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This is a multiple choice answer as classified in NCERT Exemplar

(c) Due to presence of moisture density of air decreases.

As we know speed of sound in air v= $\sqrt[]{\frac{\gamma P}{\rho }}$

So v $\propto \frac{1}{\sqrt[]{\rho }}$

v_2/v₁= $\sqrt[]{\frac{{\rho }_2}{{\rho }_1}}$

_{$\rho$ 2} (moist air)< $\rho$ ₁ (dry air)

So v₂>v₁

So speed of sound wave increases with increase in humidity

The eligibility for the courses at Nilamber Pitambar University is set by the authorities of the university. Candidates can go through the official website of the Nilamber Pitambar University to learn more about the eligibility criteria for various courses. However, the common eligibility for the PG courses that they must have completed their UG from a recognised univeristy and in a relevant course, and for the UG courses is that candidates must have completed Class 12. 

This is a multiple choice answer as classified in NCERT Exemplar

(c) Let frequency of the two will be  $vandv\text{'}$  and it is same in both medium

So v/ $\lambda$ = v’/ $\lambda$

$\lambda \text{'}$ = v’ $\lambda$ /v

$\lambda \text{'}$ = 2v $\lambda$ /v=2 $\lambda$

Where $\lambda$ and $\lambda$ ’ and v and v’ are wavelength and speeds of first and second medium respectively

This is a multiple choice answer as classified in NCERT Exemplar

(b) Water waves produced by a motorboat are both longitudinal and transverse because it produce both lateral and transverse wave In the medium.

IILM Lucknow offers a BBA programme in a full-time mode of study. The selection for admission is done based on merit or performance in CUET/ other entrance exam. Students wanting to do a college comparison can do so by considering the below parameters:

• Fees
• Placements package
• Faculty
• Location, etc.

This is a short answer type question as classified in NCERT Exemplar

Let there are n number of loops in the string

length corresponding each loop is $\frac{\lambda }{2}$

So we can write L= $\frac{n\lambda }{2}$

$\lambda =\frac{2L}{n}$

v/ $v$ =2L/n

so frequency $v=\frac{n}{2L}$ v= $\frac{n}{2L}\sqrt[]{\frac{T}{\mu }}$

v $\propto n$

so $v_1:v_2:v_3:v_4=n_1:n_2:n_3:n_4$

= 1:2:3:4

This is a short answer type question as classified in NCERT Exemplar

consider the frequency of tuning fork= 512Hz

(a) L= $\frac{\lambda }{4}$

$\lambda =4L$

V= $v\lambda$ = 512 $\times 4\times 17\times {10}^{-2}$

= 348.16m/s

(b) we know that v $\propto \sqrt[]{T}$

$\frac{V_{20}}{V_0}$ = $\sqrt[]{\frac{273+20}{273}}=\sqrt[]{\frac{293}{273}}$

$\frac{V_{20}}{V_0}=\sqrt[]{1.073}=1.03$

V_o= $\frac{V_{20}}{1.03}=\frac{348.16}{1.03}=338m/s$

(c) Resonance will be observed at 17cm length of air column only intensity of sound heard may be greater due to more complete reflection of the sound waves at the mercury surface because mercury is more denser than water.

To qualify in the NATA exam, a candidate must score a minimum of 70 marks out of 200. However, qualifying in NATA does not guarantee admission, as institutes may have their own cutoff criteria and eligibility requirements.

Purdue MSc in CS employment rate is 82% for 2023-24. The mean salary of CS graduates is USD 117,591 (around 1 Cr.). A few of the employers of these graduates were:

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This is a short answer type question as classified in NCERT Exemplar

Given frequency of the wave v=256Hz

          T= $\frac{1}{v}=\frac{1}{256}=3.9\times {10}^{3}s$

(a) time taken to pass through mean position is

t=T/4=1/40 =3.9 $\times \frac{{10}^{-3}}{4}s=$ 9.8 $\times$ 10^-4s

(b) nodes are A, B, C, D, E (having zero displacement)

antinodes are A’ and C’ (having maximum displacement)

(c) it is clear from diagram A’ and C’ are forming antinodes have $\lambda$ separation= v/v’=360/256=1.41m

KK University offers over 200 seats for its BTech programme. These seats are further distributed over the BTech specialisations offered at the university. To allocate these seats to eligible applicants, the university conducts an entrance test, followed by a Group Discussion (GD) and/ or a Personal Interview (PI). It must be noted that the mentioned information on seats is sourced from the official website of the university/ sanctioning body. It is still subject to change and hence, is indicative.

Yes, Nilamber Pitambar University admissions are open for 2025-26 session. Candidates can fill out the form online on the official website of the university. Admission to the offered programmes can either be entrance-based or merit-based. The university accepts NEET PG, and NEET entrance exams for admission to certain courses. 

This is a short answer type question as classified in NCERT Exemplar

We have to observe the displacement and position of different points, then accordingly nature of two waves decided

Points on positions x= 10,20,30,40 never move, always at mean position with respect to time . these are forming nodes which forms a stationary wave

Distance between two successive nodes = $\frac{\lambda }{2}$

$\lambda =2($ node to node distance)

=2 (20-10)

= 2 (10)=20cm

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Living Expenses: For UG students, the housing and other living expenses would cost around (as per the 2025-26 academic year):

This is a short answer type question as classified in NCERT Exemplar

As the source is moving towards the observer hence apparent frequency observed is more than the natural frequency

Frequency of whistle $v=400Hz$

Speed of train = v_t= 10m/s

Velocity of sound in air =v= 330m/s

Apparent frequency when source is moving v_app= (v/v-v_t)v

= ( $\frac{330}{330-10})400$

= $\frac{330}{320}\times 400=412.5Hz$

IILM Lucknow BBA admission criteria is merit and entrance-based. The admission process commences with the online registrations. After registration, applications are shortlisted based on performance in last qualifying exam, CUET scores or other entrance test scores. After selection, the candidates are informed by the authorities and can proceed with fee payment. Once the fees is paid, the seats are confirmed. 

This is a short answer type question as classified in NCERT Exemplar

length of pipe

L=20cm =20 $\times {10}^{-2}m$

$v_{close}=\frac{v}{4L}=\frac{330}{4\times 20\times {10}^{-2}}$

$v_{close}=330\times \frac{100}{80}=412.5Hz$

$\frac{v_{given}}{v_{closed}}=1237.5/412.5$ =3

Hence 3^rd harmonic node of the pipe is resonantly excited by the source of the given frequency.

No, it is not compulsory to appear for all NATA tests. Candidates can choose to appear for any one, two, or all three attempts of NATA in a given year. The best score among all attempts will be considered for admission purposes.