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The chemical bonds can be primary or strong bonds such as ionic, covalent, and metallic bonds. It can also be the secondary or weak bonds like hydrogen bonding, London dispersion force, and dipole interactions.

Rate of burning of fuel $\left(\frac{dm}{dt}\right)=1kg/s$  and velocity of ejected fuel

$\left(v\right)=60km/s$

$=60\times 10^{3}m/s.$  

Forcev =  Rate of change of momentum

$=\frac{dp}{dt}=\frac{d\left(m\nu \right)}{dt}=v\frac{dm}{dt}=\left(60\times 10^3\right)\times 1$

  $=60000$ N.

It is the bond that holds the ions, atoms or molecules to form stable substances, compounds and larger structures.

$\stackrel{?}{F}=e{E}_0\stackrel{?}{j}$

${\stackrel{?}{a}}_y=\frac{e{E}_0}{m}\stackrel{?}{j}$

$=v_0\stackrel{?}{i}+\left(\frac{e{E}_{0}t}{m}\right)\stackrel{?}{j}$

$\left|\stackrel{?}{v}\right|=\sqrt[]{v_0^2+{\left(\frac{e{E}_{0}t}{m}\right)}^2}=v_0\sqrt[]{1+{\left(\frac{e{E}_{0}t}{m}\right)}^2}$

$\lambda =\frac{{\lambda }_0}{\sqrt[]{1+{\left(\frac{e{E}_{0}t}{m}\right)}^2}}$

In Chemistry, the bonds are of four types - Covalent bond, Ionic bond, Hydrogen bond, and Metallic bond.

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As per the latest employment data available on the institute's website, of the overall graduate student population, 89% students secured employment within the first six months of completing respective studies, cementing the institute's placement prowess.

Force $\left(F\right)=10N$  and acceleration

From Lenz law, current in the square loop will be in anticlockwise sense.

Direction of  is perpendicular to equipotential surface.

GRE (Graduate Record Examination) test score is accepted by the ASU Thunderbird for admission to its management courses. However, it is not a mandatory requirement for admission & waivers may be granted to students under certain conditions. The institute hasn't explicitly mentioned a minimum score requirement for admission to its management courses.

For diamagnetic ; $\chi <0andl=\chi H$

At resonance V_L = V_C

_{$\Rightarrow cos?=\frac{V_R}{\sqrt[]{V_R^2+{\left(V_L-V_C\right)}^2}}=1$}

To check the VTUEEE result, candidates will have to visit the official website and click on the result declaration link. They will have to enter their login credentials, post which the results will be displayed on the screen.

Density of nuclei is order of 10¹⁷ kg m^-3.

Photocell works on photoelectric effect.

$U_i=-\frac{GMm}{R}$

${\left(T.E.\right)}_f=-\frac{GMm}{8R}$

$\Rightarrow Energy={\left(T.E\right)}_f-\left(U_i\right)$

$=\frac{7GMm}{8R}$

$\Rightarrow \frac{R}{100}=\frac{40}{60}$

$\Rightarrow \Delta R=\left(\frac{\Delta l}{l}+\frac{\Delta l}{\left(100-l\right)}\right)R$

$=\left(\frac{0.1}{40}+\frac{0.1}{60}\right)\times 66.7=0.27=0.3$

Application forms for the upcoming academic session 2025-26 have started at ASU Thunderbird.

International students who are interested can submit their respective admission applications by Mar 30, 2025 for postgraduation courses and Jul 1, 2025, for undergraduate courses. The university advises all students to submit their application form with all necessary documents as early as possible, due to high demand and low availability of seats.

$C_1=1\mu F{V}_1=100V?U_1=\frac{1}{2}\times 1\times {10}^{-6}\times {\left(100\right)}^2=5\times {10}^{-3}J$  

$C_2=1\mu F$ , common potential $V=\frac{C_1{V}_1}{C_1{C}_2}=\frac{100}{2}=50V$

Final electrostatic energy stored in both the capacitors.

$=\frac{1}{2}\left(C_1+C_2\right)V^2=\frac{1}{2}\times 2\times {\left(50\right)}^2\times {10}^{-6}$

$=2.5\times {10}^{-3}J$

$Energylost=2.5\times {10}^{-3}$

$\%lossofenergy=\frac{2.5\times {10}^{-3}}{5\times {10}^{-3}}\times 100$

$=50\%$