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Kindly go though the solution 

$v=\sqrt[]{\frac{\gamma RT}{M}}=330m/s$

Kindly go through the solution

p = i²R

P' = 0.64 i²R

$I=\left(\frac{2}{5}M{R}^2+M{R}^2\right)\times 2$

$=\frac{14}{5}\times 2\times \frac{9}{16}$

$=\frac{63}{20}$          

= 3.15 kg m²

By Brewsters law

m = tani

m =   $\sqrt[]{3}$

$1*\frac{\sqrt[]{3}}{2}=\sqrt[]{3}*sinr$

$sinr=\frac{1}{2}$    

r = 30°

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[A] = L²

$B=\frac{x^2}{tE}\equiv \frac{L^2}{TM{L}^2{T}^{-2}}=\frac{1}{M{T}^{-1}}$            

[B] = M^–1T

[AB] = [M^–1L²T]