following:

• Oral & Maxillofacial Pathology & Microbiology
• Public Health Dentistry
• Oral Medicine & Radiology
• Oral & Maxillofacial Surgery
• Periodontics, Conservative & Endodontics
• Orthodontics & Dentofacial Orthopaedics
• Paediatric & Preventive Dentistry
• Prosthodontics & Crown & Bridge

Let a, ar, ar², ar³ are in G.P.

a + ar + ar² + ar³ = $\frac{65}{12}$  

$\frac{1}{a}+\frac{1}{ar}+\frac{1}{a{r}^2}+\frac{1}{a{r}^3}=\frac{65}{18}$        

${\left(ar\right)}^{2}r=\frac{3}{2}\Rightarrow a=\frac{2}{3},r=\frac{3}{2}$          

  $\therefore$   third term = ar² = $\frac{2}{3}\times \frac{9}{4}=\frac{3}{2}$  

  $\therefore \alpha =\frac{3}{2}\Rightarrow 2\alpha =3$          

Let P (h, k)

$\sqrt[]{{\left(h-5\right)}^2+k^2}=3\sqrt[]{{\left(h+5\right)}^2+k^2}$           

$h^2-10h+25+k^2=9h^2+90h+225+9k^2$           

  $8h^2+8k^2+100h+200=0$

$x^2+y^2+\frac{25}{2}x+25=0$

$r^2=\frac{625}{16}-25=\frac{625-400}{16}=\frac{225}{16}$

$4r^2=\frac{225}{4}=56.25$         

The best conductor of electricity is Silver (Ag) at room temperature. It is not used in normal wiring even though being the best conductor because of its high cost.

• Electrical Conductivity ($\sigma$): $6.3 \times 10^ {7} \ \text {S/m}$

• Electrical Resistivity ($\rho$): $1.59 \times 10^ {-8} \ \Omega \cdot \text {m}$ (the lowest among all metals)

${\left(x+1\right)}^2+\left|x-5\right|=\frac{27}{4}$

Case l        x < 5

$x^2+2x+1-x+5=\frac{27}{4}$       

$\left(2x+3\right)\left(2x-1\right)=0\Rightarrow x=-\frac{3}{2},\frac{1}{2}$     

Case II   $\ge$   x 5

$x^2+2x+1+x-5=\frac{27}{4}$       

$x=\frac{-12\pm \sqrt[]{144+43\times 16}}{2\times 4}=\frac{-12\pm \sqrt[]{832}}{8}\left(rejected\right)$           

           because x > 5

Yes, NEET-PG for MDS courses is mandatory for admissions into the MDS course at Amrita School of Dentistry. The MDS courses at Amrita School of Dentistry are decided on the basis of the rank scored by the candidate in the NEET-PG exam. Candidates can check the official website for more information regarding MDS course eligibility at Amrita School of Dentistry.

α - sulphur & β - sulphur – Diamagnetic, S₂ – form is paramagnetic due to presence of unpaired electron in π* orbital like O₂.

  $\frac{2^{21}{\left(\frac{-1+i\sqrt[]{3}}{2}\right)}^{21}}{{\left(\sqrt[]{2}\right)}^{24}{\left(\frac{1-i}{\sqrt[]{2}}\right)}^{24}}+\frac{2^{21}{\left(\frac{1+\sqrt[]{3}i}{2}\right)}^{21}}{{\left(\sqrt[]{2}\right)}^{24}{\left(\frac{1+i}{\sqrt[]{2}}\right)}^{24}}=k$

=   ${\displaystyle \sum _{j=0}^5\left(j+5\right)\left(j+5-1\right)={\displaystyle \sum _{j=0}^5\left(j+5\right)\left(j+4\right)}}$

= ${\displaystyle \sum _{j=0}^5\left(j^2+9\widehat{j}+20\right)=\frac{5\times 6\times 11}{6}+\frac{9\times 5\times 6}{2}+20\times 6}$  

55 + 135 + 120 = 310

Including specialty, contractual and permanent faculty members at St Edmunds College Shillong there are a total of 38 PhD holders across various departments. Furthermore, St Edmunds College features 67 faculty members with Master's backgrounds from various streams. With a total of 105 Faculty members St Edmunds has an experienced and well-endowed faculty team focused on the academic enrichment of its students.