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Density = $\frac{mass}{volume}$

Cu > Co > Fe > Cr > Zn

If candidates miss their VSAT admit card, they can reach the exam body officials immediately and ask them for a redressal. However, if students don't get a response from the officials, they must reach out to the conducting body in person and explain their situation. Candidates will have to request for a duplicate admit card to them.

Yes, candidates must carry the any of the ID proof along with the PIM MAT admit card. The ID cards are used for the verification process. Candidates failing to bring any of the document will be not be allowed to take the examination. On the day of the examination, candidates must be carrying any of the below ID proof:

1. Voter's ID Card
2. Aadhar Card
3. Passport
4. Driving License
5. PAN Card
6. Any other id proofs issued by the academic institutions

Kindly consider the following figure

Infrared radiation is a part of the electromagnetic spectrum which is specifically used in night detection techniques to enhance visibility. They have a wavelength of around 700 nm to 1 mm and have a frequency range of around 10^12 Hz.

No, there is no such provision of a duplicate admit card of VSAT exam. There is only one admit card, however, if candidates think they might miss on their admit card, they download two copies and keep one copy safe.

Freundlich adsorption isotherm

$\frac{x}{m}=k{p}^{1/n}$

$log\frac{x}{m}=\frac{1}{n}logp+logk$

Comparing with y = mx + C

so, slope of given graph is $\frac{1}{n}$ $\frac{}{}$ whose value varies from 0 to 1.

Sphalerite is ore of zinc consists of ZnS during its concentration group 1 cyanides are used as depressants like NaCN

Major components of gun metal are Cu, Sn and Zn

There are different types of electromagnetic waves and each of them have different wavelengths. Human eye can only see the light rays which have a minimum wavelength of around 400-700nm. Rays which don't meet this threshold will eventually not be visible to the humans.

From option let it be isosceles where AB = AC then

$x=\sqrt[]{r^2-{\left(h-r\right)}^2}$            

 =   $\sqrt[]{r^2-h^2-r^2+2rh}$

$x=\sqrt[]{2hr-h^2}........\left(i\right)$        

Now ar $\left(\Delta ABC\right)=\Delta =\frac{1}{2}BC\times AL$

$\Delta =\frac{1}{2}\times 2\sqrt[]{2hr-a^2}\times h$       

then   $x=\sqrt[]{2\times \frac{3r}{2}\times r-\frac{9r^2}{4}}=\frac{\sqrt[]{3}}{2}rfrom\left(i\right)$

$\Rightarrow BC=\sqrt[]{3}r$      

So . $AB=\sqrt[]{h^2+x^2}=\sqrt[]{\frac{9r^2}{4}+\frac{3r^2}{4}}=\sqrt[]{3}r$

Hence $\Delta$ be equilateral having each side of length $\sqrt[]{3}r.$  

Along with the VSAT admit card, candidates can carry any one government issued photo ID such as - 

• Aadhar card
• Voter ID card
• Passport
• Driving License
• Pan card, etc.

${?}_1=\frac{3}{5}{E}_0\left(0.2\right)N{m}^2{C}^{-1},and{?}_2=\frac{4}{5}{E}_0\left(0.3\right)N{m}^2{C}^{-1}$

$\Rightarrow \frac{{?}_1}{{?}_2}=\frac{3\times 0.2\times 5}{5\times 0.3\times 4}=\frac{1}{2}$

Let v is velocity at the highest position.

$T_{max}=5T_{min}\Rightarrow mg+\frac{m\left(v^2+4g\mathcal{l}\right)}{\mathcal{l}}=5\left(\frac{m{v}^2}{\mathcal{l}}-mg\right)\Rightarrow 4.\frac{v^2}{\mathcal{l}}=10g$

$\Rightarrow v=\sqrt[]{\frac{5}{2}g\mathcal{l}}=\sqrt[]{\frac{5}{2}\times 10\times 1}=5m/s$

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It depends on the frequency of the wave. Rays such as Gamma rays, X-Rays etc. have higher frequencies which can lead to harmful impacts if exposed to the human body. These kind of rays cannot be even produced easily unlike low frequency rays.

$\Delta U+\Delta KE=0$

$\Rightarrow \frac{f}{2}nR\Delta T=\frac{1}{2}m{v}^2\Rightarrow \Delta T=\frac{m}{n}\frac{v^2}{fR}=4\times 10^{-3}\times \frac{30^2}{3R}=\frac{3.6}{3R}K.$

The following are the topics covered in this chapter: Electric Field and Field Lines, Gauss's Law, Electric Dipole, Conductors and Insulators, and Electric Flux.