For the block shown, F1 is the minimum force required to move block upwards and F2 is the minimum force required to prevent it from slipping, find | F → 1 − F → 2 |

fK = μmg cosq = 0.1 * 5 0 * 3 2 = 2 . 5 3 N F1 = mg sinq + fK = 25 + 2.5 3 F2 = mg sinq – fK = 25 – 2.5 F1 – F2 = 5 3 N

For the block shown, F₁ is the minimum force required to move block upwards and F₂ is the minimum force required to prevent it from slipping, find $| {\vec{F}}_{1} - {\vec{F}}_{2} |$

Option 1 - 50 <math> <mrow> <mroot> <mrow> <mn>3</mn> </mrow> <mrow></mrow> </mroot> </mrow> </math>  N

Option 2 - 5 <math> <mrow> <mroot> <mrow> <mn>3</mn> </mrow> <mrow></mrow> </mroot> </mrow> </math>  N

Option 3 - 25 <math> <mrow> <mroot> <mrow> <mn>3</mn> </mrow> <mrow></mrow> </mroot> </mrow> </math>  N

Option 4 -   <math> <mrow> <mfrac> <mrow> <mn>5</mn> <mroot> <mrow> <mn>3</mn> </mrow> <mrow></mrow> </mroot> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> N

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Answered by

Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 2

Detailed Solution:

f_K = μmg cosq

= 0.1 * $\frac{50 * \sqrt[]{3}}{2}$