Once graduated from BTech from Sri Krishnadevaraya University (SKU), students have plenty of career prospects to pursue. Both private and government sectors offer a variety of options. Some of the most sought-after government career prospects for BTech graduates from SK University include the following:

Central Government Jobs:

Indian Engineering Services (IES)
Engineering Services Examination (ESE)
Scientist Recruitment Board (SRB)

Other Government Jobs:

Railways
Defence

NOTE: The above-mentioned data is taken from the various sources. It is still subject to change and, hence, is indicative.

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11 months ago

Lingaya’s Vidyapeeth

What is the placement scenario at Lingaya’s Vidyapeeth?

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Shoaib Mehdi

Contributor-Level 10

The placement scenario is consistently strong, with students placed in diverse sectors such as IT, Core Engineering, AI/ML, Healthcare, Management, and Finance. Pre-placement training and industry collaborations enhance employability. The key highlights of Lingaya's Vidyapeeth placements for the Class of 2024 and 2025 are tabulated below:

Particulars	Placement Statistics (2024)	Placement Statistics (2025)
Highest package	INR 8 LPA	INR 15 LPA
Total students	1,020	11,00
Students placed	564	650

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11 months ago

Why to choose KL University Guntur?

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Kartik Shekhar

Contributor-Level 10

KL University offer high placement rates, especially for CSE and other IT-related courses. The university is accredited by the NAAC with an A+ grade. It has well-equipped labs, a library, etc. and a qualified faculty with experience in their respective fields. KL University has collaborations with top companies like Microsoft, IBM, and Cisco, providing students with valuable industry connections and learning opportunities.

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11 months ago

BSc Nursing

Where can I find the rank list for admission to B.Sc Nursing course 2024-2025 under NRI quota?

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11 months ago

Waves physics ncert solutions class 11th

15.12 (i) For the wave on a string described in Exercise 15.11, do all the points on the string oscillate with the same (a) Frequency (b) Phase (c) Amplitude? Explain your answers.

(ii) What is the amplitude of a point 0.375 m away from one end

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Vishal Baghel

Contributor-Level 10

(i)

(a) All the points on the string oscillates with the same frequency, except at the nodes, which have zero frequency

(b) All the points in any vibrating loop have the same phase, except at the nodes.

(c) All the points in any vibrating loop will have different amplitudes of vibration.

(ii)

The given equation is: y (x, t) = 0.06 sin ( $\frac{2 π}{3} x)$ cos (120 $π t)$

For x = 0.375 and t =0

Amplitude = Displacement = 0.06 sin ( $\frac{2 π}{3} \times \times 0.375)$ cos (0 $)$ = 0.06sin ( $\frac{π}{4})$ = 0.042 m

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11 months ago

Accounting & Commerce B.Com

Are BCom seats at NPU Jharkhand evenly distributed across colleges?

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Himanshu Singh

Contributor-Level 10

No, BCom seat distribution at NPU Jharkhand is not uniform across its affiliated colleges. While institutions like S.P.D. College and Sant Tulsi Dash College offer 1,000 and 600 seats respectively, others such as Gopinath Singh Mahila College offer as few as 14.

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11 months ago

Sri Krishnadevaraya University B.Tech

What is the fee for a four-year BTech at SK University?

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Nidhi Madavi

Contributor-Level 10

The tuition fee for the SK University BTech for the entire four-year course duration ranges from INR 1.4 Lacs to INR 2.8 lakh. However, apart from the tuition fee, there are various fee elements that are involved in the total course fee. These elements could include the admission fee, security charges, and other one-time charges. Hence, candidates are required to remit this course fee to confirm their enrollment.

NOTE: The aforementioned fee is taken from the official website/sanctioning body. It is still subject to change and, hence, is indicative.

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11 months ago

Humanities & Social Sciences B.A

What are the parameters that can be considered for BA colleges while comparing it with PTSNS University?

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Virajita Madavi

Contributor-Level 10

There are certain parameters that are widely used for college comparison. Pandit SN Shukla University BA aspirants with other preferences can compare to calculate the return on investment. It shall help in making a sound decision. Some of the parameters that can be considered are:

Fees
Placements
Faculty
Location
Student Reviews, etc.

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11 months ago

Waves physics ncert solutions class 11th

15.11 The transverse displacement of a string (clamped at its both ends) is given by

y(x, t) = 0.06 sin( $\frac{2 π}{3} x)$ cos (120 $π t)$

where x and y are in m and t in s. The length of the string is 1.5 m and its mass is 3.0 ×10^–2 kg.

Answer the following :

(a) Does the function represent a travelling wave or a stationary wave?

(b) Interpret the wave as a superposition of two waves travelling in opposite directions. What are the wavelength, frequency, and speed of each wave ?

(c) Determine the tension in the string

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Vishal Baghel

Contributor-Level 10

(a) The general equation representing a stationary wave is given by the displacement function y(x,t) = 2asin kx cos $ω t$

The equation is similar to the give equation y(x, t) = 0.06 sin ( $\frac{2 π}{3} x)$ cos (120 $π t)$

Hence, the given function represents a stationary wave.

A wave travelling along the positive x-direction is given as: $y_{1}$ = asin ( $ω$ t – kx)

The wave travelling along the negative x-direction is given as: $y_{2}$ = asin ( $ω$ t + kx)

(b) The superposition of these two waves yields:

y = $y_{1} + y_{2}$ = asin ( $ω$ t – kx) + asin ( $ω$ t + kx)

= a sin( $ω$ t)cos(kx) – a sin

...more

(a) The general equation representing a stationary wave is given by the displacement function y(x,t) = 2asin kx cos $ω t$

The equation is similar to the give equation y(x, t) = 0.06 sin ( $\frac{2 π}{3} x)$ cos (120 $π t)$

Hence, the given function represents a stationary wave.

A wave travelling along the positive x-direction is given as: $y_{1}$ = asin ( $ω$ t – kx)

The wave travelling along the negative x-direction is given as: $y_{2}$ = asin ( $ω$ t + kx)

(b) The superposition of these two waves yields:

y = $y_{1} + y_{2}$ = asin ( $ω$ t – kx) + asin ( $ω$ t + kx)

= a sin( $ω$ t)cos(kx) – a sin(kx)cos( $ω$ t) – asin( $ω$ t)cos(kx) – asin(kx)cos( $ω$ t)

= -2a sin (kx) cos ( $ω$ t)

= -2asin( $\frac{2 π}{λ}$ x) cos (2 $π ν$ t) …….(i)

The transverse displacement of the string is given as

y(x, t) = 0.06 sin ( $\frac{2 π}{3} x)$ cos (120 $π t) \dots \dots \dots$ (ii)

Comparing equations (i) and (ii), we have $\frac{2 π}{λ}$ = $\frac{2 π}{3}$

Therefore $λ$ = 3m, it is given that 120 $π$ = 2 $π ν$ so Frequency, $ν = 60 H z$

Wave speed, v = $ν λ$ = 60 $\times 3$ = 180 m/s

The velocity of a transverse wave travelling in a string is given by the relation:

v = $\sqrt{\frac{T}{μ}}$ ….(i)

We have v = 180 m/s, mass of the string, m = 3 $\times 10^{- 2}$ kg,

length of the string, l = 1.5 m

Mass per unit length of the string, $μ$ = m/l = $\frac{3}{1.5} \times 10^{- 2}$ = $2 \times 10^{- 2}$ kg/m

(c) Tension in the string, T = $v^{2}$ $\times μ = 180^{2}$ $\times 2 \times 10^{- 2}$ = 648 N

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11 months ago

Design Fashion Design

Do the Fashion Design colleges in Delhi NCR offer UG Diploma courses?

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Tasbiya Khan

Contributor-Level 10

Yes, there are about 80+ best Fashion Design colleges in Delhi NCR offer UG Diploma courses. SOme of them are mentioned below along with their tuition fees:

Top Colleges	Tuition Fee
JD Institute of Fashion Technology	INR 71,000 - INR 5 lakh
World University of Design	INR 2 lakh
IGNOU - Indira Gandhi National Open University	INR 7,000
AAFT	INR 2 lakh
New Delhi YMCA, Institute for Fashion Technology and Design	INR 79,000 - INR 2 lakh

Disclaimer: This information is sourced from official website and may vary.

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11 months ago

Waves physics ncert solutions class 11th

15.10 For the travelling harmonic wave

y(x, t) = 2.0 cos 2 (10t – 0.0080 x + 0.35)

where x and y are in cm and t in s. Calculate the phase difference between oscillatory motion of two points separated by a distance of

(a) 4 m

(b) 0.5 m

(c) $λ$ /2

(d) 3 /4

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Vishal Baghel

Contributor-Level 10

The equation for a travelling harmonic wave is given by

y(x, t) = 2.0 cos 2 $π$ (10t – 0.0080 x + 0.35) or

= 2.0 cos (20 $π$ t – 0.016 $π$ x + 0.70 $π$ )

Comparing with classical equation y (x, t) = a $\sin ? (ω t + k x + φ)$ , we get

Amplitude a = 2.0 cm. Propagation constant, k = 0.016 $π$ , angular frequent, $ω = 20 π r a d / s$

From the relation $φ = k x = \frac{2 π}{λ} x$

(a) For x = 4 m = 400 cm, we have $φ$ = 0.016 $π \times 400$ = 6.4 $π$ rad

(b) For x = 0.5 m = 50 cm, we have $φ$ = 0.016 $π \times 50$ = 0.8 $π$ rad

(c) For x = $\frac{λ}{2}$ , we have $φ = \frac{2 π}{λ} \times$ $\frac{λ}{2}$ = $π$ rad

(d) For x = $\frac{3 λ}{4}$ , we have $φ = \frac{2 π}{λ} \times$ &n

...more

The equation for a travelling harmonic wave is given by

y(x, t) = 2.0 cos 2 $π$ (10t – 0.0080 x + 0.35) or

= 2.0 cos (20 $π$ t – 0.016 $π$ x + 0.70 $π$ )

Comparing with classical equation y (x, t) = a $\sin ? (ω t + k x + φ)$ , we get

Amplitude a = 2.0 cm. Propagation constant, k = 0.016 $π$ , angular frequent, $ω = 20 π r a d / s$

From the relation $φ = k x = \frac{2 π}{λ} x$

(a) For x = 4 m = 400 cm, we have $φ$ = 0.016 $π \times 400$ = 6.4 $π$ rad

(b) For x = 0.5 m = 50 cm, we have $φ$ = 0.016 $π \times 50$ = 0.8 $π$ rad

(c) For x = $\frac{λ}{2}$ , we have $φ = \frac{2 π}{λ} \times$ $\frac{λ}{2}$ = $π$ rad

(d) For x = $\frac{3 λ}{4}$ , we have $φ = \frac{2 π}{λ} \times$ $\frac{3 λ}{4}$ = $1.5 π$ rad

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11 months ago

Accounting & Commerce B.Com

How many BCom seats are available at NPU Jharkhand in 2025?

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Himanshu Singh

Contributor-Level 10

In 2025, Nilamber Pitambar University (NPU) Jharkhand offers a total of 3,314 BCom seats across its affiliated colleges. These seats are distributed among several institutions throughout the region, allowing students from different areas to access undergraduate commerce education.

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11 months ago

Waves physics ncert solutions class 11th

15.9 For the wave described in Exercise 15.8, plot the displacement (y) versus (t) graphs for x = 0, 2 and 4 cm. What are the shapes of these graphs? In which aspects does the oscillatory motion in travelling wave differ from one point to another: amplitude, frequency or phase ?

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Vishal Baghel

Contributor-Level 10

All the waves have different phases. The given transverse harmonic wave is:

y(x, t) = 3.0 sin (36t + 0.018x + $\frac{π}{4}$ ) ………(i)

For x = 0, the equation reduces to

y (0,t) = 3.0 sin (36t + $\frac{π}{4}$ )

Also $ω$ = $\frac{2 π}{T}$ , so T = $\frac{2 π}{ω}$ = $\frac{2 π}{36}$ = $\frac{π}{18}$ s

For plotting y vs., t graphs using different values of t, we get

When t = 0, y = 2.12

t = $\frac{T}{8}$ = $\frac{π}{18 \times 8}$ , y = 3

t = $\frac{2 T}{8}$ = $\frac{2 \times π}{18 \times 8}$ , y = 2.12

t = $\frac{3 T}{8}$ = $\frac{3 \times π}{18 \times 8}$ , y = 0

t = $\frac{4 T}{8}$ = $\frac{4 \times π}{18 \times 8}$ , y = -2.12

t = $\frac{5 T}{8}$ = $\frac{5 \times π}{18 \times 8}$ , y = -3

t = $\frac{6 T}{8}$ = $\frac{6 \times π}{18 \times 8}$ , y = -2.12

t = $\frac{7 T}{8}$ = $\frac{7 \times π}{18 \times 8}$ , y = 0

For x

...more

All the waves have different phases. The given transverse harmonic wave is:

y(x, t) = 3.0 sin (36t + 0.018x + $\frac{π}{4}$ ) ………(i)

For x = 0, the equation reduces to

y (0,t) = 3.0 sin (36t + $\frac{π}{4}$ )

Also $ω$ = $\frac{2 π}{T}$ , so T = $\frac{2 π}{ω}$ = $\frac{2 π}{36}$ = $\frac{π}{18}$ s

For plotting y vs., t graphs using different values of t, we get

When t = 0, y = 2.12

t = $\frac{T}{8}$ = $\frac{π}{18 \times 8}$ , y = 3

t = $\frac{2 T}{8}$ = $\frac{2 \times π}{18 \times 8}$ , y = 2.12

t = $\frac{3 T}{8}$ = $\frac{3 \times π}{18 \times 8}$ , y = 0

t = $\frac{4 T}{8}$ = $\frac{4 \times π}{18 \times 8}$ , y = -2.12

t = $\frac{5 T}{8}$ = $\frac{5 \times π}{18 \times 8}$ , y = -3

t = $\frac{6 T}{8}$ = $\frac{6 \times π}{18 \times 8}$ , y = -2.12

t = $\frac{7 T}{8}$ = $\frac{7 \times π}{18 \times 8}$ , y = 0

For x = 2 and x = 4. The phases of the three waves will get changed, frequency and amplitude will remain unchanged for any change of x.

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11 months ago

Waves physics ncert solutions class 11th

15.8 A transverse harmonic wave on a string is described by

y(x, t) = 3.0 sin (36 t + 0.018 x + $π$ /4)

where x and y are in cm and t in s. The positive direction of x is from left to right.

(a) Is this a travelling wave or a stationary wave? If it is travelling, what are the speed and direction of its propagation?

(b) What are its amplitude and frequency?

(c) What is the initial phase at the origin?

(d) What is the least distance between two successive crests in the wave?

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Vishal Baghel

Contributor-Level 10

The equation of a progressive wave travelling from right to left is given by the displacement function:

y (x, t) = a $\sin ? (ω t + k x + φ)$ ……….(i)

The given equation is

y(x, t) = 3.0 sin (36 t + 0.018 x + $π$ /4) …….(ii)

On comparing equations (i) and (ii), we find that the equation (ii) represents a travelling wave, propagating from right to left. Now, using equations (i) and (ii), we can write

$ω = 36 r a d / s$ , k = 0.018 $m^{- 1}$

From the relation $ν = \frac{ω}{2 π}$ and $λ = \frac{2 π}{k}$ and v = $ν λ$ , we can write

v = $\frac{ω}{2 π} \times$ $\frac{2 π}{k}$ = $\frac{ω}{k}$ = $\frac{36}{0.018}$ = 2000 cm /s = 20 m/s

Hence, the speed of the given travelling wave is 2

...more

The equation of a progressive wave travelling from right to left is given by the displacement function:

y (x, t) = a $\sin ? (ω t + k x + φ)$ ……….(i)

The given equation is

y(x, t) = 3.0 sin (36 t + 0.018 x + $π$ /4) …….(ii)

On comparing equations (i) and (ii), we find that the equation (ii) represents a travelling wave, propagating from right to left. Now, using equations (i) and (ii), we can write

$ω = 36 r a d / s$ , k = 0.018 $m^{- 1}$

From the relation $ν = \frac{ω}{2 π}$ and $λ = \frac{2 π}{k}$ and v = $ν λ$ , we can write

v = $\frac{ω}{2 π} \times$ $\frac{2 π}{k}$ = $\frac{ω}{k}$ = $\frac{36}{0.018}$ = 2000 cm /s = 20 m/s

Hence, the speed of the given travelling wave is 20 m/s

The frequency $ν = \frac{ω}{2 π}$ = $\frac{36}{2 π}$ = 5.73 Hz

Comparing equation (i) and (ii), we get

$φ$ = $\frac{π}{4}$

The distance between two successive crests or troughs is equal to the wavelength of the wave.

Wavelength $λ = \frac{2 π}{k}$ = $\frac{2 π}{0.018}$ = 349.07 cm = 3.49 m

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11 months ago

Virohan Lingaya's Vidyapeeth University, Faridabad

Is Lingaya’s Vidyapeeth known for its placement opportunities? Which top companies recruit students from Lingaya’s Vidyapeeth?

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Shoaib Mehdi

Contributor-Level 10

Yes, Lingaya’s Vidyapeeth is well known University in Faridabad for offering placement supprot to all of its students. The Training & Placement Cell of the University ensures that students are equipped with the right skills to meet industry demands. Check out the sector-wise top recruiters:

IT and Technology- Accenture, HCL, Wipro, Infosys, Capgemini

Consulting and Services- Genpact, Protiviti, WNS, Cvent

E-commerce & Startups- Meesho, Square Yards, Jaro Education

Industrial & Healthcare- Adani, Escorts Kubota, Sarvodhya Hospital

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11 months ago

NID Entrance Exam Design

What is the last to submit the NID B.Des Campus Preference 2025?

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Sayeba Naushad

Contributor-Level 10

The last date to submit the NID B.Des 2025 Campus/Institute Prefrence is May 19, 2025, 5 PM. The Submission window opened on May 16, 2025, 4 PM and will close on May 19, 2025, 5 PM. Window was activated with the declaration of NID B.Des Final Result.

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11 months ago

Waves physics ncert solutions class 11th

15.7 A hospital uses an ultrasonic scanner to locate tumours in a tissue. What is the wavelength of sound in the tissue in which the speed of sound is 1.7 km s^–1 ? The operating frequency of the scanner is 4.2 MHz.

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Vishal Baghel

Contributor-Level 10

Speed of sound in tissue, v = 1.7 km/s = 1.7 $\times 10^{3}$ m/s

Operating frequency of the scanner, $ν$ = 4.2 MHz = 4.2 $\times 10^{6}$ Hz

The wavelength of sound in the tissue is given as:

$λ = \frac{v}{ν}$ = $\frac{1.7 \times 10^{3}}{4.2 \times 10^{6}}$ = 4.05 $\times 10^{- 4}$ m

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11 months ago

Siva Sivani Degree College Telangana

How can I get admission to the Siva Sivani Degree College Hyderabad (SSDCH) BBA course?

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Mamona Mishra

Contributor-Level 9

Siva Sivani Degree College Hyderabad (SSDCH) admission is done based on the candidate's performance in the last qualifying exam, i.e., Class 12. The college offers four undergraduate programmes in full-time and regular modes. The college's admission process commences online via its official website. Students are selected based on academic merit in the last qualifying exam. Further, candidates seeking admission to the BBA programme must be Class 12 passed from a recognised board.

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11 months ago

Guru Gobind Singh Indraprastha University Engineering

Are there any openings for admission in B.Tech CSE at GGSIPU?

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