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Since p (x) has relative extreme at x=1 and 2
so p' (x)=0 at x=1 and 2
⇒ p' (x)=A (x-1) (x-2)
⇒ p (x)=∫A (x²-3x+2)dx
p (x)=A (x³/3 - 3x²/2 + 2x)+C
P (1)=8
From (1)
8=A (1/3-3/2+2)+C
⇒ 8=5A/6+C ⇒ 48=5A+6C
P (2)=4
⇒ 4=A (8/3-6+4)+C
⇒ 4=-2A/3+C ⇒ 12=-2A+3C
From 3 and 4, C=-12
So P (0)=C=-12

With a BPharm degree from GJUST, candidates can build a career in the field of health care. The graduates can find job opportunities at government hospitals, private medical shops, and private hospitals/clinics. Individuals can also have their own consulting and medical shops. Moreover, BPharm degree holders are also eligible for jobs in the Indian Army.

Some of the prominent recruiters of BPharm graduates in India are:

• Cipla
• Biocon
• Dr. Reddy's Laboratories
• Sun Pharmaceutical Laboratories, etc.

As of now, admission at Ambalika Institute of Professional Studies is not open. The application process is an offline procedure. Admission forms are available in the month of December/January every year.The institute offers three Diploma courses, namely, Diploma in Electrical Engineering, Diploma in Computer Science and Diploma in Mechanical Engineering Automobile. 

R { (x, y):x, y∈z, x²+3y²≤8}
For domain of R? ¹
Collection of all integral of 's
For x=0, 3y²≤8
⇒ y∈ {-1,0,1}

There are various PG courses available for BPharm graduates. Students can select the given course based on their career goals, interests, & the specific field they want to specialise in within the pharmaceutical industry. Some of the PG course options after BPharm from GJUST Hisar are:

• Master of Pharmacy (MPharm)
• Clinical Research courses
• Pharmacovigilance & Drug Safety Courses
• Doctor of Pharmacy (PharmD)
• MBA Pharmaceutical Management

Yes, Sabarmati University does offer BSc courses for a duration of three years. Further, the course is divided into six semesters. These BSc courses are offered through the School of Applied Science in various departments. The names of some of the offered specialisations are BSc IT, BSc CS, Physics, Chemistry, etc. 

α and β are roots of 5x²+6x-2=0
⇒ 5α²+6α-2=0
⇒ 5α? ²+6α? ¹-2α? =0
(By multiplying α? )
Similarly 5β? ²+6β? ¹-2β? =0
By adding (1) and (2)
5S? +6S? -2S? =0
For n=4
5S? +6S? =2S?

The institute offers three Diploma courses, namely, Diploma in Electrical Engineering, Diploma in Computer Science and Diploma in Mechanical Engineering Automobile. To secure a seat at AIPS, students can follow the steps presented below:

1. Visit the official website and complete the offline application process. 
2. Ensure eligibility and entrance-based selection for all programmes.
3. The selection criteria are entrance-based.
4. Upon selection, pay the specified fee to confirm and secure your seat.

f (x)=sin (|x|+5)/ (x²+1)
For domain:
-1 ≤ (|x|+5)/ (x²+1) ≤ 1
Since |x|+5 and x²+1 is always positive
So (|x|+5)/ (x²+1) ≥ 0 ∀x∈R
So for domain:
(|x|+5)/ (x²+1) ≤ 1
⇒ |x|+5 ≤ x²+1
⇒ 0 ≤ x²-|x|-4
⇒ 0 ≤ (|x|- (1+√17)/2) (|x|- (1-√17)/2)
⇒ |x| ≥ (1+√17)/2 or |x|≤ (1-√17)/2 (Rejected)
⇒ x∈ (-∞, - (1+√17)/2] ∪ [ (1+√17)/2, ∞)
So, a = (1+√17)/2

The admission deadline for Executive PGDM at PBS has not been revealed by the institute yet. The admissions into PBS Executive PGDM courses is decided by the interview for admissions. A candidates's performance in this interview is used to decide whether they are granted admissions or not. All candidates interested in the PBS Executive PGDM admissions are advised to visit the official website of PBS to confirm the admission timeline.

Let p denotes statement
p: I reach the station in time.
q: I will catch the train.
Contrapositive of p→q is q→p
q→p: I will not catch the train, then I do not reach the station in time.

Bredig's Arc Method is used for preparation of colloidal sol's of less reactive metal like Au, Ag, Pt.

(2+sin x)/ (y+1) dy/dx = -cosx, y>0
⇒ dy/ (y+1) = -cosx/ (2+sinx) dx
By integrating both sides:
ln|y+1| = -ln|2+sinx|+lnK
⇒ y+1 = K/ (2+sinx) (y+1>0)
⇒ y (x) = K/ (2+sinx) - 1
Given y (0)=1 ⇒ 1=K/2-1 ⇒ K=4
So, y (x)=4/ (2+sinx)-1
a=y (π)=1
b=dy/dx|x=π = -cosx/ (y (x)+1)|x=π = 1
So, (a, b)= (1,1)

Slope of tangent to the curve y=x+siny
at (a, b) is (a-2)/ (b-3)=1
⇒ dy/dx|x=a = 1
dy/dx = 1+cos y dy/dx (from equation of curve)
⇒ dy/dx|x=a and y=b = 1+cosb=1
⇒ cosb=0
⇒ sinb=±1
Now, from curve y=x+siny
b=a+sinb
⇒ |b-a|=|sinb|=1

Since spin only magnetic moment is 4.90BM so number of unpaired electrons must be 4, so If the complex is octahedral, then it has to be high spin complex with configuration t? g? e²g¹ in that case
CFSE = 4× (-0.4Δ? ) + 2×0.6Δ? = -0.4Δ?
If the complex is tetrahedral then its electronic configuration will be e? ², t? g² and CFSE will be = 3× (-0.6Δ? ) + 3× (0.4Δ? ) = -0.6Δ?

σ²=variance
µ=mean
σ² = Σ (x? -µ)²/n
µ=17
⇒ Σ (ax+b)/17 = 17
⇒ 9a+b=17
σ²=216
⇒ Σ (ax+b-17)²/17 = 216
⇒ Σa² (x-9)²/17 = 216
⇒ a² (81-18×9+3×35) = 216
⇒ a² (24) = 216 ⇒ a²=9 ⇒ a=3 (a>0)
⇒ From (1), b=-10
So, a+b=-7

Candidates can download IPU CET admit card by following these steps

• Visit official IPU admission website ipu.admissions.nic.in.
• Click on link for IPU CET Admit Card 2026.
• Log in using registered User ID and Password.
• Go to the Download Hall Ticket section.
• Admit card will appear on screen with exam details.
• Download PDF and take clear print of admit card.

The institute offers three Diploma courses, namely, Diploma in Electrical Engineering, Diploma in Computer Science and Diploma in Mechanical Engineering Automobile. The selection criteria are based on entrance exam scores. To get admitted to AIPS, candidates must meet the eligibility criteria set by the institute. 

|x|/2 + |y|/3 = 1
x²/4 + y²/9 = 1
Area of Ellipse = πab = 6π
Required area = π×2×3 - (Area of quadrilateral)
= 6π - 1/2×6×4
= 6π-12
= 6 (π-2)