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$\mathrm{}{\lambda }_{\text{electron}}=\frac{h}{\sqrt[]{2mE}}\mathrm{}\mathrm{}\frac{{\lambda }_{\text{electron}}}{{\lambda }_{\text{photon}}}=\frac{1}{c}\sqrt[]{\frac{E}{2m}}$

${\lambda }_{\text{photon}}=\frac{\mathrm{h}\mathrm{c}}{\mathrm{E}}$

$y^2-2x-2y=1$

$\Rightarrow {\left(y-1\right)}^2=2\left(x+1\right)$ …. (i)

Equation of tangent at A is 2x – y – 5 = 0 ………. (ii)

D is mid point of AB solving (ii) with y = 1 P (3, 1)

$\therefore PD=4,AD=2$

$Areaof\Delta APD=\frac{1}{2}\left(PD\right)\left(AD\right)=4$

$\therefore Areaof\Delta APB=8sq.units$

Current in capacitor l = $\frac{V}{X_C}$ $\frac{}{{}_{}}$

I = v × $\left(\omega c\right)$ $$

$C=\frac{1}{v\omega }=\frac{6.9\times 10^{-6}}{230\times 600}=50pF$

Ionisation enthalpy order :

              Li > Na > K

              He > Ne > Ar > Kr > Xe > Rn

              Sr > Rb

              Zn > Ga

Assuming current ‘i’ In outer loop magnetic field at centre

$=4\times \frac{{\mu }_0}{4\pi }\frac{i}{L/2}\times [2sin45°)$

$=\frac{2\sqrt[]{2}{\mu }_{0}i}{\pi L}$

M = $\frac{Fm\alpha throughinnerloop}{i}$ $\frac{}{}$

= $\frac{2\sqrt[]{2}{\mu }_{0}i{\mathcal{l}}^2}{\pi L}=\frac{2\sqrt[]{2}{\mu }_0{\mathcal{l}}^2}{\pi L}$ $\frac{\text{exception 25:}{}_{}{}^{}}{}\frac{\text{exception 25:}{}_{}{}^{}}{}$

Total power is  $(15\times 45)+(15\times 100)+(15\times 10)+(2\times 1000)=4325\mathrm{W}$

So, current is $\frac{4325}{220}=19.66\mathrm{A}$

Answer is $20\mathrm{A}\mathrm{m}\mathrm{p}$ .

Officially, the recent data on the median packages offered to BSc courses at Central  Agricultural University has not been released. However, as per the previous placements reports of the BSc course at CAU, the median package offered by the university is INR 7.5 LPA. Candidates must note that this represents the placements for the UG 4 years. 

$f=\frac{1}{2\pi \sqrt[]{LC}}$

$f\alpha \frac{1}{\sqrt[]{C}}$

Another capacitor should be added in series with the first capacitor.

Arena Animation, Dehradun is located in the beautiful location of Dehradun, Uttarakhand and is accessible via different modes of transportation. Students can arrive at the Dehradun Railway Station, and take a 10-minute drive to reach the institute campus. Students can also choose to travel by air and arrive at the Jolly Grant Airport, Dehradun. From there, they can take a 50-minute drive to reach the campus of Arena Animation, Dehradun.

Arena Animation, Dehradun provides a large diversity of courses and has a simple and straightforward admissions process. Students can apply for their favorite programs according to the merit criteria. For example, students seeking to apply for Arena Animation BSc programme must appear for their Higher Secondary/10+2 examination and attain valid scoring.

IGNOU BSc fees range is INR 10,500 to INR 43,500. The fees varies based on selected course specialisation. This fee component payment frequency is usually semester-wise or yearly. Candidates must note that the mentioned fee amount is as per the official website/ sanctioning body. It is still subject to revision and hence, is indicative.

The BCom syllabus for Kurukshetra University starts with 8 different subjects in its 1st and 2nd semester. After the first year, the rest of the semesters include only 6 subjects for students to clear. The first 2 semesters focus heavily on basic subjects like soft skills and communication skills which is why they have more subjects than the later semesters.

Given below are the diverse Arena Animation, Dehradun specializations for various courses:

Radius of circular path R = $\sqrt[]{\frac{2mk}{qB}}$ $\text{exception 25:}$

$q=\frac{\sqrt[]{2mk}}{RB}$

$\frac{q_1}{q_2}=\sqrt[]{\frac{m_1}{m_2}}\times \frac{R_2}{R_1}=\sqrt[]{\frac{9}{4}}\times \frac{5}{6}=\frac{5}{4}$

Since magnetic force cannot change the speed. So only electric field which is along -direction will change the speed along -direction only.

$v_x=\frac{E_{0}q}{m}t$ but $v_y=v_0$  

$2v_0=\sqrt[]{v_x^2+v_y^2}$

$4v_0^2=\frac{E_o^2{q}^2{t}^2}{m^2}+v_0^2$

$t=\frac{\sqrt[]{3}m{v}_o}{q{E}_o}$

Arena Animation, Dehradun has a vibrant placement system on its campus. Every year, multiple prominent recruiters visit the campus for the best talent in Animation and Multimedia. Although Arena Animation, Dehradun has not mentioned the average package information on its official website, the top recruiters include Uniplay Digital Solutions, Aswaforce, Fitpage, Cimpress India, Irealities Animation Studio, among others.

The Film and Television Institute of India will declare FTII JET result 2026 after the Stage 1 exam is conducted. The final merit list will be announced after FTII JET Stage 2 is successfully administered.

Arena Animation, Dehradun admissions are currently underway and admissions are based on the merit basis. Students can visit the official website and learn more about the course-specific eligibility and other details. Students must appear for their previous qualifying examination (i.e. 12th Standard/Graduation) and obtain valid scoring for gaining admission at the institute.

A fluctuating trend can be seen in the highest package from 2023 to 2025. The highest package recorded in the recent years at  Narsee Monjee College of Commerce & Economics  is present in the table below: