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According to Balmer formula? = 1 / λ = R_H [1/n₁² – 1/n₂²]

For the longest wavelength transition in the Balmer series of atomic hydrogen, wave number must be least. This is possible in case n₂ – n₁ = minimum; i.e. n₁ = 2 and n₂ = 3. Substituting the values:

? = 1 / λ = (1.097 x 10⁷ m^-1) [1/2² – 1/3²] = (1.097 x 10⁷ m^-1) [5/36] = 1.523 x 10⁶ m^-1

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According to the official stats, Saveetha Engineering College concluded the placements for the batch passing out in 2025with 97% placements. The key highlights of Saveetha Engineering College placements for the Class of 2025 are tabulated below:

Candidates are to pass a Statement of Purpose discussion, an extempore round, and a personal interview. The last selection has 50\% CAT, 20\% academics and 30\% elements of interaction. Every round is carried out separately to evaluate the holistic potential. In the process, women get 5 bonus marks.

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(i) For an electron, the energies in the two orbits can be compared as:

E₁ / E₂ = (n₂ / n₁)²          [Since E is inversely proportional to n²]

Given: n₁ = 1, E₁ = –2.17 × 10^-18 J atom^-1, n₂ = 5

Therefore, (–2.17 × 10^-18 J atom^-1) / E₂ = (5 / 1) ² = 25

=> E₂ = (–2.17 × 10^-18 J atom^-1) / 25 = –8.77 x 10^-20 J atom^-1

(ii) For hydrogen atom; r_n = 0.529 x n² Å

r₅ = 0.529 x (5)² = 13.225 Å = 1.3225 nm.

Yes, pursuing an MBA from Saveetha Engineering College is a good choice if considering the placement opportunities. The course-wise placement stats are yet to be released on the official website. Meanwhile, check out the overall highlights of Saveetha Engineering College placements for the Class of 2025 in the table below:

As per Shiksha student reviews, the highest package offered during BTech placements at Integral University in 2024 was INR 12 LPA, while the lowest stood at INR 5 LPA. The average package was around INR 8 LPA. Top recruiters included TCS, IBM, and Wipro, showcasing good industry participation in the placement process.

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Saveetha Engineering College concluded the placements for the Class of 2025 with an average package of INR 5.36 LPA. The salary package offered during Saveetha Engineering College placements 2025 are tabulated below:

The maximum no. of emission lines =  [n (n–1)] /2 =  [6 (6–1)] / 2 =3 × 5 = 15

The transitions that take place are as follows:

Saveetha Engineering College has released the placement report for the Class of 2025. The key highlights of are tabulated below:

BTech is a well-known course of Saveetha Engineering College, Greater Chennai. As per the latest report, one student of the BTech AIDS batch 2025 received the highest package of INR 36 LPA during the 2025 placement session. Check out the key highlights of Saveetha Engineering College placements for the Class of 2025 in the table below:

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Disclaimer: This information is sourced from the official website/ sanctioning body and may vary.

IITDM Kurnool JEE Main cutoff 2025 concluded with the release of the final round cutoff list for admission to various BTech specialisations. For the General AI category, the overall cutoff ranged from 30326 to 94749. 

In the table below, students can find the cutoff range for different categories according to the closing ranks of the first and last round. 

Yes, Saveetha Engineering College offers decent placements annually for its BTech, M.Tech and MBA courses. As per the latest report, the the highest and average package offered during Saveetha Engineering College placements in 2025 stood at INR 36 LPA and INR 5.36 LPA, respectively. The key highlights of Saveetha Engineering College placements for the Class of 2025 are tabulated below:

Although official 2024 placement data for BTech at Integral University hasn't been released, student reviews on Shiksha indicate a strong placement rate of approximately 98%. This suggests that most BTech students secured jobs, reflecting positively on the university's industry connections and the effectiveness of its engineering programmes in preparing students for employment.

According to Balmer formula,

Wave number (? ) = R_H [1/n₁²  - 1/n₂² ]cm^-1

= 109678 [1/2² – 1/4²] cm^-1

= (109678 x 3) / 16 cm^-1

λ = 1 /? = 16 / (109678 x 3) cm = 16 x 10⁷ / (109678 x 3) nm = 486 nm