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New Question

5 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

dm = λdx = λ? (1 + x/L)dx
M = ∫? λ? (1 + x/L)dx = λ? [L + L²/2L] = 3λ? L/2
dI = dmx² = λ? (1 + x/L)dx × x²
I = λ? ∫? (x² + x³/L)dx = λ? [L³/3 + L? /4L]
I = (7λ? L³)/12 = (7/12) * (2M/3L) * L³ = (7/18)ML²

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

P = 1/f = (N/100)D
2x + 40 = 100
x = 30 cm
100 – x = 70 cm
1/v - 1/u = 1/f
1/70 - 1/ (-30) = 1/f


1/f = 1/70 + 1/30 = (3+7)/210 = 1/21
f = 21 cm = 0.21M
Power = 1/f = 1/0.21; D = (100)/21
N/100 D = 100/21
N = 10000/21 = 476.19
N = 476

New Question

5 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

(i) Foam - Froth (e)
(ii) Gel - Jellies (c)
(iii) Aerosol - smoke (a)
(iv) Emulsion - milk (f)

New Question

5 months ago

0 Follower 2 Views

Shiksha Ask & Answer
Tanu Rao

Contributor-Level 10

Grras IT Solutions provides Industry-certified trainers with years of experience and deep practical knowledge. The institute offers comprehensive courses such as Full Stack Web Development, DevOps, Red Hat Linux, AWS Cloud, Data Science, Python, Cyber Security, Ethical Hacking, UI/UX, and more. All training modules are enhanced with AI tools and concepts, keeping learners future-ready. Grras offers hands-on training with capstone projects to simulate real-world IT scenarios. The institute has a dedicated placement cell with resume building, mock interviews, and job referrals. Grras also offers special preparation sessions with the

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New Question

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Distance moved = Area under curve
= ½ * 8 * 5 = 20

New Question

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

de-Broglie wavelength
λ = h/mv = h / √ (3kT/m * m) = h / √ (3mkT)
λ = (6.63 × 10? ³? ) / √ (3 × 4.64 × 10? ²? × 1.38 × 10? ²³ × 400)
λ = (6.63 / 2.77) × 10? ¹¹ = 2.39 × 10? ¹¹ m ≈ 0.24Å

New Question

5 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Mean relaxation time T = λ/V? = λ / √ (8RT/πm)
∴ T ∝ 1/√T

New Question

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

B (ΔV/V) = ΔP
ΔV/V = ΔP/B = (4 x 10? )/ (8 x 10¹? ) = 1/20
V = l³
dV = 3l² dl
dV/V = 3l²dl/l³ = 3dl/l
ΔV/V = 3 (Δl/l); 1/20 = 3 (Δl/l); ΔV/V = 1/60

% (Δl/l) = 100/60 = 1.67%

New Question

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New Question

5 months ago

0 Follower 1 View

I
Ishita Kalra

Contributor-Level 10

Tohoku University is one of the most esteemed universities for pursuing higher education in Japan. The university offers a large variety of degree programs for its international and Indian students. According to Shiksha Popularity Ranking, Tohoku University has an overall ranking of #188 in world and #3 in Japan. The top programs at Tohoku University that are ranked by Shiksha Popularity Rankings are listed below:

Course name

Shiksha Popularity Ranking 2025

MS

#3

Mechanical Engineering

#4

Physics

#3

M.Arch

#5

M.A.

#6

Politics

#6

LL.M.

#8

MIM

#8

Engineering

#4

New Question

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

ΔQ = heat supplied
ΔW = work done
ΔU = change in internal energy
(i) adiabatic (B) Δθ = 0
(ii) isothermal (D) ΔU = 0
(iii) isochoric (A) ΔW = 0
(iv) isobaric (C) ΔU ≠ 0, ΔW ≠ 0, ΔQ ≠ 0

New Question

5 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New Question

5 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Eext > 1.1 V, cell reaction is reversed
i.e. Cu → Cu²? anode
Zn²? + 2e? → Zn cathode

New Question

5 months ago

0 Follower 21 Views

V
Vishal Baghel

Contributor-Level 10

Mg + MkV² = MA = -mv (dV/dx)
Vdv = (−) (g + kV²)dx
∫? (Vdv)/ (g + kv²) = ∫? - dx
[ln (g + kV²)/2k]? = -x
ln (g/ (g + ku²) = −2kx
x = (1/2k)ln (1 + ku²/g)

New Question

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Using Bernoulli's equation
P? + (1/2)ρv? ² + ρgh? = P? + (1/2)ρv? ² + ρgh?
For horizontal tube h? = h?
P + (1/2)ρv² = P/2 + (1/2)ρV²
(1/2)ρV² = P/2 + (1/2)ρv²
V = √ (P/ρ + v²)

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Escape velocity = √ (2GM/R) = v? f
Orbital speed = √ (GM/R) = V?
V? /V? = 1/√2

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

From aerie's law x = c/r
I = xH
I? = x? H?
I? = x? H?
I? /I? = x? H? /x? H?
I? /I? = T? H? /T? H? = (4 x 0.3)/ (24 x 0.4) = 1/8
I? = T? /8 = 6/8 = 0.75

New Question

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New Question

5 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Network done is equal to area under F-x curve
= 200 x 15 + ½ x 100 x 15 + 100 × 15
= 4500 + 750
= 5250

New Question

5 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

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