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New Question

7 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Let B? be the event where Box-I is selected and B? →where box-II selected
P (B? )=P (B? )=1/2
Let E be the event where selected card is non prime.
For B? : Prime numbers: {2,3,5,7,11,13,17,19,23,29}
For B? : Prime numbers: {31,37,41,43,47}
P (E)=P (B? )×P (E/B? )+P (B? )P (E/B? )
= 1/2×20/30+1/2×15/20
Required probability:
P (B? /E) = (P (E/B? )P (B? )/P (E) = (1/2×20/30)/ (1/2×20/30+1/2×15/20) = (2/3)/ (2/3+3/4) = 8/17

New Question

7 months ago

0 Follower 1 View

L
Liyansha Gaurav

Contributor-Level 10

Candidates seeking admission to the Ambalika Institute of Professional Studies must fulfil the college's eligibility criteria. The institute offers Diploma in Electrical Engineering, Diploma in Computer Science and Diploma in Mechanical Engineering Automobile courses. However, the institute also offers direct admission under Management Quota/ Vacant Seats after counselling of BTE (JEECUP).

New Question

7 months ago

0 Follower 16 Views

A
alok kumar singh

Contributor-Level 10

x > d path is straight line
-y = 1/2 at²
x-d = V?t ⇒ t=(x-d)/V?
-y = 1/2 a((x-d)/V?)²
-y/at = (1/2at)(a²t²)
at = V?
(-y/at) = (d/2V?)
(x-d)/V? = d/V?
(-y - 1/2 a t²)/(at) = (x-d - V?t)/V?
y = (-qEd/mV?)(x/V? - d/2V?) ; y = (qEd/mV?²)(d/2 - x)

 

New Question

7 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

With weak field ligands Mn (II) will be of high spin and with strong field ligands it will be of low spin.
Ni (II) tetrahedral complexes will be generally of high spin due to sp³ hybridisation. Mn (II) is of light pink color in aqueous solution.

New Question

7 months ago

0 Follower 3 Views

A
Anshul Jindal

Contributor-Level 10

For Andhra Pradesh EdCET, focus on understanding the syllabus and exam pattern, especially the three sections: General English, General Knowledge & Teaching Aptitude, and Methodology. Create a study plan, solve previous year's question papers and mock tests to identify weak areas, and maintain a consistent revision schedule.

In Teaching Aptitude and GK

  • Stay updated on current affairs and practice problem-solving skills, while for Methodology, use the official syllabus to guide your preparation. 

General English

  • Read Newspapers: Regularly read newspapers and magazines to improve your vocabulary, grammar, and comprehension.
  • Practice Com
...more

New Question

7 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Slope of tangent is 2, Tangent of hyperbola
x²/4-y²/2=1 at the point (x? , y? ) is xx? /4-yy? /2=1 (T=0)
Slope: x? /2y? =2 ⇒ x? =4y?
(x? , y? ) lies on hyperbola
⇒ x? ²/4-y? ²/2=1
From (1) and (2)
(4y? )²/4-y? ²/2=1 ⇒ 4y? ²-y? ²/2=1
⇒ 7y? ²=2 ⇒ y? ²=2/7
Now x? ²+5y? ² = (4y? )²+5y? ² = 21y? ² = 21×2/7=6

New Question

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

f? = 1/ (2l) √ (T? /µ)
f? = 1/ (2l) √ (T? /µ)
f? /f? = 450/300 = √ (T? /T? )
⇒ T? /T? = 9/4 = 2.25

New Question

7 months ago

0 Follower 3 Views

C
Chikat Marchang

Contributor-Level 8

Chennai Institute of Technology is a well known institute in India with international reputation. CIT is frequently ranked among top 150 engineering institutions in India by different national bodies like NIRF. The latest 2024 NIRF rankings have firmly placed Chennai Institute of Technology at 100-150 rank establishing it as one of premier engineering institutions of India.

New Question

7 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

2x-y+2z=2
x-2y+λz=-4
x+λy+z=4
For no solution:
D=|2, -1,2; 1, -2, λ 1,1,1|=0
⇒ 2 (-2-λ²)+1 (1-λ)+2 (λ+2)=0
⇒ -2λ²+λ+1=0
⇒ λ=1, -1/2
D? =|2, -1,2; -4, -2, λ 4,1,1|
=2 (-2-λ)+1 (-4-4λ)+2 (-4+8)
=2 (1+λ) which is not equal to zero for λ=1, -1/2

New Question

7 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

On moving Left to Right along a period.
Atomic Radius → decreases.
Electronegativity → Increases.
Electron gain enthalpy → Increases.
Ionisation Enthalpy → Increases

New Question

7 months ago

0 Follower 2 Views

M
Manisha Sahni

Contributor-Level 7

No, once the IPU CET admit card is issued, the exam centre allotted cannot be changed. The centres are assigned based on the choices filled during the application process and the availability of seats at each centre. Candidates are expected to appear at the centre mentioned on their admit card, as requests for changes are generally not entertained under any circumstances.

New Question

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Based on theory.

New Question

7 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Let three terms of G.P. are a/r, a, ar product=27
⇒ a³=27 ⇒ a=3
S=3/r+3r+3
For r>0
(3/r+3r)/2 ≥ √9 = 3
⇒ 3/r+3r≥6
For r<0, 3/r+3r≤-6
From (1) and (2)
S∈ (-∞, -3]∪ [9, ∞)

New Question

7 months ago

0 Follower 1 View

A
Anshul Jindal

Contributor-Level 10

While there are no magical "tricks," you can use strategic methods like thorough syllabus study, creating a detailed study plan, practicing mock tests, and solving previous year's papers to prepare effectively for the Andhra Pradesh EdCET exam. Focusing on weak areas, making short notes for quick revision, and maintaining a healthy lifestyle also significantly improve your chances of success. Don't stress and avoid last-minute cramming. It ruins everything.

New Question

7 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

Energy Density = 1/2 B²/µ?
B = √ (2 × µ? × Energy density)
B = √ (2 × 4π × 10? × 1.02 × 10? ) = 160 × 10? = 160nT

New Question

7 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

f (x) = {ae? +be? , -1For continuity at x=1
Lim (x→1? )f (x) = Lim (x→1? )f (x)
⇒ ae+be? ¹=c ⇒ b=ce-ae²
For continuity at x=3
Lim (x→3? )f (x) = Lim (x→3? )f (x)
⇒ 9c=9a+6c ⇒ c=3a
f' (0)+f' (2)=e
(ae? -be? ) at x=0 + (2cx) at x=2 = e
⇒ a-b+4c=e
From (1), (2) and (3)
a-3ae+ae²+12a=e
⇒ a (e²+13-3e)=e
⇒ a=e/ (e²-3e+13)

New Question

7 months ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

The vapour pressure of solution will be less than vapour pressure of pure solvent, so some vapour molecules will get condensed to maintain new equilibrium.

New Question

7 months ago

0 Follower 3 Views

P
Piyush Jain

Contributor-Level 10

The primary eligibility requirement for admission to the BSc course at Sabarmati University is that applicants must complete their Class 12 from a Science stream with decent scores. Moreover, for admissions to the BSc course, the university releases the merit list of shortlisted candidates after evaluating their Class 12 scores. 

New Question

7 months ago

0 Follower 6 Views

R
Ranjeeta Karan

Contributor-Level 10

There is no concise placements report for BPharm released by GJUST. However, as per the data available online, the average salary of BPharm graduates ranges from INR 2.6 LPA to INR 5.8 LPA. Some of the job profiles along with the salary packages are:

Job Profiles

Average Salary

Pharmacist

INR 2.6 LPA

Drug Inspector

INR 2.7 LPA

Quality Control

INR 2.6 LPA

Clinical Researcher

INR 5.8 LPA

Hospital Pharmacist

INR 2.7 LPA

NOTE: The average salary has been taken from Ambitionbox.com.

New Question

7 months ago

0 Follower 1 View

S
Saurabh Khanduri

Contributor-Level 10

Executive PGDM admission dates have not been revealed by PBS at this point of time. The admissions are decided through an admission interview conducted by PBS itself. It appears that candidates can apply for admissions at any point of time and the institute officials will call them for the admission interview at the appropriate time. For more information, candidates are advised to visit the official website.

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