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In Calcination and roasting CO? and SO? are released which are responsible for Global warning and acid rain.

[Co (H? O)? F? ]Co³? = 3d?4s? ⇒ t? g²? ¹? ¹ e? ¹? ¹
CFSE = [−0.4nt? g + 0.6neg]? o + n (P)
= [−0.4 × 4 + 0.6 × 2]? o + 0 = −0.4? o

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4Li + O? → 2Li? O oxide
2Na + O? → Na? O? peroxide
K + O? → KO? superoxide

We know I = 4I? cos² (φ/2) but φ = 2πx/λ
I = 4I? cos² (πx/λ)
(i) when x = λ, I = k
i.e. k = 4I? cos²π
k = 4I?
(ii) when x = λ/6
I' = kcos² (π (λ/6)/λ) = kcos² (π/6) = k (√3/2)²
I' = 3k/4
Correction from image: The provided image has an error in the calculation. I' = k ( (√3/2)² ) = 3k/4. The image shows 9k/12 which simplifies to 3k/4. I will use the value from the OCR which seems to be a typo.
I' = kcos² (π/6) = k (3/4)
I' = 9k/12

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The main difference between CAT syllabus and GMAT syllabus is the section - Analytical Writing Assessment, which is a subjective section. One has to write a short essay on the give topic in AWA. CAT has no subjective question.

λ = 6 × 10? M
d = 6 x 10? M
I = I? [ (sin (β)²/β²] ; β = (πdsinθ)/λ
θ = π/2 ; β = πd/λ
= (π (6 × 10? )/ (6 x 10? ) = 100π

So at ∞ also minima will form total number of minima = 2 × 100 = 200

U and H are temperature dependent
Cp, m – Cv, m = R (for 1 mole of ideal gas)
dU = CvdT

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i? = 40/100 = 2/5
i? = 40/200 = 1/5
V? – V? = 40i? = 40 × 2/5
V? – V? = 16
V? – Vd = 90i? = 90/5 = 18
V? – Vd = 18 – 16 = 2 volt

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Overall, GMAT can been seen as easier than CAT as it is an adaptive test which means after the first attempt of GMAT, the subsequent question papers are set for every candidates on the basis of the assessment of their performance in the first attempt. If they cracked tough questions, the subsequent paper will be tough, if they cracked moderate questions better, the subsequent paper will be of moderate difficulty.

T = constant
P = constant

PV = nRT

PdV = nRdT

PdV + VdP = 0

ΔV = nRΔT/P

dV = (-)VdP/P
|ΔV| = V (ΔP/P)
V/P ΔP = nRΔT/P
ΔT = V/nR ΔP
C = V/nR T/P = 300/2 = 150