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Candidates who clear the admission process for their applied for course are eligible to pay the course fee and secure their admission to the programme. Check out the table below to learn more about the course fee :

Candidates who meet the eligibility criteria that is set by the institute can apply for the courses on offer. Check out the table below to learn more about IHM Silvassa's eligibility and selection criteria: 

16. The given data can be tabulated as follow.

Having backlogs and an education gap can make B.Tech admission a bit challenging, but it's not impossible. Many colleges allow you to apply once you clear your backlogs. Some private institutes may also accept you with backlogs or gaps, but it's better to clear them first. Be honest about your situation and check each college's rules before applying.

15. We have, first 10 multiples of 3=3,6,9,12,15,18,21,24,27,30.

So,  $\overline{x}=\frac{3+6+9+12+15+18+21+24+27+30}{10}=\frac{165}{10}=16.5$

We can now tabulate the given data as following.

Therefore, variance,  $a^2=\frac{1}{n}{\displaystyle \sum _{i=1}^n{\left(x_i-\overline{x}\right)}^2}$

$\begin{array}{c}=\frac{1}{10}\times 742.5\\ \end{array}$

= 74.25.

14. We know that,

Sum of first'n ' natural no $=\frac{n(n+1)}{2}$

So, mean, $\begin{array}{c}\overline{x}=\frac{\text{\hspace{0.17em}sumoffirst}\left(n\right)\text{\hspace{0.17em}naturalno}.=}{}\frac{n(n\text{\hspace{0.17em}+1})/2}{n}\\ no\; of\; observations\end{array}$

$=\frac{n+1}{2}$

So, Variance, $a^2=\frac{1}{n}{\displaystyle \sum _{i=1}^n{\left(x_i-\overline{x}\right)}^2}=\frac{1}{n}{\displaystyle \sum _{i=1}^n{\left(x_i-\left(\frac{n+1}{2}\right)\right)}^2}$

$\begin{array}{l}{a}^2=\frac{1}{n}\left[{\displaystyle \sum _{i=1}^n{x}_i^2}-{\displaystyle \sum _{i=1}^{n}2}{x}_i\left(\frac{n+1}{2}\right)+{\displaystyle \sum _{i=1}^n{\left(\frac{n+1}{2}\right)}^2}\right]\\ \_\_\_\_\_\_\_(1)\end{array}$

So, $\begin{array}{c}{\displaystyle \sum _{i=1}^n{x}_i^2}={(1)}^2+{(2)}^2+{(3)}^2+\dots +{(n)}^2\\ =\frac{n(n+1)(2n+1)}{6}\_\_\_\_\_\left(2\right).\end{array}$

And ${\displaystyle \sum _{i=1}^n{\left(\frac{n+1}{2}\right)}^2}=\frac{{(n+1)}^2}{4}{\displaystyle \sum _{i=1}^{n}1}.=\frac{n{(n+1)}^2}{4\cdot }\_\_\_\_\left(4\right).$

Putting (2), (3) and (4) in (1) we get,

$\begin{array}{c}{a}^2=\frac{1}{n}\left[\frac{n(n+1)(2n+1)}{6}-\frac{n{(n+1)}^2}{2}+\frac{n{(n+1)}^2}{4}\right]\\ \end{array}$

$\begin{array}{c}=\frac{(n+1)(2n+1)}{6}-\frac{{(n+1)}^2}{2}+\frac{{(n+1)}^2}{4}\\ \end{array}$

$\begin{array}{c}=\frac{(n+1)(2n+1)}{6}-\frac{{(n+1)}^2}{4}.\\ \end{array}$

$\begin{array}{c}=(n+1)\left[\frac{2n+1}{6}-\frac{(n+1)}{4}\right]\\ \end{array}$

$=(n+1)\left[\frac{4n+2-3n-3}{12}\right]$

$=\frac{(n+1)(n-1)}{12}=\frac{n^2-1}{12}.$

According to information collated from official sources, Magadh University boasts a high number of seats for BCom. These seats are offered via more than 10 affiliated colleges. Out of all the colleges/institutes, Gaya College, has the highest intake, with 2343 seats. Some other colleges that offer a good number of seats are Sri Arvind Mahila College, Mahatma Gandhi College, Gaya, and more.

13. The given data can be tabulated as.

we have,

mean,  $\overline{x}=\frac{{\displaystyle \sum _{i=1}^n{x}_i}}{n}=\frac{6+7+10+12+13+4+8+12}{8}=\frac{72}{8}=9.$

So, variance,  $\begin{array}{c}{a}^2=\frac{1}{8}{\displaystyle \sum _{i=1}^n{\left(x_i-\overline{x}\right)}^2}\\ \end{array}$

$=\frac{1}{8}\times 74=9.25$

The fee of the three-year BSc programme at IHM Silvassa is INR 2.96 lakh. The course cost fee must be paid in order to reserve a seat for candidates who are accepted through the entrance-based admissions process. In order to properly submit the deposit, candidates must adhere to the fee payment requirements established by the institute. The means available to pay the fee are mentioned on the official website of the institute. 

Yes, at Magadh University, students are offered a high number of seats under the BCom programme. As per official sources, a total of 12,728 seats are available for BCom admissions. Students must note that these seats are distributed across various colleges affiliated with the university. Moreover, the seat intake is subject to change on an yearly basis.

You can check a few docs to be carried at the time of the Textile Engineering Diploma admission process at top colleges given here:

• Class 10 or Class 12 Mark Sheet with at least 50% marks
• Entrance Exam Scorecard Copy (if applicable)
• Address and Identity Proof (Aadhar card, passport, PAN card)
• Reservation Category Certificate (if applicable)
• Character Certificate from the passing institute (may be required)
• Recent Passport-Size Photos

This is a very basic list that can vary from college to college. You can go to the college websites and read their admission guidelines to get a clear picture.

The Textile Engg. admission process for the Diploma course after Class 10 can easily take at least 4 to 5 months to complete because of various admission guidelines that the college needs to look after, including admission forms, entrance exams (if applicable), results, cutoffs, college counseling, seat distribution and fee payment.

To be eligible for BNYS at Sona Medical College of Naturopathy and Yoga, candidates must have passed Class 12 with a minimum of 50% aggregate marks in the Science subjects, namely Physics, Chemistry, Biology/Botany and Zoology. Interested candidates can apply online on the official website for the desired course. 

You can gain a lot of skills from the Diploma course in Textile Engg. that would help you have a successful career in the field of textile and apparel design. Some of the important skills are listed here for your reference:

• Working knowledge of textile manufacturing techniques
• Textile quality control, testing, and analysis
• Fabric draping and coloration
• Teamwork and Adaptability
• Critical Thinking and Creativity
• Innovative Approach and Sound knowledge of CAD software for textile design

Useful Link: Know all about the Diploma in Textile Engineering Course

Karnavati University offers BTech through the Unitedworld Institute of Technology (UIT). Admission to the programme is subject to the fulfilment of the eligibility criteria specified by the university. As per the university's official website, the eligibility requirement for admission to the BTech course of Karnavati University is as follows:

• General/ UR Category: A minimum aggregate of 65% in Class 12 with Physics, Chemistry and Mathematics (PCM)

• SC/ ST/ OBC Category: A minimum aggregate of 50% in Class 12 with Physics, Chemistry and Mathematics (PCM)

To guarantee their spot in the BSc programme, applicants must adhere to the entrance-based admissions procedure. To guarantee a seat, aspirants must complete the NCHMCT JEE application form, show up for the entrance exam, and pass the institute's cutoff. Candidates who surpass the cutoff are given the final admission offer. Candidates must make the fee payment to confirm admission to the programme. 

Once the affiliated colleges of Magadh University complete the verification process, students are required to log into their online student accounts and click on the registration button. After that, they must update all the required details and pay a registration fee of INR 461.

Note: The above-mentioned fee is as per official sources. However, it is subject to change.

Yes, Karnavati University offers B.Tech programs. They offer courses such as computer Science and engineering with specialisation in fields like artificial intelligence and machine learning, data science, cyber security as well as information technology, electronics and communication and many more.