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$T=2\pi \sqrt[]{\frac{I}{g}}$

$g=\frac{4{\pi }^{2}I}{T^2}$

$\frac{\Delta g}{g}=\frac{\Delta I}{I}+\frac{2\Delta T}{T}$

$=\frac{0.2}{20}+2\left(\frac{1}{40}\right)$

= 6%

$\frac{1}{2}{\epsilon }_0{E}^2=\frac{B^2}{2{\mu }_0}$

$?E=CBandC=\frac{1}{{\mu }_0{\epsilon }_0}$          

$?=\frac{h}{p}\left[??\frac{1}{p}\right]$

Þ        lp = h (constant)

            So, the plot is a rectangular hyperbola.

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The magnitude of resultant vector (R)

$=\sqrt[]{a^2+b^2+2abcos\theta }$            

here a = b = A

then R = $\sqrt[]{A^2+A^2+2A^{2}cos\theta }$  

$=A\sqrt[]{2}\sqrt[]{1+cos\theta }$

$=\sqrt[]{2}A\sqrt[]{2co{s}^2\frac{\theta }{2}}$

$=2Acos\frac{\theta }{2}$      

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q = 0 as adiabatic process is given

            W = 0 as p_axt = 0

            q + W = DU

            q = 0

            W = 0

            Þ DU = 0