Are NCERT Solutions for Conic Sections available in PDF form?

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A
10 months ago

Yes, We have uploaded  complete NCERT Class 11 Maths Conic Sections Soluitions in normal accessible mode as well as downloadable PDF mode. Students can utilise this ultimate NCERT Solution as mathematical guide to resolve their in class doubts, practicing problems, and strengthening the concepts. St

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 APBP

M1 M2 = 1

2tt23×2/631t2=1

t = 1

So, A (1, 2) and B (1, 2) they must be end pts of focal chord.

Length of latus rectum =2b2a

4=2b2a

b2 = 2a and ae = 1

Eccentricity of ellipse (Horizontal)

b2 = a2 (1 – e2)

2a = a2 (1 – e2)

2 = 1e (1e2)

e2 + 2e – 1 = 0

e=2±4+42

e=1+2

now 1e2=3+2

Given hyperbola : kx26y26=1 so eccentricity e = 1+k and directrices x=±ae

x=±6kk+16kk+1=1

k = 2 therefore equation of hyperbola is x23y26=1

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Abscissae of PQ are roots of x2 – 4x – 6 = 0

Ordinates of PQ are roots of y2 + 2y – 7 = 0 and PQ is diameter

Equation of circle is x 2 + y 2 4 x + 2 y 1 3 = 0   ……………. (i)

But, given  x 2 + y 2 + 2 a x + 2 b y + c = 0 ……………. (ii)

By comparison a = -2, b = 1, c = -13 Þ a + b – c = -2 + 1 + 13 = 12

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Maths Conic Sections 2021

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