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11 months ago

0 Follower 8 Views

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11 months ago

0 Follower 3 Views

N
Nishtha Hazarika

Contributor-Level 10

Pratibha Institute of Business Management generally does not offer direct admissions for any of its courses. Candidates need to appear for the accepted exam, such as MAH MCA CET, MAT/CAT, etc. Additionally, students must also satisfy the eligibility set by the institute to get a seat at the institute. However, students may connect with the college's help desk to obtain the relevant information about the admission procedure, including Pratibha Institute of Business Management admission chances.

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11 months ago

0 Follower 12 Views

P
Payal Gupta

Contributor-Level 10

11.35 Room temperature, T = 27 ?  = 300 K

Atmospheric pressure, P = 1 atm = 1.01 × 10 5  Pa

Atomic weight of helium atom = 4

Avogadro’s number, N A  = 6.023 × 10 23

Boltzmann’s constant, k = 1.38 × 10 - 23  J m o l - 1 K - 1

Planck’s constant, h = 6.626 × 10 - 34  Js

Average energy of a gas at temperature T is given as:

E = 3 2 kT = 3 2 × 1.38 × 10 - 23 × 300  = 6.21 × 10 - 21 J

De Broglie wavelength is given as

λ = h 2 m E  , where m = mass of He atom = A t o m i c w e i g h t A v o g a d r o ' s n u m b e r  = 4 6.023 × 10 23

m = 6.641 × 10 - 24  gm = 6.641 × 10 - 27 kg

λ = 6.626 × 10 - 34 2 × 6.641 × 10 - 27 × 6.21 × 10 - 21 = 7.29 × 10 - 11 m

We have ideal gas formula:

PV = RT

PV = kNT

V N = k T P          

Where, V = volume of the gas

N = number of moles of the gas

Mea

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11 months ago

0 Follower 2 Views

A
Atul Singh

Contributor-Level 6

A journalism internship is a hands-on training in reporting, news writing, editing, and other journalism related profiles. During internship, students work with news/media organizations. They assist with research, interview, and content for print or digital media. Interns learn about newsroom workflows and journalism ethics. 

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11 months ago

0 Follower 1 View

H
Himanshi Pandey

Contributor-Level 10

Candidates willing to secure a seat at Mahatma Gandhi Kashi Vidyapith for an MBA must undergo a multi-step process. They must first register and appear for the CUET PG exam. Candidates with valid CUET PG exam must register for admission on the university's official website. Based on their CUET PG scores, the university allocates seat to eligible candidates through a counselling process. Selected candidates must submit the prescribed fees for seat confirmation.

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11 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

11.34 Wavelength of a proton or a neutron, λ 10 - 15 m

Rest mass energy of an electron: m 0 c 2 = 0.511 MeV = 0.511 × 10 6  eV

= 0.511 × 10 6 × 1.6 × 10 - 19  J

m 0 c = 8.176 × 10 - 14 J

Planck’s constant, h = 6.626 × 10 - 34 Js

Speed of light, c = 3 × 10 8  m/s

The momentum of a proton or a neutron is given as:

p = h λ  = 6.626 × 10 - 34 10 - 15  = 6.626 × 10 - 19  kgm/s

The relativistic relation for energy (e) is given as:

E 2 = p 2 c 2 + m 0 2 c 2

= ( 6.626 × 10 - 19 ) 2 × ( 3 × 10 8 ) 2 + ( 8.176 × 10 - 14 ) 2

= 4.390 × 10 - 37 × 9 × 10 16  + 6.684 × 10 - 27

=3.951 × 10 - 20

E = 1.988 × 10 - 10  J = 1.988 × 10 - 10 1.6 × 10 - 19  eV = 1.242 × 10 9  eV = 1.242 BeV

New Question

11 months ago

0 Follower 8 Views

M
Mukul Vimal

Contributor-Level 7

Usually, the top-ranked MBA universities in Europe are extremely competitive and have a low acceptance rate. Below are the university specific details:

University

Acceptance Rate

London Business School

20%

HEC Paris

18%

HEC5 Judge Business School

31%

IE Business School

41%

IESE Business School

26%

INSEAD

30 - 35%

Imperial College Business School

15%

Oxford Said Business School

20%

SDA Bocconi School of Management

32%

Esade Business School

60%

New Question

11 months ago

0 Follower 5 Views

N
Nishtha Singh

Contributor-Level 10

To apply to Bachelor's courses, the applicants have to apply through the online portal on the uni-assist website. Additionally, do submit the documents like proof of university entrance qualification, proof of German language skills, and passport, etc. For Master's degree too, the applicants are first required to apply via uni-assist. An APS Certificate is also required for studies.

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11 months ago

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11 months ago

0 Follower 12 Views

P
Payal Gupta

Contributor-Level 10

11.33 The accelerating voltage of the electrons, V = 50 kV = 50 × 10 3  V

Mass of the electron, m e = 9.11 × 10 - 31  kg

Planck’s constant, h = 6.626 × 10 - 34  Js

Charge of an electron, e = 1.6 × 10 - 19  C

Wavelength of yellow light, λ = 5.9 × 10 - 7 m

The kinetic energy of the electron is given as, E k  = e × V  = 1.6 × 10 - 19 × 50 × 10 3  J = 8 × 10 - 15 J

De Broglie wavelength is given by the relation,

λ = h 2 × m e × E k = 6.626 × 10 - 34 2 × 9.11 × 10 - 31 × 8 × 10 - 15  = 5.5 × 10 - 12  m

This wavelength is nearly 10 5 times less than the wavelength of a yellow light.

The resolving power of a microscope is inversely proportional to the wavelength of light used. Thus, the resolving power of an electron microscope is nea

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11 months ago

0 Follower 3 Views

N
Nishtha Patra

Contributor-Level 7

It is quite competitive to get hired by top recruiters such as Taj, Oberoi, Marriott, Hyatt, ITC, Hilton, or leading cruise lines and international chains, but not impossible. 

Moreover, entry-level roles like Management Trainee (MT) courses are highly selective, often with group discussions, aptitude tests, and multi-round interviews. Cruise lines, international hotels, and airlines conduct global hiring drives, with thousands of applicants competing for a few positions. Mostly, only 10–20% of students may get placed in luxury chains or international brands during campus placements.

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11 months ago

0 Follower 9 Views

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Nupur Shukla

Contributor-Level 9

Siva Sivani Degree College Hyderabad (SSDCH) offers a wide range of programmes to students at the UG level. The college is mainly concerned with the Management, Commerce, Science, and Computer Application streams. The college offers various programmes to students such as BBA, BCom, BSc, and BBA. 

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11 months ago

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P
Payal Gupta

Contributor-Level 10

11.32 Kinetic energy of neutron, E k n == 150 eV = 150 × 1.6 × 10 - 19 J = 2.4 × 10 - 27 J

Mass of a neutron, m n = 1.675 × 10 - 27 kg

Planck’s constant, h = 6.626 × 10 - 34 Js

Kinetic energy of a neutron is given by the relation:

 = Ekn=12mnvn2……….(1)

Where, v n is the velocity of neutron

The de Broglie wavelength is given by

λ = h p , where p = momentum = m n v n

λ = h m n v n

v n = h m n λ

Substituting the value of  v n in equation (1), we get

E k n = 1 2 m n ( h m n λ ) 2 = h 2 2 m n λ 2

  λ2 = h22mnEkn

λ = h 2 2 m n E k n = h 2 m n E k n = 6.626 × 10 - 34 2 × 1.675 × 10 - 27 × 2.4 × 10 - 17  = 2.337 × 10 - 12 m

 It is given in the previous problem that the inter-atomic spacing of a crystal is about 1 Å, i.e. 10 - 10 m. Hence, the inter-atomic spacing is about 10 2  times greater. Hence, a neutron beam

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11 months ago

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P
Payal Gupta

Contributor-Level 10

11.31 Wavelength of the light emitted from probe, λ = 1 Å = 1 × 10 - 10 m

Mass of the electron, me = 9.11 × 10 - 31 kg

Planck’s constant, h = 6.626 × 10 - 34 Js

Charge of an electron, e = 1.6 × 10 - 19 C

Speed of light, c = 3 ×108
 m/s

The kinetic energy of the electron is given as :

E k = 1 2 m e v 2 ……………(1)

The de Broglie wavelength is given by

λ = h p ,where p = momentum = m e v

λ = h m e v

v = hmeλ

Substituting the value of v in equation (1), we get

E k = 1 2 m e ( h m e λ ) 2 = m e h 2 2 m e 2 λ 2 = h 2 2 m e λ 2

= ( 6.626 × 10 - 34 ) 2 2 × 9.11 × 10 - 31 × ( 1 × 10 - 10 ) 2

= 2.41 × 10 - 17 1.6 × 10 - 19 ev

= 150.6 eV

Energy of a photon, E’ =  h c λ = 6.626 × 10 - 34 × 3 × 10 8 1 × 10 - 10 × 1.6 × 10 - 19 = 12.42 × 10 3 eV= 12.42 keV

Hence, a photon has a greater energy than an electron for the same wavelength.

New Question

11 months ago

0 Follower 8 Views

C
Chandra Chaudhary

Contributor-Level 10

TU Berlin ranks among the Top 200 Universities in the world in 2025. It offers courses in Engineering, Technology, Natural Sciences, Social Sciences, Economics, etc. There are more than 34,000 students studying at this university. It is one of the largest technical universities in Germany. Also, there is no tuition fee to study at this university and the exceptions to this are Master's and Continuing Education programs.

New Question

11 months ago

0 Follower 12 Views

V
Vedant Mishra

Beginner-Level 2

No, there is no entrance exam. You only have to give a personal interview, they see your communication skills.

New Question

11 months ago

0 Follower 1 View

A
Aishwarya Kumari

Contributor-Level 10

Pandit SN Shukla University offers BA programme across different specialisations. All the courses are available in a full-time mode. Admission is granted on a merit-basis. Some of the offered course specialisations are as follows:

  • Economics, Geography, Political Science
  • Psychology, Sociology, English
  • English, Hindi, History
  • History, English, Sociology, etc. 

New Question

11 months ago

0 Follower 6 Views

I
Ishita Singh

Contributor-Level 10

Most Master's courses at TU Berlin are taught in German. But, there are some courses that are taught in English. A proof of German language proficiency is required for all degree programs held in the German language. A few of the German language certificates accepted by this university are DSH 2 or 3 / TestDAF. The same is applicable for the Bachelor's courses. German language proficiency score report is required for admission wherever applicable.

New Question

11 months ago

0 Follower 6 Views

S
Shailja Rawat

Contributor-Level 10

KIIT School of Management has received rankings by many ranking bodies, including Times. In the year 2024, it was ranked #2 by Times under the 'BBA' category.

New Question

11 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

11.30 Intensity of the incident light, I = 10 - 5  W m - 2

Surface area of the sodium photocell, A = 2 c m 2  = 2 × 10 - 4 m 2

The incident power of the light, P = I × A  = 10 - 5 × 10 - 4 m 2 W = 2 × 10 - 9  W

Work function of the metal, 0 = 2 eV = 2 × 1.6 × 10 - 19  J = 3.2 × 10 - 19  J

Number of layers of sodium that absorbs the incident energy, n = 5

The effective atomic area of a sodium atom, A e  = 10 - 20 m 2

Hence, the number of conduction electrons in n layers is given by:

n’ = n × A A e  = 5 × 2 × 10 - 4 10 - 20  = 1 × 10 17

Since the incident power is uniformly absorbed by all the electrons continuously, the amount of energy absorbed per second per electron is

E = P n '  = 2 × 10 - 9 1 × 10 17  = 2 × 10 - 26  J/

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