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11 months ago

Maharishi Markandeshwar University, Sadopur Colleges in Ambala

Can I get direct admission in MMU Sadopur BBA?

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Aayush Sharma

Contributor-Level 10

MMU Sadopur BBA admissions takes place through the merit secured in Class 12 exams. Candidates looking to secure admission in the BBA programme should make sure they have a valid Class 12 score. A passing grade in Class 12 exams is essential to be eligible for the programme. Candidates can apply for admission as soon as they get their Class 12 scores.

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11 months ago

SSN College of Engineering College of Engineering, Anna University

Is CEG better than SSN?

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11 months ago

SRM Institute of Science and Technology, Kattankulathur SRM Institute of Science and Technology, Ramapuram Campus- Chennai

Can I take direct admission in the BTech course at SRM Ramapuram?

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Anushka Bidhi

Contributor-Level 10

No, the admission into the BTech of SRM Ramapuram is subject to fulfillment of certain academic conditions. Only if the applying students are able to satisfy the set eligibility criteria, they are considered for the admissions. Students must secure an aggregate of 60% in the relevant qualifying exam, i.e., Class 12 exams.

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11 months ago

How costly is Mahatma Gandhi University?

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Jagriti Shukla

Contributor-Level 10

The fee structure of the programme ranges between INR 3,000- INR 11.3 lakh. The fee structure includes various factors such as caution deposit, exam fee, tuition fee, etc. Students can make the fee payment via online/ offline mode as per institute guidelines.

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11 months ago

Northwestern Polytechnic University India

What exams are accepted for BSc admission at NPU Jharkhand?

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Himanshu Singh

Contributor-Level 10

For BSc admission at NPU Jharkhand, the university primarily considers marks obtained in Class 12 from recognised boards like CBSE and JAC. Students should stay updated on these exam results and related announcements to ensure timely application.

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11 months ago

Business Management Studies ASBM University

Is BBA available at ASBM University?

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Himanshi Pandey

Contributor-Level 10

ASBM University offers a BBA (Hons) lasting four years. It is UG-level programme offered in the full-time mode. Following the NEP 2020, the university provides students with an option to exit the programme after three years. Such students are awarded with a BBA degree. Hence, candidates can pursue a BBA at ASBM University. The BBA curriculum is based on the CBCS scheme. It comprises six semesters.

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11 months ago

Delhi University (DU) Colleges in Delhi

I want to do B.Sc Psychology course. Is there a Delhi University or any Government University in West Bengal?

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Akhilesh Kumar Malav

Beginner-Level 1

Yes, You can take admission in two other universities. You will have to give CAT exam for that and college will be provided to you as per your marks.

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11 months ago

Northwestern Polytechnic University India

Is BSc admission open at NPU Jharkhand for 2025?

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Himanshu Singh

Contributor-Level 10

BSc admission at NPU Jharkhand for 2025 will be available soon. Interested students are advised to regularly check the university's official website for updates on application start dates, deadlines, and counselling schedules.

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11 months ago

Teaching & Education UGC NET Centres

What is the UGC NET City Intimation Slip or City Slip?

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Kritika Sharma

Contributor-Level 6

The UGC NET City Intimation Slip or City Slip is a document released by the NTA to inform candidates about the city where the exam center is located. Basically, it is not the admit card but provides advance information to help candidates make travel arrangements in advance.

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11 months ago

Tripura Agartala

When will the admissions start at MBB College, Agartala?

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11 months ago

Northwestern Polytechnic University Colleges in USA

What is the fee of BSc at NPU Jharkhand?

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Himanshu Singh

Contributor-Level 10

BSc fee at NPU Jharkhand is INR 1,700, as per the data from the official sources. This amount may include components like tuition, security, and other academic charges. A portion of the fee must be paid at the time of admission to confirm the seat. The fee structure is subject to revision.

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11 months ago

Northwestern Polytechnic University Study Abroad

Can I get direct admission to BSc at NPU Jharkhand?

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Himanshu Singh

Contributor-Level 10

Yes, NPU Jharkhand allows direct admission to its BSc programme based on academic merit. Students are selected primarily through their Class 12 performance from boards like CBSE or JAC. There is no separate entrance exam, making the admission process straightforward for eligible candidates who meet the required criteria.

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11 months ago

Merit Swiss Asian School of Hotel Management Mohyal Educational Research Institute of Technology (MERIT)

I have applied for IIT Guwahati for MA development studies, but where should I see the merit list.

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11 months ago

Northwestern Polytechnic University Colleges in USA

What is the eligibility criteria for BSc at NPU Jharkhand?

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Himanshu Singh

Contributor-Level 10

To be eligible for BSc admission at NPU Jharkhand, students must have secured a minimum of 45% aggregate marks in Class 12. This applies specifically to general category students. The qualifying examination must be from a recognised board such as CBSE or the Jharkhand Academic Council (JAC).

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11 months ago

NIMS - Nizam's Institute of Medical Sciences Colleges in Hyderabad

What is the expected cutoff for B.Sc nursing at NIMS, Hyderabad? I have 28827 rank in NEET.

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11 months ago

Humanities & Social Sciences B.A

Which colleges are best for BA elective English course with affordable fee and without CUET admission, based on 12th?

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ROHIT Rohit

Contributor-Level 10

Several colleges offer a BA in English (elective or honors) based on 12th-grade results without requiring CUET scores, with varying fees. Some popular choices include Delhi University colleges like Hindu College, Miranda House, and Gargi College, as well as options like St. Xavier's College (Kolkata) and Loyola College (Chennai). For more affordable options, consider institutions like MCM DAV College for Women (Chandigarh) or government degree colleges in different states.

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11 months ago

Northwestern Polytechnic University Study Abroad

Is the BSc course available at NPU Jharkhand?

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Himanshu Singh

Contributor-Level 10

Yes, Nilamber Pitambar University (NPU) Jharkhand offers a Bachelor of Science (BSc) programme that spans three years and is divided into six semesters. The course covers various core Science subjects and is designed to provide a strong academic foundation, preparing students for careers in science, research, and higher education.

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11 months ago

Cheran Polytechnic College Engineering

I want to know about the latest cutoff information for Diploma in Medical Laboratory Technology at Cheran Polytechnic College.

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11 months ago

physics ncert solutions class 11th Mechanical Properties of Fluids

10.31 (a) It is known that density $ρ$ of air decreases with height y as

where $ρ = ρ_{o} e^{\frac{- y}{y_{o}}}$ = 1.25 kg m^–3 is the density at sea level, and $ρ_{o}$ is a constant. This density variation is called the law of atmospheres. Obtain this law assuming that the temperature of atmosphere remains a constant (isothermal conditions). Also assume that the value of g remains constant.

(b) A large He balloon of volume 1425 m3 is used to lift a payload of 400 kg. Assume that the balloon maintains constant radius as it rises. How high does it rise?

[Take $y_{o}$ = 8000 m and $y_{o}$ = 0.18 kg m–3].

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Vishal Baghel

Contributor-Level 10

Volume of the balloon, V = 1425 $ρ_{H e}$

Mass of the payload, m = 400 kg

Acceleration due to gravity, g = 9.8 m/ $m^{3}$

$s^{2}$ = 8000 m

$y_{o}$ = 0.18 kg m^–3

$ρ_{H e}$ = 1.25 kg m^–3

Density of the balloon = $ρ_{o}$

Height to which the balloon will rise = y

Density of air decreases with height and the relationship is given by:

$ρ$ = $ρ = ρ_{o} e^{\frac{- y}{y_{o}}}$ ……(i)

Differentiating equation (i), we get

$\frac{ρ}{ρ_{o}}$ $e^{\frac{- y}{y_{o}}}$

$- \frac{d ρ}{d y}$ , where k is the constant of proportionality

$α ρ$ , height changes from 0 to y, while density changes from $\frac{d ρ}{d y} = - k ρ$ to $\frac{d ρ}{ρ} = - k d y$ . Integrating both sides between the limits, we get:

$ρ_{o}$

$ρ$ = -ky

$\int_{ρ_{o}}^{ρ} \frac{d ρ}{ρ} = - \int_{0}^{y} k d y$ = ${[\log_{e} ? ρ]}_{ρ_{o}}^{ρ}$ ….(ii)

From equation (i) and

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Volume of the balloon, V = 1425 $ρ_{H e}$

Mass of the payload, m = 400 kg

Acceleration due to gravity, g = 9.8 m/ $m^{3}$

$s^{2}$ = 8000 m

$y_{o}$ = 0.18 kg m^–3

$ρ_{H e}$ = 1.25 kg m^–3

Density of the balloon = $ρ_{o}$

Height to which the balloon will rise = y

Density of air decreases with height and the relationship is given by:

$ρ$ = $ρ = ρ_{o} e^{\frac{- y}{y_{o}}}$ ……(i)

Differentiating equation (i), we get

$\frac{ρ}{ρ_{o}}$ $e^{\frac{- y}{y_{o}}}$

$- \frac{d ρ}{d y}$ , where k is the constant of proportionality

$α ρ$ , height changes from 0 to y, while density changes from $\frac{d ρ}{d y} = - k ρ$ to $\frac{d ρ}{ρ} = - k d y$ . Integrating both sides between the limits, we get:

$ρ_{o}$

$ρ$ = -ky

$\int_{ρ_{o}}^{ρ} \frac{d ρ}{ρ} = - \int_{0}^{y} k d y$ = ${[\log_{e} ? ρ]}_{ρ_{o}}^{ρ}$ ….(ii)

From equation (i) and (ii), we get

$\frac{ρ}{ρ_{o}}$ = $e^{- k y}$ , k = $y_{0}$

Substituting the value of k in equation (ii), we get

$\frac{1}{k}$

Density $\frac{1}{y_{o}}$ = $ρ = ρ_{o} e^{\frac{- y}{y_{o}}} \dots \dots (i i i)$

= $ρ = \frac{M a s s}{V o l u m e} = \frac{M a s s o f t h e p a y l o a d + M a s s o f h e l i u m}{V o l u m e}$ = 0.461 kg/ $\frac{m + V ρ_{H e}}{V}$

From equation (iii), taking log on both sides

$\frac{400 + 1425 \times 0.18}{1425}$ = - $m^{3}$

y = -8000 $\log_{e} ? \frac{ρ}{ρ_{o}}$ = 8000 m = 8 km

The balloon will rise to 8 km

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11 months ago

physics ncert solutions class 11th Mechanical Properties of Fluids

10.30 Two narrow bores of diameters 3.0 mm and 6.0 mm are joined together to form a U-tube open at both ends. If the U-tube contains water, what is the difference in its levels in the two limbs of the tube? Surface tension of water at the temperature of the experiment is 7.3 × 10^–2 N m–1. Take the angle of contact to be zero and density of water to be 1.0 × 103 kg m^–3 (g = 9.8 m s^–2)

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Vishal Baghel

Contributor-Level 10

Diameter of the 1st bore, $d_{1}$ = 3 mm = 3 $\times 10^{- 3}$ m

Radius of the first bore, $r_{1}$ = 1.5 mm = 1.5 $\times 10^{- 3}$ m

Diameter of the 2nd bore, $d_{2}$ = 6 mm = 6 $\times 10^{- 3}$ m

Radius of the 2nd bore, $r_{2}$ = 3.0 mm = 3 $\times 10^{- 3}$ m

Surface tension of water, s= 7.3 $\times 10^{- 2}$ N/m

Angle of contact between the bore surface and water, $θ = 0$

Density of water, $ρ = 1.0 \times 10^{3}$ kg/ $m^{3}$

Acceleration due to gravity. g = 9.8 m/ $s^{2}$

Let $h_{1}$ and $h_{2}$ be the heights to which water rises in 1st and 2nd tubes respectively. These heights are given by the relations:

$h_{1} = {(2 s c o s ? θ) / ρ g r}_{1}$ …(i)

$h_{2} = {(2 s c o s ? θ) / ρ g r}_{2}$ …(ii)

The difference in level of water i

...more

Diameter of the 1st bore, $d_{1}$ = 3 mm = 3 $\times 10^{- 3}$ m

Radius of the first bore, $r_{1}$ = 1.5 mm = 1.5 $\times 10^{- 3}$ m

Diameter of the 2nd bore, $d_{2}$ = 6 mm = 6 $\times 10^{- 3}$ m

Radius of the 2nd bore, $r_{2}$ = 3.0 mm = 3 $\times 10^{- 3}$ m

Surface tension of water, s= 7.3 $\times 10^{- 2}$ N/m

Angle of contact between the bore surface and water, $θ = 0$

Density of water, $ρ = 1.0 \times 10^{3}$ kg/ $m^{3}$

Acceleration due to gravity. g = 9.8 m/ $s^{2}$

Let $h_{1}$ and $h_{2}$ be the heights to which water rises in 1st and 2nd tubes respectively. These heights are given by the relations:

$h_{1} = {(2 s c o s ? θ) / ρ g r}_{1}$ …(i)

$h_{2} = {(2 s c o s ? θ) / ρ g r}_{2}$ …(ii)

The difference in level of water in the 2 limbs

$h_{1} - h_{2}$ = $\frac{2 s c o s ? θ}{ρ g}$ ( $\frac{1}{r_{1}}$ - $\frac{1}{r_{2}})$

= $\frac{2 \times 7.3 \times 10^{- 2} \times c o s ? 0}{1.0 \times 10^{3} \times 9.8}$ ( $\frac{1}{1.5 \times 10^{- 3}}$ - $\frac{1}{3 \times 10^{- 3}})$ = 4.965 $\times 10^{- 3}$ m = 4.965 mm

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