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Yes, SLS Pandit Deendayal Energy University registration window is currently open. The eligible students can visit the official website to register and apply for the BCom (H) courses. Admission criteria is entrance-based at the university. Moreover, the applications are accepted in an online mode by the university. Eligible students can visit the official website to register and apply. 

This is a multiple choice answer as classified in NCERT Exemplar

(a, b, d) a) total mechanical energy of the body at any time t is

E= $\frac{1}{2}m$ w²a²

KE=1/2mv²= $\frac{1}{2}m[{\frac{dx}{dt}]}^2$

K_max= ½ mw²a²=E

b) K= ½ mw²a²cos²wt

for a cycle value of coswt is =1/2

 = 1/4 mw²a²= kmax/2

c) v=dx/dt = a coswt

V_maen =V_max+V_min/2

= aw-aw/2=0

d)V_rms= $\sqrt[]{\frac{v_1^2+v_2^2}{2}}=\sqrt[]{\frac{0+a^2{w}^2}{2}}=\frac{aw}{\sqrt[]{2}}$

V_rms=V_max/    $\sqrt[]{2}$

For admission to the BSc course at Cheran College of Nursing, students need to fulfil the minimum eligibility criteria in the first place. The selection criteria for this course is merit-based and candidates must pass Class 12. The duration of the course is four years.

MAKAUT is affiliated with around 40 colleges; the total number of seats offered in the colleges and university is around 6,670. From which only two colleges offer the highest number of BSc seats. Check out the name of the college with the number of seats offered for the BSc course in the table below:

Yes, BSc course is available at Cheran College of Nursing. The institute offers BSc courses at the UG level. Candidate must meet the eligibility criteria to enrol for BSc course admission set by the college. Aspirants must pass Class 12. Cheran College of Nursing's admission process is merit-based.

This is a multiple choice answer as classified in NCERT Exemplar

(a, b, c) At t= 3T/4, the displacement of the particle is zero. Hence particle executing SHM will be at mean position i.e x=0 acceleration is zero and force is also zero.

At t= 4T/3, displacement is maximum i.e extreme position, so acceleration is maximum

At t = T/4 corresponds to mean position, so velocity will be maximum at this position.

At t= T/2 corresponds to extreme position so KE =0 and PE =maximum.

Yes, SLS, Pandit Deendayal Energy University offers BCom (Hons) course of four-year duration. It is available in a full-time mode of study. For admission, candidates have to take the entrance test of the school and selected students are called for the interview round. After this, the selected students can confirm their seats by paying the required fee amount. 

This is a multiple choice answer as classified in NCERT Exemplar

(a, b, d) x=asinwt

V=dx/dt=awcoswt

A=dv/dt=-aw²sinwt

Force = mass $\times acceleration$ = -mw²x

So force is directly proportional to displacement.

With 88 percentile in MBA CET and coming from general category it's unlikely to get an admission in PUMBA. PUMBA cutoff through CET for general category students is usually around 98 to 99 percentile.There is immense competition and all the seats are usually taken by top scorers. You can apply and get involved in the CAP rounds, because the cut off may differ slightly every year. You should also consider applying at other reputable colleges in Maharashtra accepting CET scores as there may be colleges with little lower cutoff. Stay ready with backup options.

This is a multiple choice answer as classified in NCERT Exemplar

(b), (d) It is clear the curve that points corresponding to t=2s and t=6s are separated by a distance belongs to one time period. hence these points must be in same phase

Similarly points belongs t-1s to t=5sare at separation of one time period. Hence must be in phase.

MSc Nursing full form is Master of Science in Nursing, a two-year-long PG degree program, intended to provide advanced education and training for Registered Nurses. This course helps students develop strong clinical, teaching, and research skills, preparing them for nursing education, management, and leadership roles. Students can check the list of career options available after completing MSc from Cheran College of Nursing:

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: Correct option: D

[Fe (CN)₆]^3-  ion shows magnetic moment corresponding to one unpaired electron. (CN) is a ligand with a strong field that couples electrons, resulting in hybridisation. d²sp³ and it has one unpaired electron, it has the magnetic moment of one paired electron.

  μ= $\sqrt[]{n(n+2}$   = 1 (1 + 2)

   = 3 = 1.73BM 

This is a multiple choice answer as classified in NCERT Exemplar

(a), (c) the rotation of earth about its axis is periodic because it repeats after a regular interval of time.

The rotation of earth is obviously not a to and fro type of motion about a fixed point. So its motion is SHM.

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: Correct option: B

From the Cis and Trans forms, geometrical isomerism forms compounds. All of the valences in the MX₆ ligand are the same, resulting in an identical molecule. L is a distinct ligand in MX₅L, and it can be replaced with any other valency in the structure to create an identical molecule; the molecule does not change. Because of the presence of symmetry, which is an essential prerequisite for revealing geometrical isomerism, complexes do not show geometrical isomerism.

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: Correct option: A

The term "linkage isomerism" refers to two molecules that have similar ligands but differ in the donating site of the ligand. Ambidentate is made up of two different types of donor atoms.

Example [Fe (NO₂) (H₂O)₅]Cl₂. NO₂ is Ambidentate ligand as Nand O₂ are donors.

 As a result, linkage isomerism occurs in coordinations with ambidentate ligands. Reason and Assertion are both correct.

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: Correct option: B

[Cr (H₂O)₆]Cl₂ and [Fe (H₂O)₆]Cl₂ 

Due to the creation of a more stable complex ion after obtaining ion, [Cr (H₂O)₆]Cl₂ and [Fe (H₂O)₆]Cl₂ are reduced in nature. Both compounds have a coordination of 6 and so form an octahedral complex. The hybridisation state of is 3 and the oxidation state of is 2+. Hybridization is 3d⁴ and 3d⁶ is 2+. Both compounds have unpaired electrons and have weak field ligands. In both compounds, removing electrons is simple.