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NaOH is obtained by electrolysis of NaCl. Solution of NaCl using Hg cathode

$\begin{array}{l}Cathode:N{a}^{+}+e\underset{}{\overset{Hg}{\to }}Na-Amalgam\\ Anode:2C{l}^{-}\to C{l}_2+2e\\ 2Na-Amalgam+2H_{2}O\to 2NaOH+2Hg+H_2\end{array}$

$N{i}^{2+}+2dmg\to \left[Ni{\left(dmg\right)}_2\right]\downarrow$ Rosy-red precipitate

Penicillin is not a broad spectrum artibiotic and is used to treat only certain infections caused by streptococci and staphylococci such as pneumonia.

In Hall Heroult process electrolysis is carried out using carbon anode. The liberated

O2 at anode reacts with anode.

Cathode : $A{l}^{3+}\left(melt\right)+3ek\to A\mathcal{l}\left(\mathcal{l}\right)$

Anode : $\begin{array}{l}C\left(s\right)+O^{2-}\left(Melt\right)\to CO\left(g\right)+2e\\ C\left(s\right)+2O^{2-}\left(Melt\right)\to C{O}_2\left(g\right)+4e\end{array}$

Net Reaction 2Al2O3 + 3C $4A\mathcal{l}+3C{O}_2$

$Cellulose\underset{}{\overset{H^{+}/H_{2}O}{\to }}\beta -D-Glucose\underset{Water}{\overset{B{r}_2}{\to }}Gluconicacid$

At present, only three SAT exam dates for 2027 have been released by College Board and they are as follows:

1. March 13, 2027
2. May 1, 2027
3. June 5, 2027

The other SAT exam dates 2027 India are yet to be announced. 

Kindly consider the following figure

$\frac{dy}{dx}+2ytanx=2sinx$  

  $I.F.=e^{2{\displaystyle \int tanxdx}}=se{c}^{2}x$             

$\therefore$  Solution y sec²x =   $2{\displaystyle \int sinxse{c}^{2}xdx=2{\displaystyle \int secxtanxdx}}$

y sec² x = 2sec x + c

y = 2 cos x + c cos²x passes $\left(\frac{\pi }{4},0\right)=B$     C =   $-2\sqrt[]{2}$

y = 2 cos x  $2\sqrt[]{2}co{s}^{2}x$ $\therefore {\displaystyle \underset{0}{\overset{\pi /2}{\int }}ydx}=2-\frac{\pi }{\sqrt[]{2}}$                              

Candidates who are applying for admissions into the BPharma course at Mahatma Jyoti Rao Phoole University are advised to only fill truthful information. Information which can be proved with the documents attached to the application give candidates the best chance of clearing the assessment round. Any discrepancies in the details filled in the application form will result in the rejection of a candidate's candidature for BPharma admissions at Mahatma Jyoti Rao Phoole University.

To apply for the BPharm programme at Chitkara University, candidates must have passed Class 12 with at least 50% aggregate marks in Physics, Chemistry, and Biology or Mathematics from a recognised board. Eligible applicants are shortlisted for a personal interview, which is a key part of the final admission process.

BPharm course at Chitkara University is a four-year undergraduate programme, recognised by the Pharmacy Council of India (PCI). It is structured across eight semesters, offering a comprehensive mix of theoretical and practical knowledge to prepare students for real-world challenges in the pharmaceutical industry.

The anticipated SAT exam dates for 2026 are as follows, month-wise for prospective applicants:

• March 14, 2026
• May 2, 2026
• June 6, 2026
• August 15, 2026
• September 12, 2026
• October 3, 2026
• November 7, 2026
• December 5, 2026

These dates have been announced on the College Board's website. Those planning to take SAT in 2026 can choose from any of the above mentioned dates and register as and when the deadlines approach.

For bio technology, you have to get a rank of 45,000 to 50,000. Also, you need to qualify JEE Mains and have at least 75% marks in 12th.

The admission fee for the BPharma course at Mahatma Jyoti Rao Phoole University is currently unknown. The components of the admission fee are also not disclosed by the Mahatma Jyoti Rao Phoole University. Candidates who wish to apply for BPharma courses at Mahatma Jyoti Rao Phoole University are advised to prepare the first instalment of their BPharma course fee as admission fee. The first instalment course fee for BPharma at Mahatma Jyoti Rao Phoole University is INR 47,500.

$2y{e}^{x/y^2}dx+\left(y^2-4x{e}^{x/y^2}\right)dy=0$

  $\Rightarrow 2e^{2/y^2}\left(ydx-2xdy\right)+y^{2}dy=0$            

$2e^{x/y^2}d\left(\frac{x}{y^2}\right)+\frac{dy}{y}=0$

Integrating   $2e^{x/y^2}+Iny=c$

y = 1, n = 0  c = 2

  ^{$2e^{x/y^2}+Iny=2$}  

$\therefore y=e\Rightarrow 2e^{x/e^2}+1=2$

x = -e² In2

Joining AIIMS Bathinda for BSc course is generally considered a good option. Candidates must also consider factors like infrastructure, faculty experience, hostel and mess facilities, curriculum, etc. while taking admission. They can apply online or offline for admission at AIIMS Bathinda. Additionally, they can also check for student/alumni reviews or visit the campus before admission. 

Kindly consider the following figure

$T_{90\mathrm{\%}}=\frac{2.303}{k}log\frac{100}{10}$

$T_{50\mathrm{\%}}=\frac{2.303}{k}log\frac{100}{50}$

$\frac{T_{90\mathrm{\%}}}{T_{50\mathrm{\%}}}=\frac{log10}{log2}=\frac{1}{0.301}=3.32$