Ask & Answer: India's Largest Education Community

No, candidates are not allowed to apply for the MBA course at IIM Mumbai through XAT. The institute only accepts valid CAT scores for admissions to MBA courses. Moreover, candidates will be shortlisted based on the CAT 2024 score and other parameters like reservation category, gender diversity, etc. Therefore, to get admission into MBA courses at NITIE, candidates are obliged to secure good scores in CAT. 

As per popularity basis, Rabindra Bharati University emerged to be as the top BFA college in Kolkata. Some of the other top colleges are mentioned below along with their tuition fees:

Disclaimer: This information is sourced from the official website and may vary.

11. From the given data we can tabulate the following.

About 10 best BFA colleges are there in Kolkata. Of these, 5 colleges are privately owned and 3 colleges are owned by public/government organisations. Students can secure admission after passing Class 12 boards. Some of the top BFA colleges in Kolkata include Rabindra Bharati University, Sister Nivedita University, Government College of Arts and Crafts, Kolkata, Techno India University, Amity University, Kolkata, Government College of Art and Craft, The Indian College of Arts and Draftsmanship, and many others.

It is still possible for candidates to get admitted to IHM Silvassa's courses without taking the NCHMCT JEE. The main eligibility criteria for admission to the BSc programme are grades and NCHMCT JEE rank. To be eligible for Certificate courses, candidates must have completed Class 12. Candidates are admitted directly based only on their qualifications and merit for the Certification programmes. 

10. From the given data we can insulate the following.

Take the assumed mean a=120 and h=10

Heigts in cm.	No. of boys fi	Mid-pointsxi		fidi	|xi - x? |	fi |xi - x? |
95-105	9	100	-2	-18	25.3	227.7
105-115	13	110	-1	-13	15.3	198.9
115-125	26	120	0	5.3	137.8
125-135	30	130	1	30	4.7	141
135-145	12	140	2	24	14.7	176.4

ASB Noida's BA course is offered in one specialisation, i.e. Psychology. The graudates of BA in Pyschology are hired by various organisations in the government and the private sectors. Some job positions that they can seek, along with their respective average salaries, are tabulated below:

Note: The salaries given above have been taken from ambitionbox.com and may vary depending on the companies offering the jobs.

With a 60% in Class 12, candidates can get admitted to the Institute of Hotel Management Silvsassa (IHM Silvassa), but only if they do well inthe NCHMCT JEE entrance exam. The cut-off scores determine the eligibility for the counseling and interview stages. The NCHMCT JEE is the only entrance test that is accepted for admission to IHM Silvassa's BSc programme. 

9. From the given data we cantabulate the following.

8. From the given data we can tabulate the following.

Here N = 29 which is odd.

= 1/29 * 148

= 5. 10

7. From the given data we cantabulate the following.

Now, N=26 which is even.

So, Median is the mean of 13^th and 14^th observation. Both of these observations lie in the cumulative frequency 14 for which corresponding observation is 7.

Depending on the course, IHM Silvassa's admissions procedure is either entrance or merit-based. Candidates can apply for admission and take the necessary entrance exam, such as NCHMCT JEE, if they meet the eligibility conditions. Candidates can pay the course fee and guarantee their enrollment if they make it past the institute's cutoff. 
On the basis of their academic merit, such as their Class 12 aggregate, candidates are shortlisted for the certification programme. 

6. From the given data we tabulate the following.

We have,

5. From the given data we have,

4. Arranging the given data in ascending order we get,

36,42,45,46,46,49,51,53,60,72

As n = 10 (even)

$=\frac{\left(\raisebox{1ex}{$n$}\!\left/ \!\raisebox{-1ex}{$2$}\right.\right){\text{\hspace{0.17em}thObservation}}^{}+{(\raisebox{1ex}{$n$}\!\left/ \!\raisebox{-1ex}{$2$}\right.+1)thObservation}^{}}{2}$

$\Rightarrow =\frac{{\mathrm{5thobservation}}^{}+{\mathrm{6thobservation}}^{}}{2}$

$=\frac{46+49}{2}$

$=\frac{95}{2}$

= 47.5

$\therefore$ M.D. (M) $=\frac{1}{n}\times {\displaystyle \sum _{i=1}^n\left|x_i-M\right|}$

$=\frac{1}{10}\times \left(11.5+5.5+2.5+1.5+1.5+1.5+3.5+5.5+12.5+24.5\right)$

$=\frac{70}{10}=7.$

3. Arranging the data in ascending order we get,

10,11,1112,13,13,14,16,16,17,17,18

As n=12, even

So, median is the mean of ${(\frac{M}{2})th}^{}$ and ${(\frac{M}{2}+1)th}^{}$ observation.

$\Rightarrow =\frac{{\mathrm{6thobservation}}^{}+{\mathrm{7thobservation}}^{}}{2}$

$M=\frac{13+14}{2}=\frac{27}{2}=13.5.$

So, deviation of respective observation about the median. $M,\left|x_i-M\right|$ are

Therefore the mean deviation about the mean is

$\text{\hspace{0.17em}M.D.}(M)=\frac{1}{n}\times {\displaystyle \sum _{i=1}^n\left|x_i-M\right|}$

$=\frac{1}{12}\times (3.5+2.5+2.5+1.5+0.5+0.5+0.5+2.5+2.5+3.5+3.5+4.5)$

$=\frac{28}{12}=2.33.$

2. Mean of the given observation is.

$\overline{x}=\frac{38+70+48+40+42+55+63+46+54+44}{10}$

$=\frac{500}{10}=50.$

So,

Therefore, the required mean deviation about the mean is

$\text{\hspace{0.17em}M.D.}(\overline{x})=\frac{1}{n}{\displaystyle \sum _{i=1}^n\left|x_i-\overline{x}\right|}$

$=\frac{12+20+2+10+8+5+13+4+4+6}{10}$

$=\frac{84}{10}$

= 8.4

1. Mean of the given observation is.

$\overline{x}=\frac{4+7+8+9+10+12+13+17}{8}$

$=\frac{80}{8}=10.$

Deviation of the respective observation about the mean $\overline{x}$ i.e.,  $x_i-\overline{x}$ are 4–10,7–10,8–10,9–10,10–10,12–10,13–10,17–10

=6, -3, -2, -1,0,2,3,7

The absolute value of the deviation i.e.,  $\left|x_i-\overline{x}\right|$ are 6,3,2,1,0,2,3,7.

Therefore, the required mean deviation about the mean is

$\mathrm{M.D}=(\overline{x})=\frac{1}{n}{\displaystyle \sum _{i=1}^n\left|x_i-\overline{x}\right|}=\frac{6+3+2+1+0+2+3+7}{8}$

$=\frac{24}{8}$

= 3.