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Ranchi University offers a total of 1020 seats for BBA courses. This means that a total of 1020 students can take admission into the BBA course in a single academic year. These seats are spread across different affiliated colleges, including St. Xavier's College, Nirmala College Ranchi, B. N. J. College, Yogoda Satsanga Mahavidyalaya, and more.

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This is a multiple choice answer as classified in NCERT Exemplar

(a, c, d) at point A graph will parallel to time axis hence, v=dx/dt=0. As the starting point is A hence, we can say that the particle is starting from rest.

At C, the graph changes slope, hence velocity also changes. As graph at C is almost parallel to time axis hence, we can say that velocity vanishes.

Velocity is 0. So particle at rest that time. As slope of D will be greater than E . so velocity will be greater at D.

Yes, candidates who are offered admission to the Ranchi University BBA course and wish to secure it must make payment of the prescribed fees. In general, during this stage, candidates are required to pay an admission fee. Along with this, students may also be required to make payment of the first installment of tuition fees.

This is a multiple choice answer as classified in NCERT Exemplar

(c) in this situation we have to find net velocity with respect to the earth that will be equal to velocity of the girl plus velocity of escalator.

Let displacement is L the

Velocity of  girl v_g= L/t₁

Velocity of escalator v_e= L/t₂

net velocity = velocity of escalator +velocity of girl

V_g=l/t₁  and V_e=l/t₂

So net velocity = L/t₁+ L/t₂

So t= $\frac{t_1{t}_2}{t_1+t_2}$

Students who are interested for the admission in BBA programme at Gangadhar Meher University is expected to meet all the eligibility criteria set by the university. These are important to ensure that students have developed the required understanding and are ready to delve deeper into the subjects opted for. The below table gives the details of the eligibility criteria required for admission into BBA course:

The closing date of Maya Academy of Advanced Creativity, Rajouri Garden for admission 2025 is not declared yet. Occasionally, candidates are supposed to check the official website for updates. It should be applied early to have a better probability of getting a seat. Admission takes place through first come, first served basis.

Yes, application to Maya Academy of Advanced Creativity, Rajouri Garden in 2025 is already open. Those students who want to be enrolled in certificate programs will get admissions using the official site. The process of admission is conducted on merit performance of Class 12. Eligible candidates have to accomplish all the procedures to be selected.

This is a multiple choice answer as classified in NCERT Exemplar

(b) x = (t-2)²

V= dx/dt= 2 (t-2)

And acceleration a = 2

When t =0 v= -4m/s

When t= 2s v= 0m/s

When t= 4s v= 4m/s

Distance travelled = area of graph =area of OAC+area of ABD= $\frac{4\times 2}{2}+\frac{1}{2}\times 2\times 4$ =8m

The application process for BBA admissions at Ranchi University is conducted through the Chancellor's Portal. Thus, candidates seeking admission visit the official website of the portal and follow the steps as follows:

1. Click on 'Chancellor's Portal' available at the end of the page.

2. Register on the portal and fill out the application form with all the important details.

3. Pay the application fee online through a debit/credit card.

4. Preview and submit the form.

This is a multiple choice answer as classified in NCERT Exemplar

(c) Time taken to travel first half distance t₁= $\frac{l/2}{v_1}=\frac{l}{2v_1}$

Time taken to travel second half distance t₂= $\frac{l}{2v_2}$

Total time =t₁+t₂

formula for average velocity will be =  $\frac{l}{2v_1}+\frac{l}{2v_2}=\frac{l}{2}\left. [\frac{1}{v_1}+\frac{1}{v_2}\right]$

formula for average velocity will be= v_av=average speed= total distance/total time = $\frac{2v_1+v_2}{v_{1+}{v}_2}$

This is a multiple choice answer as classified in NCERT Exemplar

(b) For maximum and minimum displacement we have to keep in mind the magnitude and direction of maximum velocity.

As maximum velocity in positive direction is v_o maximum velocity in opposite direction is also v_o.

Maximum displacement in one direction = v_oT

Maximum displacement in opposite direction=-v_oT

Hence -v_oToT

Yes, KK University offers a full-time BTech lasting four years. The course duration is further divided into eight semesters. The university offers the programme with four specialisation options through its School of Engineering & Technology. These specialisations are Civil Engineering, Mechanical Engineering, Electrical Engineering, and Computer Science & Engineering. Further, candidates can also take admission directly to the second year of BTech through lateral entry. For more information, interested candidates can visit the university's official website or directly contact the admission team.

This is a multiple choice answer as classified in NCERT Exemplar

(a) As the lift when coming downward directions displacement will be negative. We have to see whether the motion is accelerating or retarding.

We know that due to downward motion displacement will be negative, when the lift reaches 4^th floor is about to stop hence motion is retarding in nature.

As displacement is in negative direction . velocity will also be negative i.e v<0  

This is a multiple choice answer as classified in NCERT Exemplar

(b) To making it vanish one part must cancel other part which is only possible in graph b.

As there are opposite velocities in the interval 0 to T hence average velocity can vanish in b .

International applicants at Purdue University applying for UG programs can apply via Common App. For graduate courses, the applicants can find the link to apply from the respective course's official university pages.