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This is a  Fill in the Blanks Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}?P\left(A/B\right)=\frac{P\left(A\cap B\right)}{P\left(B\right)}\\ \Rightarrow P\left(A\right)=\frac{P\left(A\cap B\right)}{P\left(B\right)}\\ \Rightarrow P\left(A\cap B\right)=P\left(A\right).P\left(B\right)\\ So,AisindependentofB.\end{array}$

This is a multiple choice answer as classified in NCERT Exemplar

Correct option (i)

The compound has the following number of electrons:

NO₃^-  =  32e^- 

CO₃^2-  =  32e^- 

ClO₃^-  =  42e^- 

SO₃ ^-  =  42e^- 

Hence,  NO₃^- and CO₃^2-  are isoelectronic

This is a  Fill in the Blanks Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Var\left(X\right)=E\left(X^2\right)-{\left[E\left(X\right)\right]}^2\\ ={{\displaystyle \sum _{}^{}{X}^{2}P\left(X\right)-\left[{\displaystyle \sum _{}^{}X.P\left(X\right)}\right]}}^2={\displaystyle \sum _{}^{}{p}_i{x}_i^2}-{\left({\displaystyle \sum _{}^{}{p}_i{x}_i}\right)}^2\\ Hence,Var\left(X\right)isequalto{\displaystyle \sum _{}^{}{p}_i{x}_i^2}-{\left({\displaystyle \sum _{}^{}{p}_i{x}_i}\right)}^2.\end{array}$

This is a multiple choice answer as classified in NCERT Exemplar

Correct option (iii)

If an electron pair is donated to a vacant orbital on one atom and a lone pair of electrons on the other, the bonding is designated pπ-dπ depending on the orbital to which the electron pair is donated and the orbital from which the electron pair is donated.

Because their valence shells lack d-orbitals, nitrogen, carbon, and boron cannot form a pi bond. Phosphorus, on the other hand, can produce pi bonds.

This is a  Fill in the Blanks Type Questions as classified in NCERT Exemplar

Sol:

This is a  Fill in the Blanks Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Here,P\left(A\text{'}\cup B\text{'}\right)=\frac{2}{3}andP\left(A\cup B\right)=\frac{5}{9}\\ \therefore 1-P\left(A\cap B\right)=\frac{2}{3}\\ \Rightarrow P\left(A\cap B\right)=1-\frac{2}{3}=\frac{1}{3}\\ NowP\left(A\text{'}\right)+P\left(B\text{'}\right)=1-P\left(A\right)+1-P\left(B\right)=2-\left[P\left(A\right)+P\left(B\right)\right]\\ =2-\left[P\left(A\cup B\right)+P\left(A\cap B\right)\right]\\ =2-\left[\frac{5}{9}+\frac{1}{3}\right]=2-\frac{8}{9}=\frac{10}{9}\\ Hence,thevalueofthefilleris\frac{10}{9}.\end{array}$

This is a  Fill in the Blanks Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhat:P\left(A\right)=p,P\left(B\right)=\frac{1}{3}andP\left(A\cup B\right)=\frac{5}{9}\\ P\left(A/B\right)=\frac{P\left(A\cap B\right)}{P\left(B\right)}=p\Rightarrow P\left(A\cap B\right)=p.P\left(B\right)=p.\frac{1}{3}\\ andP\left(A\cup B\right)=P\left(A\right)+P\left(B\right)-P\left(A\cap B\right)\\ \frac{5}{9}=p+\frac{1}{3}-\frac{p}{3}\Rightarrow \frac{5}{9}-\frac{1}{3}=\frac{2p}{3}\Rightarrow \frac{2}{9}=\frac{2p}{3}\Rightarrow p=\frac{1}{3}\\ Hence,pisequalto\frac{1}{3}.\end{array}$

This is a multiple choice answer as classified in NCERT Exemplar

Correct option (ii)

When H₂S is passed through an aqueous solution of salt acidified with dil. HCl in qualitative analysis, a black precipitate is produced. When the precipitate is boiled with dil. HNO3, a blue solution results. When an excess of ammonia aqueous solution is added to this solution, it produces a deep blue  [Cu (NH₃)₄]²⁺  solution.

Kirori Mal College is affiliated with the University of Delhi (DU). Admission to the BSc course at KMC is based on the applicants' merit in CUET UG. The university has prescribed the subject combinations that one must select while appearing for CUET UG. To be eligible for admission, candidates must appear in CUET UG with the same/ similar subjects that they have passed Class 12 with. Candidates willing to take admission to KMC for BSc (Hons) in Chemistry must appear in CUET with the following subject combination: Physics + Chemistry + Applied Mathematics/ Mathematics.

The documents required to fill the application form for Nehru College of Nursing are: 

• Class 10 marksheet
• Class 12 marksheet 
• Graduation marksheet for the PG course
• TC
• Government Issued ID

Candidates can learn more about the application process through the official website of the institute. 

This is a True or False Type Questions as classified in NCERT Exemplar

Sol:$\begin{array}{l}{\mathrm{}}^{}\end{array}$

$\begin{array}{l}True\\ SinceP\left(atleasttwoofA,BandCoccur\right)\\ =p\times p\times \left(1-p\right)+\left(1-p\right).p.p+p\left(1-p\right).p+p.p.p\\ =3p^2\left(1-p\right)+p^3=3p^2-3p^3+p^3=3p^2-2p^3\end{array}$

Verified student reviews on Shiksha suggest that Shri Guru Ram Rai University's placement rate for the BA programme stood at 70% during the recent years' placements drive. Moreover, the the highest salary package offered to BA students stood at INR 12 LPA. To know more, students can get in touch with the university.

Applicants must fulfill the following requirements in order to be considered for admission to the courses offered by the Nehru College of Nursing: 

Step 1: Visit the official website of the institute.

Step 2: Fill out the application by visiting the "Apply Now" section. Candidates also need to fill out the KEAM form.  

Step 3: Complete the application and submit the form. 

This is a multiple choice answer as classified in NCERT Exemplar

Correct option is (iii)

Hydrogen iodide is a more powerful reducing agent than sulphuric acid, it reduces the amount of iodine in the solution from H₂SO₄ to SO₂ and HI to I₂

When chloride salts are treated with sulfuric acid,  HCl gas is formed, which produces a colourless gas.

NaCl + H₂SO₄→HCl + Na₂SO₄

Violet fumes are produced during the reaction due to the creation of iodine (I₂) gas.

2NaI + H₂SO₄→Na₂SO₄ + 2HI 2H₂O + SO₂ + I₂

This is a True or False Type Questions as classified in NCERT Exemplar

Sol:  $False\left[?P\left(B/A\right)=\frac{P\left(A\cap B\right)}{P\left(A\right)}=\frac{P\left(A\right)+P\left(B\right)-P\left(A\cup B\right)}{P\left(A\right)}>\frac{1-P\left(A\cup B\right)}{P\left(A\right)}\right]$

RRB NTPC city intimation slip gives details related to exam city only. The detailed address of RRB NTPC exam centre are mentioned in the admit card. The city intimation slip is released so that after knowing the exam city candidates can make travel plans accordingly. 

Go to the internet and find the MyACT website. You have to make a student account there. Click on the Register button. Pick a test date that is available. Upload a clear photo of your face. Pay the exam fee online. Verify details twice before you submit.