What is the selection process for B.Tech and what is the minimum JEE score required?
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2 Answers
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The selection process for B.Tech involves several steps, including meeting eligibility criteria, submitting application forms, and appearing for entrance exams. The most common entrance exam for B.Tech in India is the Joint Entrance Examination (JEE). This exam is conducted in two stages - JEE Main and JEE Advanced. To be eligible for the JEE Main, candidates must have passed their 10+2 or equivalent examination with Physics, Chemistry, and Mathematics as compulsory subjects. They must also have secured a minimum aggregate of 55% (45% for SC/ST candidates) in their 10+2 exams. After clearing the JEE Main, candidates can appear for the
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The admission procedure for B.Tech at Sandip University, Nashik, requires the following:
- The candidate must have completed 10+2 with Physics, Chemistry, and Mathematics with a minimum of 50% aggregate marks (45% for reserved categories).
- The candidate must have a fundamental knowledge of Computers and Programming languages.
- The candidate must have valid scores in any of JEE Main/ MHT CET/ SUJEE.
The minimum JEE score required for admission to B.Tech at Sandip University, Nashik, is not available.
However, the previous year’s cutoff scores for B.Tech at Sandip University, Nashik, were 39.92.
The cutoff scores will vary course
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