Ask & Answer: India's Largest Education Community

Yes, English is a compulsory subject in class 12^th to apply for the UP CNET exam. Candidates must also have passed physics, chemistry, and biology with 50 per cent overall aggregate in class 12^th to be eligible to apply for the nursing entrance exam. Reserved category candidates must have scored 45 per cent marks to be eligible for appearing in the entrance exam.

Candidate not more than 35 years of age can apply for the UP CNET exam. The minimum age to appear for the CNET nursing exam is 17 years. Age is an important criterion. Candidates must adhere to it while filling the application form. Candidates not fulfilling this criterion but having qualified the exam will not be given admission to the CNET participating institutes.

Selected candidates will be given details about DEED admission formalities, fee payment, and deadlines. They may also be required to confirm their seat within a given time frame.

To pursue the BSc nursing programme a candidate must have passed 10+2 or its equivalent exam. The candidate should have studied Physics, Chemistry, Biology, and English in class 12.

Minimum Marks required to apply for the exam are 40% for reserved categories and 45% marks for the general category.

The minimum age limit to apply for the UP CNET 2026 exam is generally set at 17 years as of December 31, 2026. The exam is held once a year by ABVMU, Lucknow. It is mandatory to fill out the application form to appear for the UG-level nursing entrance. 

Yes, students appearing for 10+2 or 10+3 Diploma exams in the current year are eligible to apply for NATA. However, eligibility for admission depends on qualifying the exam.

Eligibility to Apply for NATA:

• Candidates who have passed or are appearing for:
• 10+2 exam with Physics, Chemistry, and Mathematics (PCM), or
• 10+3 Diploma with Mathematics as a compulsory subject
  are eligible to apply for NATA.

For Fall 2024, the university had a total of 29,927 students enrolled at the university, of which 20,418 accounted for the undergraduate student body and 9,509 for the graduates. The admission trends along with the trend for Pitt acceptance rate over the last few years is given below.

This is a multiple choice answer as classified in NCERT Exemplar

Option (iv) O₂, N₂, H₂, He

Higher the critical temperature of gases more easily, the gas will be liquefied. So, the order of liquefying of gases will be  O₂ > N₂ > H₂ >He. 

Candidates can check their result by logging into the DJAD admissions portal using their registered email ID and password.

The DEED result is usually declared a few days after the personal interview round. The exact date is announced on the official DJAD website and via email to candidates.

This is a multiple choice answer as classified in NCERT Exemplar

Option (i) increases

Gay Lussac’s law shows the direct relationship between the pressure and the temperature of a fixed amount of gas at constant volume.

Gay Lussac's law states that at constant volume, the pressure of a fixed amount of a gas is directly proportional to the temperature.

Therefore,  

P∝T   ……….at constant volume

Thus, pressure increases if the temperature is increased at a constant volume.

To elaborate more on this topic, we will see a real-life example.

The following steps should be followed for DEED Entrance Examination:

• Visit the official website and sign up on the admissions portal.
• After registering, fill out the online application form, pay the application fee, and submit it.
• You'll receive a confirmation email at your registered email address.
• Upload your portfolio through the DJAD admissions portal.
• Shortlisted candidates will be notified via email with further details regarding DEED 24 and the personal interview.

This is a multiple choice answer as classified in NCERT Exemplar

option (iii) 8 × 10⁴  Nm^-2 

Partial pressure of oxygen, Po₂= Xo₂   $\times$ P_total

Mole fraction of O₂= $\frac{Moleofoxygen}{Molesofoxygen+Molesofhydrogen}$

= $\frac{4}{4+1}$ = $\frac{4}{5}$

Po₂= $\frac{4}{5}$ $\times$ 1 = $\frac{4}{5}$  (?P_total = 1 atm)

1 atm =  1.1034 × 10⁵ Nm^-2 or Pa

Partial pressure of dioxygen = 0.8 ×10⁵ = 8×10⁴  Nm^-2 

This is a multiple choice answer as classified in NCERT Exemplar

option (iii) less than unit electronic charge 

Charge of 1 electron is 1.6 × 10 ^-19 C and the partial charge is always less than the unit electronic charge.

This is a multiple choice answer as classified in NCERT Exemplar

option (iii) polarisability of interacting particles.

The energy of the London force or London dispersion force  is inversely proportional to (distance between two interacting particles)⁶ but their magnitude depends upon the polarisability of interacting particles.

The mode of NATA application is entirely online, there's no offline submission. You must:

• Visit the official NATA portal (nata.in)
• Complete online registration
• Fill in all required personal, academic, and contact details
• Upload scanned photo and signature
• Pay the application fee at the end of the form
  
  

This is a multiple choice answer as classified in NCERT Exemplar

option  iii. p₁  < p₂ < p₃ < p₄

At a particular temperature, PV is constant

Therefore,   V ∝ $\frac{1}{\mathit{p}}$

So, as v₁ >  v₂  >  v₃  >  v₄   the order of pressure:  p₁  < p₂ < p₃ < p₄ .