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New Question

a month ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

v b = v b r + v ,

New Question

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Magnify power of telescope for far point is given as

m = θ i θ 0 = f 0 f e

? θ i = θ 0 f 0 f e = 1 0 100 5 = 20 0

New Question

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

R ( θ θ 0 )

l o g e R = l o g e k + l o g e ( θ θ 0 )

New Question

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

0 1 × 1 0 4 Ω ± 5 % = 1 0 × 1 0 3 Ω ± 5 %

New Question

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

For thin prism, deviation = μ - 1 A

New Question

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

F = m a = M L T 2

T 2 = M L F

[ T ] = M 1 / 2 L 1 / 2 F 1 / 2

New Question

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

ω = 2 π T = π 5 r a d / s

θ ¯ a t t = 0 = 0 0

x = 5 sin ? ω t

x = 5 sin ? π 5 t

 

New Question

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

l = 2 5 0 = 4 0 m A

New Question

a month ago

0 Follower 1 View

N
Nishtha Chaudhary

Contributor-Level 7

The VTUEEE registrations is expected to start either in October or November 2025. We will share all the dates of the VTUEEE registrations, as and when it is out.

New Question

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

V=18016xm/ sec 

accn=Vdvdx

= ( 1 8 0 1 6 x ) 1 / 2 d ( 1 8 0 1 6 x ) 1 / 2 d x

= ( 1 8 1 6 x ) 1 / 2 × 1 2 ( 1 8 0 1 6 x ) 1 / 2 × 1 6

= ? 8 m/sec2

New Question

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

E = V R 2 + ( V L V C ) 2

E = ( 6 0 ) 2 + ( 1 0 0 2 0 ) 2

E = 100V

New Question

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

F = i l × B

? m g sin ? θ = i l × B

? m g sin ? θ = B cos ? θ l v R l B cos ? θ

? V = R m g sin ? θ B 2 l 2 cos 2 ? θ

 

New Question

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

1 f = 1 v 1 u

1 f = 1 1 0 0 1 5 0 = 1 5 0 1 1 0 0

f = + 1 0 0 c m

New Question

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

C e q = 2 C = 2 A ε 0 d

New Question

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

a b = | a × b | a b  cos θ=ab sin θ

a b _ a b _ = s i n θ c o s θ

 tan θ=1

New Question

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Inside a spherical shell gravitational field is zero, so net force acting on a particle placed inside it is also zero.

Total energy of a bound system is always negative.

New Question

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Work done = Δ K E

f = x

f = x y

New Question

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Time (minimum) taken to cross the river

t = W V s / r = 200 × 10 - 3 2

100 × 10 - 3 h

= 0.1 h = 6 m i n u t e s

New Question

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

F = q E a = q E m

s = 1 2 a t 2 = 1 2 ( q E m ) t 2

W o r k d o n e = Δ K

Δ K = F . s = q 2 E 2 t 2 2 m

New Question

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

f l = μ N = 0 . 6 × m g c o s θ f l = 0 . 6 × 2 × 1 0 × 4 5 = 9 . 6 N

Component of weight along incline.

= m g s i n θ = 2 × 1 0 × 3 5 = 1 2 N

m g s i n θ > f l s o T = 2 . 4 N

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