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4 months ago

Physics Motion in Plane Physics

The velocity of boat m still water is 10 ms $m s^{- 1}$ . The river flow velocity is 5 ms $m s^{- 1} .$

If $_{}$ $v_{b}$ ,= velocity of boat with respect to river velocity, $v_{b} =$ $_{}$ actual velocity of boat (i.e. with respect to bank), $v_{r} =$ $_{}$ velocity of stream, then the value of $v_{b}$ $_{}$ is

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Raj Pandey

Contributor-Level 9

$v_{b} = v_{b r} + v,$

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4 months ago

Physics NCERT Exemplar Solutions Class 11th Chapter Eight Physics

A telescope with objective of focal length $100 c m$ and eyepiece of focal length $5 c m$ is focused on a far object such that parallel rays emerge from eyepiece. If object subtends an angle of $1^{0}$ on objective, the angular size of image is

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alok kumar singh

Contributor-Level 10

Magnify power of telescope for far point is given as

$m = \frac{θ_{i}}{θ_{0}} = \frac{f_{0}}{f_{e}}$

$? θ_{i} = θ_{0} (\frac{f_{0}}{f_{e}}) {= 1}^{0} (\frac{100}{5}) = 20^{0}$

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4 months ago

Physics Class 11th

The correct graph between logeR and loge( - 0) during cooling of a body may be (R is the rate of cooling and 0 is surrounding temperature)

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Vishal Baghel

Contributor-Level 10

$R \propto (θ - θ_{0})$

$\Rightarrow l o g_{e} R = l o g_{e} k + l o g_{e} (θ - θ_{0})$

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4 months ago

Overview Physics Current Electricity

Resistance of given carbon resistor is

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Vishal Baghel

Contributor-Level 10

$01 \times 1 0^{4} Ω \pm 5 % = 10 \times 1 0^{3} Ω \pm 5 %$

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4 months ago

Physics NCERT Exemplar Solutions Class 11th Chapter Eight Physics

Deviation of light ray by a thin prism of refractive index $μ$ and refracting angle $A$ is

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alok kumar singh

Contributor-Level 10

For thin prism, deviation $= (μ - 1) A$

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4 months ago

Physics Class 11th

If force (F), mass (M), length (L) are taken as fundamental quantities, dimensions of time will be

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Vishal Baghel

Contributor-Level 10

$F = m a = \frac{M L}{T^{2}}$

$\Rightarrow T^{2} = \frac{M L}{F}$

$\Rightarrow [T] = ⌊ M^{1 / 2} L^{1 / 2} F^{- 1 / 2} ⌋$

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4 months ago

Physics NCERT Exemplar Solutions Class 11th Chapter Eight physics ncert solutions class 11th

The radius of circle, the period of revolution $T$ , initial position and sense of revolution are indicated in the figure. x-projection of the radius vector of rotating particle $P$ is

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alok kumar singh

Contributor-Level 10

$ω = \frac{2 π}{T} = \frac{π}{5} r a d / s$

$\bar{θ} (a t t = 0) = 0^{0}$

$x = 5 \sin ? ω t$

$x = 5 \sin ? (\frac{π}{5} t)$

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4 months ago

Physics Ncert Solutions Class 12th Semiconductor Electronics: Materials, Devices and

What is the current through an ideal P – N junction diode shown in figure below?

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Vishal Baghel

Contributor-Level 10

$\Rightarrow l = \frac{2}{50} = 40 m A$

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4 months ago

Engineering VTUEEE

When will VTUEEE registrations start?

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Nishtha Chaudhary

Contributor-Level 7

The VTUEEE registrations is expected to start soon. We will share all the dates of the VTUEEE registrations, as and when it is out.

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4 months ago

Physics Motion in Straight Line Physics

The velocity of a particle is given by $v = \sqrt[]{180 - 16 x} m / s$ . Its acceleration will be

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Raj Pandey

Contributor-Level 9

$V = \sqrt[]{180 - 16 x} m / sec$

$ac c^{n} = V \frac{d v}{d x}$

$= {(180 - 16 x)}^{1 / 2} \frac{d {(180 - 16 x)}^{1 / 2}}{d x}$

= ${(18 - 16 x)}^{1 / 2} \times \frac{1}{2} {(180 - 16 x)}^{1 / 2} \times - 16$

= $? 8 m / s e c^{2}$

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4 months ago

Alternating Current Overview Physics

The value of alternating emf (E) in the given circuit will be

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Vishal Baghel

Contributor-Level 10

$E = \sqrt[]{V_{R}^{2} + {(V_{L} - V_{C})}^{2}}$

$E = \sqrt[]{{(60)}^{2} + {(100 - 20)}^{2}}$

E = 100V

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4 months ago

Physics NCERT Exemplar Solutions Class 11th Chapter Eight Physics

Two conducting rods inclined at $' θ'$ angle from horizontal are kept parallel at separation $' l'$ to each other. A resistor of resistance $R$ joins the two rods at their topmost point. A metal bar of length $' l'$ is free to slide on the rods as shown in figure. on releasing from rest, the maximum speed that can be attained by the bar if a constant magnetic field $B$ exists vertically downwards, is

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alok kumar singh

Contributor-Level 10

$F = i l \times B$

$? m g \sin ? θ = i l \times B$

$? m g \sin ? θ = (\frac{B \cos ? θ l v}{R}) l B \cos ? θ$

$? V = \frac{R m g \sin ? θ}{B^{2} l^{2} \cos^{2} ? θ}$

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4 months ago

Physics Class 12th

A farsighted person cannot focus distinctly objects closer than 100cm. The lens that will permit him to read from a distance of 50cm, will have a focal length:

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Vishal Baghel

Contributor-Level 10

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

$\Rightarrow \frac{1}{f} = \frac{1}{- 100} - \frac{1}{- 50} = \frac{1}{50} - \frac{1}{100}$

$\Rightarrow f = + 100 c m$

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4 months ago

Electrostatics Physics Electrostatic Potential and Capacitance

Figure shown four plates each of area A and separated from another by a distance d. What is the capacitance between P and Q?

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Vishal Baghel

Contributor-Level 10

$C_{e q} = 2 C = \frac{2 A ε_{0}}{d}$

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4 months ago

Scalars and Vectors Physics Motion in Plane

If $a \cdot b = | a \times b |$ , then the $θ$ angle between a and b will be

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Raj Pandey

Contributor-Level 9

$a \cdot b = | a \times b | a b$ $cos θ = a b sin θ$

$\frac{\underline{a b}}{\underline{a b}} = \frac{s i n θ}{c o s θ}$

$tan θ = 1$

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4 months ago

Physics NCERT Exemplar Solutions Class 11th Chapter Eight Overview

Consider the following two statements .

(A)The gravitational force on a particle inside a spherical shell is zero.

(B) Total mechanical energy of a body on earth’s surface may be positive.

Which of the following options is correct?

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alok kumar singh

Contributor-Level 10

Inside a spherical shell gravitational field is zero, so net force acting on a particle placed inside it is also zero.

Total energy of a bound system is always negative.

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4 months ago

Physics Class 11th

A body possesses kinetic energy x, moving on a rough horizontal surface, is stopped in a distance y. The friction force exerted on the body is

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Vishal Baghel

Contributor-Level 10

Work done = $Δ K E$

$\Rightarrow - f = - x$

$\Rightarrow f = \frac{x}{y}$

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4 months ago

Physics Motion in Plane Physics NCERT Exemplar Solutions Class 11th Chapter Eight

A man who can swim with a speed of $2 k h / h$ wants to cross a river $200 m$ wide. If the river is flowing with a speed of $3 k m / h$ then in what minimum time can the man cross the river?